This guy and his weird pronounciation and funny examples...it's as if he knows that everyone who's watching this video is super frustrated trying to learn angular momentum. I certainly cheered up when I saw the severed hand example lol
My dear sir after watching many vedios about angular moment ,among of these your vedio lecture is the best and most concept clearing. I am from Pakistan
Thank you Doc Physics ! I finally have understood what the angular momentum is, and means, among a ton of videos. Note : I'm french, and your english is very clear.
Awesome video!! love you're the Quirkiness lol i have a question for you tho... how would this apply if.... you have 2 people biking on the exact same model of Bicycle(same dimensions of wheel) at the same speed 10m/s. however person (A) is on the 6 gear and person (B) is on the 3 gear. so person (B) is peddling 2x faster/harder. what cyclist benefits from a bigger stability on his bicycle and why? hope you can help
Great video! It's really helping me prepare for my physics exam! Also, at 7:40, why is the torque positive instead of negative when the hammer goes counter-clockwise?
The leading factor on moment of inertia formulas depends on the specific shape and the distribution of mass. The 1/2 factor is what applies to a uniform solid cylinder about its circular symmetry axis. For a thin uniform hoop, the moment of inertia equals m*r^2. For a point mass, the moment of inertia is m*r^2.
There is no kinetic energy in a moving mass there is force Mv squared kinetic energy is the energy of consistent work from a consistent force regards Graham Flowers
When you derived L = Iw into L = mvr, does that work 100% of the time? Because I isn't always equal to mr^2. You'd have to use the parallel axis theorem to figure it out.
I=m*r^2 is a special case of the formula for moment of inertia, when you have a point mass. It also applies for a thin uniform hoop, about its axis of circular symmetry, because all mass is at the same radial position from the axis of rotation. If you have another shape, you have the distribution of mass to account for, as not every particle in a rigid body moves with the same linear speed, or at the same radial coordinate from the reference axis. In a rigid body, v=omega*r holds true, where omega is a uniform value for the whole body, and v and r vary, when r is relative to a point called the instantaneous center of zero velocity. Given the velocities of two points on a rigid body, all the rest of the velocities are dependent on these two velocities. A system of individual particles is a summation of m*r^2 for all the particle masses and radii relative to a reference axis. A continuous rigid body will have its moment of inertia calculated as integral r^2 dm. All the moment of inertia formulae you see in your textbook, are calculated from this integral.
@@ennfuture3340 Yes, since not otherwise specified, your weight would be constant. But what other quantities remain constant in the situation of a person crawling around on a big turntable? Think of quantities in Physics that are conserved.
because omega=velocity/r, and the unit for that is m/s divided by m, which equals 1/s , so if you calculate angular momentum as L= moment of inertia (I) times angular velocity (omega), you will get (kg x m squared) x (1/s), which in the end equals (kg x m squared)/s
ralph houthoofdt Arbitrary cultural celebrations should always take a back seat to the study of the fundamental laws of the universe. Unless there's a lady involved. Did you find someone to kiss at midnight yet? Once you've got someone lined up, you can get back to work!
***** This sounds crazy, right? But since L is defined about some axis, it would be a very useful definition if the bullet were about to collide with a block of wood on a fixed axis. If the bullet's velocity vector did not point at the axis directly, the block would spin. You would be able to find its rotation by conservation of L! For the win!
Doc Schuster If the sun disappeared the earth would continue to travel along its tangent. But since the angle is getting smaller, the velocity component goes down whilst the radius increases. These cancel each other out and therefore Angular Momentum is conserved?
It isn't linear momentum. It is angular momentum, which is radius vector from a reference axis cross product the linear momentum. There already are meters in the units of linear momentum, and cross producting with a radius puts another meter unit in the numerator.
@@lachimolalalala7775 The leading factor on moment of inertia formulas depends on the specific shape and the distribution of mass. The 1/2 factor is what applies to a uniform solid cylinder about its circular symmetry axis.
The "x" refers to a cross product. It is a method of multiplying two vectors, in a manner that is greatest when they are crossed (i.e. perpendicular), and generates a third vector that is perpendicular to both of them. Look up the term "cross product" for further detail. L is the angular momentum, the quantity we are defining here. r is the radius vector from a reference axis to the particle in question p is the linear momentum (mass*velocity) of the particle in question
@@DocSchuster Over time. Integrate torque relative to angle is rotational work. It also turns out that angular momentum is not just the indefinite integral of torque d_time, it is also the definite integral of torque d_time, when starting at rest.
You lost me with the value/unit of [L] as being Kg*m2/s. Are you saying [L]= Inertia divided by time? Because that is not right. Shouldn't [L] be Inertia (kg*m2/s) * angular velocity(m/s.)? Unless [L] is different than L vector ( momentum) and it is different than L ( plane L). I don't have victor sign on my keyboard. I don't think I do.
