Torque, Angular Acceleration, and the Role of the Church in the French Revolution | Doc Physics
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- Опубликовано: 12 сен 2024
- Why do things change their angular velocity? Soon, you'll know.
Oh, and engineers call torques "moments." God love 'em.
Your nice little interjections like "Oooh... I like that!" and "Oh look, they're all right there!" are awesome.
The second system with the masses will have a lesser moment of inertia than first one. This is because all other things being the same in the two systems, the mass in the second system on the right , is distributed closer to the axis of rotation than the system on the left ..
since the second system has lesser moment of inertia than the system on the left
it will offer lesser resistance to rotational motion ( in other words rotate more easily when it experiences a net torque )..
so the system on right will be the one in which the mass will hit ground first ..
what the hell is R awwww?
Cute Radius?
Haha I was thinking the same thing!
Torque= Inertia of whole system * angular acceleration
torque applied by 10 kb block is same.
but inertia is different as inertia depends on the distance between axis and mass.
thus,
angular acceleration= torque(same for both)/ inertia of rotation(different)
inertia of rotation is more for the first one.
so it's acceleration will be less than the second one.
Took me a long time to find a vid as clear as this. Thanks.
and the role of the church in the french revolution. this is a good one.
This video is AWESOME! Throughout my college career I've used RUclips a lot!!!! this is the first time its helped for my physics class (most physics videos on here are either way too easy or way too in depth) this one was perfect!
The one on the right. Because the pulley to the right has less angular intertia, so more angular acceleration.
Those big smiles on my face after an epiphany hits...that loosening/tightening bolt fact was a really awesome addition!!! :D
A little basic video in general for what I was looking for (in physics C), but nonetheless appreciated.
+Jackie Rosenthal Thanks! I've never taught AP-C. Can you suggest some other stuff I could talk about in another video, to bring more calc in?
+Doc Schuster After our test tomorrow on rotation stuff we are doing electrostatics, electric field, etc. and on February 10th we start Gauss' Law, which I hear is hard!
If you make some videos about those topics with some calculus used, I'll share them with my teacher and all 30 something of my classmates
You bet it does. And it's the same argument as we discussed in class yesterday!
years later and this is still extremely helpful! Thank you!
your videos are amazing!!!! BTW thanks
i watch it in 2015 but its still feel like helpful ,,,,,,thanks yeahh...
Super helpful!!! My prof went over this in class but it wasn't nearly as clear as this video!
Thanks, this helped me on my world history test
The mass on the second pulley ( on the right ) will hit the ground first
Hi sir ! nice videos, but why do you keep on calling 'r' as 'aaRaa' ? :s
is this u? or is this some kinda physics thing? ;)
cheers
It's just me. Don't tell anyone.
Hey Doc,
I am in university, this is the second time I take the physics 1 calculus based course. I just found your videos. You really know how to explain the basic and fundamental information. Thank you very much
I'm glad they help. Good luck!
using r=1r on the left and r=0.5r for the right
α(Left Hand Side)=Fr/mr^2
α(Right Hand Side)= F(0.5r)/m(0.5r)^2 = 4Fr/2mr^2 = 2Fr/mr^2
=> angular acceleration on the right is twice that of the left, therefore the right will fall to the ground faster. Is this correct?
Horsepower: 300 @ 5800 RPM Torque: 300 @ 1200 RPM vs Horsepower: 330 @ 7000 RPM Torque: 270 @ 5200 RPM typically which car would win in a race?
Do you mean that you're disgusted at how similar angular acceleration is to linear acceleration. If so, you win!
In the system on the right the wheel has lesser breaking torque so to say, from the rod compared to that of the system on the left and hence the 10m on the right system hits the ground first.
Might be clearer to use T rather than tau for Torque since if you ever get any further into mechanics when looking at shear stresses caused by torques you get equations where T and tau are used in the same equation. Tau is widely used for shear stress which would be caused by a torque T.
Richard Nash I've already got tension and period as T, so that'd be a mess. We just need a bigger alphabet, yo.
+Doc Schuster wait til people start using emojis...
This stuff is amazingly helpful!
Well this helpful but where is role of church in French revolution part
Thank you so much :D
"Oh look, it's already labeled"
Unfortunately in 14:14 the relation of torque and angular acceleration is wrong neither for rigid bodies nor for particles this equation is wrong in vector form. Just in scaler form and in some special condition (rotaion about fixed axis) it is right.
Really helpful! Thanks!
nice vid mate. if there is no pulley friction, the rods do not bend and the small m masses from the rods are punctiform, both 10m weights hit the ground at the same time, because the small m masses are on the axis of rotation => r = 0 => I = 0
abuwarez One of the systems resists acceleration more. That's related to why a figure skater can reduce her spinning by allowing her arms to swing out rather than holding them in.
Doc Schuster sorry, my mistake. i interpreted the drawing in 3D, having the rod perpendicular on the pulley's plane (and not in the same plane as), going through their rotation point.that's why i said r = 0 for bot pulleys. thinking that the problem might have a catch, i complicated it;
abuwarez Aha. I wasn't very clear about my axes of rotation. It's not a hard problem at all if you've been following the video, I hope! Good work.
The one thats gonna fall down 1st is the one that has both masses on the edge othe the line
hello sir, your videos are very helpful...thank you.
i think the one on the right because alpha=f/mr so a bigger radius equates to a slower angular a
You are the man!
THANK YOU!
Does the left one hit the ground first?
Correct me if I am wrong Doc..
The second hits first!
um...a vector torque can't equal a scalar |F| |r| sin(θ) which is actually the magnitude of torque |r x F|
Why does the one on the right hit the ground first? Is it because the masses are at a closer r, so they have less moment of inertia?
the pully in left will hit the ground 1st bec it has big moment of inertia
How momentum and energy loss relationship????
the axis of rotation is coming out of the page?
Second option is correct na?
Is it the right one because F / (mr) = AA (angular acceleration) so smaller the r, the bigger AA. Is that the reason?
I prefer the language of torques and rotational inertia. Can you tell me in that language?
Doc Schuster isn't it the left one? because torque = radius times force perp. The force is further away on the first one therefore higher torque.
hey there, I wanna ask that is torque always calculated with respect to axis of rotation
Always.
Thanks man!
i love u doc
Amazing and i am only 2 minutes in :D
good
this guy is so sassy XD
Damn, you need to throw that tetanus wielding wrench away man! But good content! You remind me of Lyle from the movie "The Internship" Haha!
plzz tell me f m wrong
Shuaib Mohammad the one on the right would actually hit first. Angular acceleration is torque/moment of inertia. You are correct in saying that the moment of inertia on the left is bigger, but this means it will have a smaller angular acceleration so it will actually fall after the one on the right which will accelerate faster.
If you already know what "accelerate in a linear fashion" is, as is necessitated by this video in the first 30 seconds, you might as well NOT pay attention to the rest of the video.
twerk sum!!
:D