Balancing Redox Reactions By Ion Electron Method | Easy Trick
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- Опубликовано: 26 июн 2022
- This lecture is about balancing redox reactions by ion electron method. I will teach you balancing redox reactions in acidic medium and basic medium by ion electron method. You will learn my personal trick through which you can balance any redox reaction by ion electron method in less than a minute. Also, you will learn many examples of balancing redox reactions.
To learn more, watch this lecture till the end.
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My Chem mam will teach good
But while i am studying 11th Balancing redox reaction was deleted
But now I am preparing for NEET i don't know to balance , because of your trick now i learnt to balance it... Thanks a lot 🙏🏻🙏🏻🙏🏻
CANT BE EXPRESSED HOW U HAVE TAUGHT IT SO BEAUTIFULLY AND EASILY THAN ANY OTHER INSTITUITIONS ....THANKS A LOT SIR
11th class students who are watching in 2024? Please mark your attendance .👍😜
Present sir😂😂😂😂
Present sir
Present sir😂💀
Present sir 😂😂☑️
Watching and commenting a hour before the exam
Watching it before one day my final chem exam
ikrr
Me too
Me too
us brother🗿
Yess 😂
you're genuienly the best teacher ive ever come across hands down. i pray for you and your well being sir.
Any student who is frustrated from school redox and they got here 😢😂😂❤
It's a fantastic channel to learn the hard things to easy way the students from 😊dull can become rich in your studies by using this channel by free tq so much sir for this fantastic teach🎉❤
the best trick I had ever done by,
as I am preparing for JEE I use to need such an amazing tricks
hands of you
🐿️same bro my coaching teacher is 💩 i don't understand any step of my teacher
@@gauravkr834same here bro
All the best for your JEE exam brother... You can do it!
I was found this topic very difficult .... but you made it easy sir........!!!Thankyou sir for your wonderful lecture!!!
😭 How Sir It Is Possible You Have A Very Easy Trick And Solution For tooo Much Difficult Questions Literally Sir You Are A Real Hero ❤
Sir in your last question you do reduction in Br
But the reduction will take place in MnO4
SIR PLEASE TELL ME THE ANSWER OF MY QUESTION
Last equations, MN +7 to Mn +4 is reduction, but you said it was oxidation and vice versa.
Yes
No increase irder oxidation... decrease order reduction...
Loss of electron and gain of electron that' s a concept
Yes
Ur correct!!
You nailed it sir i was so confused in basic medium but after watching you video it is clear.Thanku very much
Is anyone here for chem public 2024😂
Mee
You make topics crystal clear
One of the best teacher ever.i have no words to praise u sir and Hats off u sir ❤❤🙏🙏 . please make videos regular it's really very helpful for all the students that facing a lot of problems to understand the topics but u make all the topics crystal clear 😊
I did it! 🕺🏾💃🏾
I balanced the last equation which u challenged us at, was difficult but ur trick saw me through. I think I understand now that superheroes don't need capes 💯
🎉
Your lectures are so useful for quick revision
💝
Last question is wrong. In that question Br is oxidising not reducing
Yes you are right
No you are wrong
Ss
Ya that's true
Absolutely I was wondering
Ohh blllee blleee finally aa gyi balancing 🕺🕺🕺
this trick is really really helpful and easy , i thought i would never be able to balance redox reaction ,but now i can easily do so ...... thanks to you
Our 50 min class was dusted within 15 min. Thanks a lot sir.
In the last reaction you mixed up oxidation and reduction, bromine is getting oxidised as it lost 6 electrons. OIL RIG - Oxidation Is Loss, Reduction Is Gain. Also, instead of cross multiplying , you basically just have to take LCM like you do for fractions.
my guy. you know ur stuff...
Sir you are legend in teaching chemistry I learnt lot from yours videos sit tq so much sir🥰🥰
Okok ur welcome
Sir i bow to you, you are great teacher who saves with tricks all time.❤❤
Sir u clear out all my doubt just in a minute 👍tnk very much I really love your tricks sir😍
Just few hours before of final exams 😂🤣
😂👍🏼
Sir I don't know how to express my gratitude because our sir had taught us a big method which was difficult to understand and this is just amazing thanks sir🙏
Very smooth explanation 👍👍 with calm voice, satisfying explanation 😌
Teaching and tricks wow amazing aur video dale sir
Sir there is a wrong in the redox reaction u gave in basic medium the lose of e- should be 1 not 2 pls check it 8:51
THAT WAS MY BIGGEST PROBLEM .. AND U SOLVE IT DOWN.. TYSSSSSSM A LOT 😢❤
sir his trick is mind blowing i just learn this easy method in one go . i have watched numbers of videos but i didn't get that but your tick is soo easy love it
Fantastic channel and the best explanation❤❤❤❤
May your channel touch the sky 😊
Thank you very very much
Legends are watching 2 hours before exam
1 hour 😂 really
Am Writing retest Bro 😢😓😓
In last equation Mn+7.. Is reduce to Mn+4.. So it is reduce not Not oxidise..
