Yes my friend that intro was just for comedic relief 😂 lovely hearing from you once again. We haven't spoken on Instagram in quite a while, is everything okay?
Kamaal كمال in Arabic means perfection (it may also mean completion and by extension, be interpreted as maximum in some languages that have borrowed from Arabic). I have no idea what nationality you belong to, but, in any case, the name Perfection suits you well! The evidence is in your videos! And, never let it cross your mind that you lack friends. You have a huge community of math lovers who appreciate you and wish you well.
Here's a kinda cool Integral of a double sum, maybe you like it :3 (Also F for friends) Integral from 0 to 1 of (Sum from n=1 to inf of x^n * (Sum from k=1 to k=2n-1 of (-1)^(n+k) / binomial(2n,k))) dx Answer should be 1-(pi^2 / 12)
I just have a question about the derivative regarding s of the integral; you seem to do it freely but shouldn't we first check for continuity definition and domination of the integrated function ?
Today's integral is sponsored by an existencial crisis
the integrals are your friends
Yes, you have friends!
Yes my friend that intro was just for comedic relief 😂 lovely hearing from you once again. We haven't spoken on Instagram in quite a while, is everything okay?
Being early on a maths 505 video, there’s nothing greater
Thanks for your featured effort.
Wonderful integral
Dont worry bro, every single positive integer is your personal friend
why u need friends when u got bros (us daily viewers)😊
SUIIIIIIIIIIIIIIIIII
I had to put aside the time that I’d spend with my (not |R) friends to watch this video
You are my friend ❤
In my language, Kamaal means Maximum, so you are the roof function of all Maths RUclipsrs 😅
It has a similar meaning in Arabic 😂 thanks bro
Kamaal كمال in Arabic means perfection (it may also mean completion and by extension, be interpreted as maximum in some languages that have borrowed from Arabic). I have no idea what nationality you belong to, but, in any case, the name Perfection suits you well! The evidence is in your videos! And, never let it cross your mind that you lack friends. You have a huge community of math lovers who appreciate you and wish you well.
Can you evaluate this sum:
Sum of cos(bln(x))/x^a with x going from 1 to infinity .
a and b are like parametres
You differentiate with respect and integrate with zeal.
Here's a kinda cool Integral of a double sum, maybe you like it :3 (Also F for friends)
Integral from 0 to 1 of (Sum from n=1 to inf of x^n * (Sum from k=1 to k=2n-1 of (-1)^(n+k) / binomial(2n,k))) dx
Answer should be 1-(pi^2 / 12)
Thanks
11:37 i suspect a phi will show up
i was right
How do you figure out how to solve stuff
Well....it helps when I invent the problem in the first place 😂😂😂
Before using the digamma you could just factorise the numerator and have a simple polynomial integral
awesome, also F
I just have a question about the derivative regarding s of the integral;
you seem to do it freely but shouldn't we first check for continuity definition and domination of the integrated function ?
Heres a fun series problem
Summation cos(2nx)/(4n²-1) from n= 1 to n--> infinity
Ans is (1/2)-(π/4)sinx
@aniruddhkabra9430 😆
The actual fact is that you have friends but none of them are math nerds like you
Noice,now give us nice integral with the trigamma function.😊💯
respect brother F
I'(s)=I(0-->1)=(x^s-1)(1-x)/(1-x^k)...semplifico I'(s)=I(0->1) (x^s-1)/(1+x+x^2+...x^(k-1)..
F
I solve this hhh😂
Surely you're joking?!
F
F