@@MichelvanBiezen I think you all can consider this. A lot of "professional engineers" in my field only know how to use it and don't know where it is derived from.
Hi, sorry I got confused a little, In previous lecture, friction factor was calculated for laminar flow (64/Re) or turbulent flow (Moody chart). how come here we have a straight forward formula for it?!
Just like with all concpets in physics, we start with a simplified model. (Like ignoring wind resistance with projectile motion). This way we learn the basic principles which give us good approximate values espceically with low flow rates and substances with low viscosity.
It confused me as well. Basically, if we look at the bernoulli's, its written in pressure form directly -> in BAR (or Pa), so we can write directly dp = rho g f(h). I dont understand why its done in the video the way around, it is expressing friction factor using f(h) = dp / rho g, and then from friction factor again expressing dp = rho g f(h) ... ?
Do you have a video talking about minor losses in terms of equivalent length?
Not yet. Only what we have in this playlist.
@@MichelvanBiezen I think you all can consider this. A lot of "professional engineers" in my field only know how to use it and don't know where it is derived from.
That is often the case. Once an engineer knows how to apply it, it becomes less relevant to know why it works.
Hi, sorry I got confused a little, In previous lecture, friction factor was calculated for laminar flow (64/Re) or turbulent flow (Moody chart). how come here we have a straight forward formula for it?!
Just like with all concpets in physics, we start with a simplified model. (Like ignoring wind resistance with projectile motion). This way we learn the basic principles which give us good approximate values espceically with low flow rates and substances with low viscosity.
It confused me as well. Basically, if we look at the bernoulli's, its written in pressure form directly -> in BAR (or Pa), so we can write directly dp = rho g f(h). I dont understand why its done in the video the way around, it is expressing friction factor using f(h) = dp / rho g, and then from friction factor again expressing dp = rho g f(h) ... ?
The final equation for frictional head lost at 1:45, does it mean that it does not depend on velocity and diameter of the pipe..
In the real world it does, but we want to start with simplified ideal systems before including all of the factors.
thank you very much