L is angular momentum. It is equivalent to moment of inertia (units of kg-m^2) * angular velocity (radians/second). Radians are considered dimensionless units, that don't end up needing to be written when combining with other units. It is only correct when your angular kinematics terms are in units based on the radian.
Gravity does not exist, angular momentum is what causes all “gravity effects” we assume that air -space has no mass, the earth is special, our atmosphere in combination with angular momentum around the sun has created a vacuum, making mass heavier. Think how airplanes fly the wings have up draft because it’s pushing thru air. Think of air like a lighter form of water. In space there to is air just no vacuum effects , a brick falls same rate as a feather. The rotations of planets are angular momentum.
First of all what are you saying??? Your syntax is completely incomprehensible, try conveying your point across better. Anyways gravity isn't caused by angular momentum. General relativity explains that matter (or more correctly the energy-momentum tensor) causes spacetime to have curvature. If no external forces act on a test particle then it will follow the straightest possible path through spacetime, called a geodesic. This may be a curved path through three dimensional space but it is a geodesic nonetheless. The gravitational force is a consequence of this. Gravity is completely a geometric property of spacetime. If anything in cases like the roattaion of the planets gravity is what causes the planets to have angular momentum, not the other way around.
@@its_not_lux space time ? General relativity? We are talking about things guessed upon in a time when math seemed to answer such questions. Point being is that planets are all on sort of spinning rotational path. Thru a medium that is endless . What is up or down in an environment which seems to have no boundaries? Angular momentum is gravity. Although angular momentum like gravity cannot be understood. We do not yet have the means. Black holes are still a hypothesis. If the earth wasn’t spinning we’d fall off, so why can’t we suppose that in spinning experiments where there is stability can we not think we are nothing different. Bottom line gravity cannot be called a force if no one knows what gravity is?
This guy and his weird pronounciation and funny examples...it's as if he knows that everyone who's watching this video is super frustrated trying to learn angular momentum. I certainly cheered up when I saw the severed hand example lol
I've learned more from a couple of your videos than I have from a whole semester of AP Physics at my high school. :) Thanks a bunch
+Sarah Klein Happy to help! Tell your friends. Thank you!
And whose fault was it? The teacher's? Or weren't you paying attention?
square = squirr
there = thurr
r = errah
+Anjelica Gacayan =D
Man that got complicated real fast.... completely lost
What is errah and squir?
Just like aarh perp, they are something valuable :D
Swinging it around with a "live hand." Haha! I love it!
i love how meters square becomes meters squer :P
wow finally learnt angular momentum .... thanks now I think that I will be able to tackle any questions on this topic in my exam ...THANKS Doc. :-)
This video saved my life, I feel so much more confident for my IB Physics test tomorrow now! Thank you soooo much!
My dear sir after watching many vedios about angular moment ,among of these your vedio lecture is the best and most concept clearing. I am from Pakistan
Thank you Doc Physics ! I finally have understood what the angular momentum is, and means, among a ton of videos.
Note : I'm french, and your english is very clear.
very important & very nice
Very good Demo by you 💐💐💐💐💐💐💐💐💐💐💐💐💐💐👍👍👍👍👍👍👍👍
Historical event ..
At 2:50 doc pronounced r correctly.
.
.
Again after some time he pronounced r correctly.
WOW!
Instructions unclear, got my hand severed and swung in a circle.
hahahaha "squrrr"! I love his energy, he's a great lecturer, really entertaining
a severed hand?!?! loolool whhatttt
I don't quite understand it yet, but from what I gather, it should be with respect to time. I need to research rotational physics...
Awesome video!! love you're the Quirkiness lol
i have a question for you tho... how would this apply if....
you have 2 people biking on the exact same model of Bicycle(same dimensions of wheel) at the same speed 10m/s. however person (A) is on the 6 gear and person (B) is on the 3 gear. so person (B) is peddling 2x faster/harder.
what cyclist benefits from a bigger stability on his bicycle and why?
hope you can help
great video, thanks!
You're barking mad but it makes so much sense!
Thanks, Max! It's surely a sign that you're crazy, too, if this insanity benefits you.
So why do moons/stars spin backwards creating an angular problem?
5:23... Finest looking piece of paper I've ever seen ;)
Tq sir, U make it clear for me, wish all the best for you 😉😉😉
What is tangential ratios of angular momentum and rotate movement❓❓❓
7:46 Hmmmhmmm That's a thick a$$ bullet.
Dr. D Statics
dang it...you seem like a great teacher...however I was looking for Mechanics 2 Dynamics Angular momentum and impulse
if i is the moment inertia and e is kinetic energy , what is angular momentum
this guy and his sound effects, and what is squrrr?
ara squrrr
Great video
Is r a distance or is it displacement (you denoted it with a vector arrow).
sir why we take tengential velocity in equations???
