A very interesting log trig integral

Поделиться
HTML-код
  • Опубликовано: 6 сен 2024
  • Full solution development for this cool integral featuring Feynman's trick of differentiating under the integral sign leading to a nice result.
    My complex analysis lectures:
    • Complex Analysis Lectures
    If you like the videos and would like to support the channel:
    / maths505
    You can follow me on Instagram for write ups that come in handy for my videos and DM me in case you need math help:
    ...
    My LinkedIn:
    / kamaal-mirza-86b380252
    Advanced MathWear:
    my-store-ef6c0...

Комментарии • 41

  • @nikoorourke2602
    @nikoorourke2602 2 месяца назад +8

    watched this at 1.30 am and I have never been more sure that I want to keep studying maths. so cool

  • @slavinojunepri7648
    @slavinojunepri7648 2 месяца назад +3

    Fantastic solution. Expressing cos and sin in terms of tang is key to solving this fine integral

  • @CM63_France
    @CM63_France 2 месяца назад +3

    Hi,
    "ok, cool" : 2:35 , 3:30 , 4:38 , 5:28 ,
    "terribly sorry about that" : 8:02 , 9:58 , 15:44 .

  • @bnice24
    @bnice24 2 месяца назад +5

    Super cool solution, very two-rootful

  • @noobymaster6980
    @noobymaster6980 2 месяца назад +14

    So early the thumbnail hasnt even loaded yet

    • @Akhulud
      @Akhulud 2 месяца назад

      same

  • @leroyzack265
    @leroyzack265 2 месяца назад +2

    it was wild and beautiful. it was equally root 2 rooted. This is an amazing video to conclude this wonderful day.

  • @williamberglund-lk8jh
    @williamberglund-lk8jh 2 месяца назад

    Another approach is to multiple the ln(cos) by two (later divide everything by 2) which gives ln(cos^2), then define the integral with the Feynman approach in the natural log: ln( 1+ a(cos^2 -1))= ln(1-a sin^2). Then take the derivative with respect to (alpha=a) and then solve -with all the sin^2 terms in the integral - allowing factoring.

  • @Arkanda003
    @Arkanda003 2 месяца назад +1

    The root of all math videos

  • @jackkalver4644
    @jackkalver4644 2 месяца назад

    I use a TI n-spire CX CAS to solve these tough integrals. Usually, I have to manipulate them using Feynman’s technique, but differentiating with respect to the parameter is automatically done in the integral. Then integrate the result with respect to the parameter as soon as there is no integral sign and add c. Solve for c, using a specific value of the parameter (usually 0), and finally, evaluate the I(a) using the non-integral representation and the desired a-value.

  • @Haxislive766
    @Haxislive766 2 месяца назад

    That was tooooo beautiful solution btw nice integral

  • @MrWael1970
    @MrWael1970 2 месяца назад

    Thank you for fruitful effort.

  • @halevytomer
    @halevytomer 2 месяца назад

    the fraction at the end can be derarionalized into
    2 ln ( sqrt(2) + sqrt(alpha) )

  • @johnanderson290
    @johnanderson290 2 месяца назад

    Awesome Kamaal! Too (2) rootful indeed! 😄

  • @nicolascamargo8339
    @nicolascamargo8339 2 месяца назад

    Excelente el video

  • @Gaurav-mq8yp
    @Gaurav-mq8yp 2 месяца назад +1

    Great video. I like such integrals which yield real answer instead of digamma,eta function and other special function based answers. I mean if you have to use wolfram alpha for finding values of digamma function, why not ask the integral itself to it. Anyways it is my take. Others might think differently.

  • @asianglower
    @asianglower 2 месяца назад +1

    Very rootiful!

  • @helloworld4309
    @helloworld4309 2 месяца назад +1

    Sir , I am at my initial stage of learning calculus I had completed my elementary and basics of calculus and now I am entering into college I want to learn more about calculus specially integrals plz tell me from where to start learning it 🙏🏽

    • @rishabhshah8754
      @rishabhshah8754 2 месяца назад

      i have heard inside interesting integrals is a good book. Not sure about what level it is though

    • @wondwosen3735
      @wondwosen3735 2 месяца назад

      I recommend " a treatise on the integral calculus" Joseph Edwards, start from Vol I

    • @maths_505
      @maths_505  2 месяца назад +1

      Just keep solving integrals....you can find them all over RUclips and maths stackexchange.....the books mentioned are also good choices....along with the one I plan to write eventually 😂

  • @user-yg5zb9gk6f
    @user-yg5zb9gk6f 2 месяца назад +1

    Wow! What an almost coincidence. In the last video I commented an exact similar integral just with x² instead of sin²(x). Did you get the inspiration or it's just a pure coincidence?!

    • @maths_505
      @maths_505  2 месяца назад +1

      Yes there was inspiration from that. Thanks mate.

    • @user-yg5zb9gk6f
      @user-yg5zb9gk6f 2 месяца назад

      You're welcome

    • @SussySusan-lf6fk
      @SussySusan-lf6fk 2 месяца назад

      Did you see my solution on that comment?

    • @user-yg5zb9gk6f
      @user-yg5zb9gk6f 2 месяца назад

      @@SussySusan-lf6fk yes i just need some time because i dont know Fourier transform yet

  • @fdileo
    @fdileo 2 месяца назад +1

    Ok, cool!!

  • @anasharere
    @anasharere 2 месяца назад

    why not beta function

  • @giuseppemalaguti435
    @giuseppemalaguti435 2 месяца назад

    Un idea può essere cosx=√(1+cos2x)/2..sinx=√(1-cos2x)/2

  • @jejnsndn
    @jejnsndn 2 месяца назад +1

    I've a qustion, when we integrate like ( cos(lnx) )we can subtitue cos(lnx) by the real part of x^i then integrate, what's the proof of that?

    • @SnowboardAddict37
      @SnowboardAddict37 2 месяца назад

      Comes from Euler‘s formula. e^ix = cosx + isinx. Just let x = lnx

    • @jejnsndn
      @jejnsndn 2 месяца назад

      ​@@SnowboardAddict37
      I know, but what is the proof of thag we can get out the ( Re)

    • @EphemeralEphah
      @EphemeralEphah 2 месяца назад

      @@jejnsndn It's the real part since e^ix = cosx + isinx that means that Re(e^ix) = Re(cosx +isinx) = cosx. Since the imaginary component is sinx

  • @helloworld4309
    @helloworld4309 2 месяца назад +1

    How can you introduce a perimeter alpha ?

    • @worldnotworld
      @worldnotworld 2 месяца назад +7

      By force of will! You thereby define a function I(alpha), which is, by definition, whatever the value of the integral is for any given alpha. You then differentiate with respect to alpha, and you can then figure out I(alpha), as the video shows. Then plug in alpha = 1 and you can get the value of the original integral.

    • @maths_505
      @maths_505  2 месяца назад +4

      @@worldnotworld by the force of will is seriously the best explanation I've ever heard 😂😂

    • @Jalina69
      @Jalina69 2 месяца назад +3

      Perimeter 😭😭

    • @theblainefarm3310
      @theblainefarm3310 2 месяца назад

      There is a channel called "The Feynman technique" that has hundreds of videos demonstrating this technique.

  • @Vendine2222
    @Vendine2222 2 месяца назад

    what app do you use to do math?

  • @GeraldPreston1
    @GeraldPreston1 2 месяца назад

    The reason why, the reason why.
    The reason why I had to die.
    Did I bleed the blood of greed,
    What was my destiny?

  • @alan912-qi1ew
    @alan912-qi1ew 2 месяца назад

    Dumb way to solve why we just put alpha tf