Using the tonnes per centimetre immersion, and the moment to change trim 1cm to determine the changes to a ship's draft after adding and removing weights.
The final displacement is 58,810mt. The true mean should be 11.54? On the other hand the in sinkage true mean draft? The final draft is it also corrected?
Final draft trimmed by the head? Is possible? Mostly cargoes are aft. Hence 3 and 4 cargo hold are loaded more. Probably this is panamax vessel. So, 3 and 4 are forward of midship
Thanks Tim 🙏🙏🙏🙏 this lecturer really helped me with my cargo assignment 👌👌🥰
Very well explained. Thanks and keep up the good work.
Why didn't you create this video a year earlier? I read many books until I understood it myself. You took it and told everything in 15 minutes)))
what book did you read sir?
nice one bruh, ive learned alot
The final displacement is 58,810mt. The true mean should be 11.54?
On the other hand the in sinkage true mean draft? The final draft is it also corrected?
Very informative
why do you reverse it at 6:35 and say it's negative 7.068 meters?
Thanks so much
the final draft are by head even the distribution of cargo mostly at after part? please i still dont understand 😅
Final draft trimmed by the head? Is possible? Mostly cargoes are aft. Hence 3 and 4 cargo hold are loaded more. Probably this is panamax vessel. So, 3 and 4 are forward of midship
Thank you Sir
Can i use drafts on perpendiculars for this calculation?
Good!
👍🏻
gg