M times V! I have that song and LOVE it. My physics teacher doesn't think that playing songs helps teach concepts, though. It's super disappointing.
A Thousand +1's! I seriously know of no one else in the world who knows that song!
You sir, are amazing.
Kilogram-metre-squrr
Great video! It's really helping me prepare for my physics exam!
Also, at 7:40, why is the torque positive instead of negative when the hammer goes counter-clockwise?
Thanks! That's the definition for torque. CCW is positive.
@@DocSchuster hey dude I'm from future how's your life going ?
is moment of inertia,I =1/2mr^2?
Nope only mr^2
The leading factor on moment of inertia formulas depends on the specific shape and the distribution of mass. The 1/2 factor is what applies to a uniform solid cylinder about its circular symmetry axis. For a thin uniform hoop, the moment of inertia equals m*r^2. For a point mass, the moment of inertia is m*r^2.
There is no kinetic energy in a moving mass there is force Mv squared kinetic energy is the energy of consistent work from a consistent force regards Graham Flowers
What is the name of his last prank movie again?
When you derived L = Iw into L = mvr, does that work 100% of the time? Because I isn't always equal to mr^2. You'd have to use the parallel axis theorem to figure it out.
I=m*r^2 is a special case of the formula for moment of inertia, when you have a point mass. It also applies for a thin uniform hoop, about its axis of circular symmetry, because all mass is at the same radial position from the axis of rotation.
If you have another shape, you have the distribution of mass to account for, as not every particle in a rigid body moves with the same linear speed, or at the same radial coordinate from the reference axis. In a rigid body, v=omega*r holds true, where omega is a uniform value for the whole body, and v and r vary, when r is relative to a point called the instantaneous center of zero velocity. Given the velocities of two points on a rigid body, all the rest of the velocities are dependent on these two velocities.
A system of individual particles is a summation of m*r^2 for all the particle masses and radii relative to a reference axis. A continuous rigid body will have its moment of inertia calculated as integral r^2 dm. All the moment of inertia formulae you see in your textbook, are calculated from this integral.
movementum loss of anything ???
in terms of energy
SQURR
if you are riding on a big turning table and you crawl at the edge, would your turn decrease or increase ?
Jed Dimaculangan Love it. What do you think is constant in such a situation?
+Doc Schuster my weight
@@ennfuture3340 Yes, since not otherwise specified, your weight would be constant. But what other quantities remain constant in the situation of a person crawling around on a big turntable? Think of quantities in Physics that are conserved.
why the unit of angular momentum doesnt contain (rad) which should be in the omega (rad /sec)?
because omega=velocity/r, and the unit for that is m/s divided by m, which equals 1/s , so if you calculate angular momentum as L= moment of inertia (I) times angular velocity (omega), you will get (kg x m squared) x (1/s), which in the end equals (kg x m squared)/s
Nice
isn't the direction of angular momentum perpendicular to both r and v? as you said it paralells to velocity. sorry if i miss any concept
+Empty Blank That sounds like a mistake. There is certainly a cross-product in there, as you indicate!
+Doc Schuster thanks a lot love ya video :D
what does he mean by the term “normal distance” when describing r (perpen)?
"Normal" in this context means perpendicular.
super super thanks
I'm doing physics while I should be getting ready for new year's eve, on purpose.
ralph houthoofdt Arbitrary cultural celebrations should always take a back seat to the study of the fundamental laws of the universe. Unless there's a lady involved. Did you find someone to kiss at midnight yet? Once you've got someone lined up, you can get back to work!
Güzel video
What's different ratios between angular and linear momentum 🛐🛐🛐🕉🕉🕉
What and why is there distracting noise in the background?
jimtrueblue99 GRRRR!!! I hate that, too!
How does the bullet have angular momentum if its going in a straight line path and not spinning
***** This sounds crazy, right? But since L is defined about some axis, it would be a very useful definition if the bullet were about to collide with a block of wood on a fixed axis. If the bullet's velocity vector did not point at the axis directly, the block would spin. You would be able to find its rotation by conservation of L! For the win!
Doc Schuster If the sun disappeared the earth would continue to travel along its tangent. But since the angle is getting smaller, the velocity component goes down whilst the radius increases. These cancel each other out and therefore Angular Momentum is conserved?
The apple is going like.. 11:34
Why are we *squaring* the meters in linear momentum?
It isn't linear momentum. It is angular momentum, which is radius vector from a reference axis cross product the linear momentum. There already are meters in the units of linear momentum, and cross producting with a radius puts another meter unit in the numerator.
he has movies!!! its super funny...
I thought moment of inertia (I) = 1/2mR^2
But why didn't you plug 1/2 in that formula?
Why did you think that? Got a textbook?
My bad. I was confused because I just started to learn physics. But I got it now.
@@lachimolalalala7775 The leading factor on moment of inertia formulas depends on the specific shape and the distribution of mass. The 1/2 factor is what applies to a uniform solid cylinder about its circular symmetry axis.
sir another question.... sir what is mean by L=r×p
The "x" refers to a cross product. It is a method of multiplying two vectors, in a manner that is greatest when they are crossed (i.e. perpendicular), and generates a third vector that is perpendicular to both of them. Look up the term "cross product" for further detail.
L is the angular momentum, the quantity we are defining here.
r is the radius vector from a reference axis to the particle in question
p is the linear momentum (mass*velocity) of the particle in question
why's v = wr?
omega is 2pi/period, so I'm just saying the speed is circumference over period. Thanks for watching!
you need to get yourself some of that brown roll out paper that they all use.
Leon Schuster is very cool
angular momentum is the indefinite integral of torque.
+Connor Keenum ...over time or angle?
@@DocSchuster Over time. Integrate torque relative to angle is rotational work.
It also turns out that angular momentum is not just the indefinite integral of torque d_time, it is also the definite integral of torque d_time, when starting at rest.
When u got a brain, capable of vast imaginations, but you decide to make ur particle a severed hand
😂👌
You lost me with the value/unit of [L] as being Kg*m2/s. Are you saying [L]= Inertia divided by time? Because that is not right. Shouldn't [L] be Inertia (kg*m2/s) * angular velocity(m/s.)?
Unless [L] is different than L vector ( momentum) and it is different than L ( plane L). I don't have victor sign on my keyboard. I don't think I do.
L is angular momentum. It is equivalent to moment of inertia (units of kg-m^2) * angular velocity (radians/second).
Radians are considered dimensionless units, that don't end up needing to be written when combining with other units. It is only correct when your angular kinematics terms are in units based on the radian.
Is he cool? Sure sounds cool...
Gravity does not exist, angular momentum is what causes all “gravity effects” we assume that air -space has no mass, the earth is special, our atmosphere in combination with angular momentum around the sun has created a vacuum, making mass heavier. Think how airplanes fly the wings have up draft because it’s pushing thru air. Think of air like a lighter form of water. In space there to is air just no vacuum effects , a brick falls same rate as a feather. The rotations of planets are angular momentum.
First of all what are you saying??? Your syntax is completely incomprehensible, try conveying your point across better. Anyways gravity isn't caused by angular momentum. General relativity explains that matter (or more correctly the energy-momentum tensor) causes spacetime to have curvature. If no external forces act on a test particle then it will follow the straightest possible path through spacetime, called a geodesic. This may be a curved path through three dimensional space but it is a geodesic nonetheless. The gravitational force is a consequence of this. Gravity is completely a geometric property of spacetime. If anything in cases like the roattaion of the planets gravity is what causes the planets to have angular momentum, not the other way around.
@@its_not_lux space time ? General relativity? We are talking about things guessed upon in a time when math seemed to answer such questions. Point being is that planets are all on sort of spinning rotational path. Thru a medium that is endless .
What is up or down in an environment which seems to have no boundaries? Angular momentum is gravity. Although angular momentum like gravity cannot be understood. We do not yet have the means. Black holes are still a hypothesis.
If the earth wasn’t spinning we’d fall off, so why can’t we suppose that in spinning experiments where there is stability can we not think we are nothing different. Bottom line gravity cannot be called a force if no one knows what gravity is?
SQUIRREL!!
all thanks to Allah, who made as Muslims, and gave as the ability for thinking about the world and how it goes.
Thanks to Al Khwarismi, the father of the Algebra we use today.
Why does no one ever explain why we SQUARE the meters? It's so annoying.
Because we have both r in meters, and v in meters per second, in the formula for angular momentum. Both have meters in the numerator.
What's up with yo left thumb?
You sound like you're from St. Louis.
skwer
no u cnt teech u dun even wryt with left hand lolz
Just kidding, nice presentation & points for style. Are you an actual doctor?
Ming's Yep. PhD in solid state physics, Washington University in St. Louis, 2007. Good times. Thanks for watching.
You must be joking!
squr
yea.. sqiurrr
I thought I learned angular momentum, but now, not anymurrrrrrr.......
squrr,arreh. ; )
arra
tarnslint into hindi plase
hhahaahahahaha im crying... squir?????
Squirrel
I've no idea what you're on about
mmmmm... squrrr
Really, a severed hand? Are high school students so brain dead now you have to do that to keep their attention? SMH
Squrr
Is this English
Yes. Just with a very thick accent that exaggerates features of English that stand out when heard by people accustomed to other languages.
What does he mean by the term "normal distance" when describing r (perpend)?
"Normal" in this context means perpendicular.