Superb work Sir
Very helpful 👌 ☺️
May God Bless U 🙌 🙏 ✨️ ❤️
Sir you are brilliant teacher
I watch this video and my all doubt are clear
Thanks for your helpful video
Thankyou sir
Finally I understood the ion electron method very easily
U have told you're balancing the redox reactions by half reaction method/ion electron method but you've balanced it by oxidation number method?
Watching it before neet 2024😭
Sir u r best
Or kisi concept smj aaye na aaye but aapka pakka aata h
U explaination is really good
Much good I can say
Last balance reaction ,Br is oxidised and Mn is reduced but you said opposite...pls clarify
Sir your tricks saved my life🙏🏼....
chall mari jaa rahi thi ka be
concept clear,,,,,,,, thank you sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Underrated channel and video ❤
Hello, thank you for helping me understand this topic. Thank you so much for that. 🥰
GÃ
GÆ
Thank you sir for teaching this problem very easily 🎉🎉🎉🎉
Best video on balancing! ❤️❤️❤️❤️❤️Thanks a lot sir
9:49 what if the h+ ions are in odd number , we cannot divide it by 2 right? , what should we do in that case 😢 please explain
Very easy to understand ❤❤❤❤
I balanced the last question on my own tho tnx for the lecture it was more useful than sitting in a class room and hearing a moaning single voice that doesn't quite deliver the logic and make it interesting..... keep it up bro...
Sir in the last reaction should not Mg be reduced and Br oxidised.
I watch 30 Mintes before exam 😂
You always help me in exams
Bht acha explanation ta apka mujhy smjh ni aa ra toda confusion ta but apkay video s bht clear hya tq sir
In the last reaction Mn and Br both were already balanced. So why should we balance only Mn and not Br?
cross multipication
What easy trick 😍 I really love it thank you so much🙏 we want more easy and helpful trick please
Your video in super it makes stundents understand easy way ❤
Today is my exam and I'm watching it before exam... 😅😂
Same😅
Best trick to solve thank you so much sir
Thank you so much sir! Cleared my doubts in such a short time!
Thanku so much sir ❤❤❤❤
Sir your trick doesn't always work with the Questions given to me in my tuition/school. Atoms get balanced but electrons doesn't get balanced completely.
Check it out. Ex. MnO4 + C2O4^(2-) -----------> Mn^(2+) + CO2
Yes
Same
Yes bro same problem
Bro your questions is wrong first of all Mno4^(-1)...did you try to balance the 2 carbon on both side ?.
@@Klk0087 yup bro but the trick in video isn't applicable here and we need use fundamental methods
I balanced the last equation without seeing your answer sir i got the result but my mistake was i dont know the matter of division 😅 tnx a lot sir ❤️ lots of love from ap❤️❤️❤️ india
yes bro , me too, it was not hard
@@photo_chromatic7095 bro kal paper he chem ka tera?
@@GOATS719 han bro
@@photo_chromatic7095 mera bhi he yarr abhi me 20 min vali revision video dekhunga ga fir notes revise krke so jau ga 🥺 pta nhi kesa jaega vese konse school se ho
@@GOATS719 are baap re, mera bhi same stategy hai
Legendary explanation!
thankyou sir i am so confused that how to balance reaction thank a lots for a such easy trick and it helps me a lot
7:02 The equation is balanced 😊
Your guides are really useful.
Thanks for letting us know
For the given redox reaction,
aCr2O}+bSO}(aq)+cH(aq)→→
2aCr3+(aq)+bSO{(aq)+SH2O(e)
the coefficients a, b, and c of a balanced equation are found to be, respectively:
Wow! This is a really great help, I didn't understand this anywhere until I watched your video. Thank you very much
Sir pls doo the trick of half reaction method
Recently upload
Thank you sir,it was really helpful 👍👍🤛
U r genius 😮bro put the video like this only
Thanks a lot amazing session
TQ for saving our time by tricks sir😍
I am happy by listening and all my doubts cleared by this video you are really great
Thanks for such a great explanation and tricks
Sir I have no words to express ..thanks a lot sir❤
Watching this 2hrs before my batch test
in that last question i think we're mixing up the oxidation and redution :)
Thank you very very very much
YOU ARE BEST LITELLARY YOU are great thank you so much for this
Thanks dude
Last one is incorrect in terms of redox
Very very helpful u r srsly the best sir ❤❤❤❤❤❤❤❤🎉
At 9:08 iodine is having only 1 electron is more on the product side like -1 to 0 so only 1 electron gap so why are we writing 2 electrons and then solving it forward
Ekdam jhakas😂. Nice method of clearing doubts❤
Nice method 👍
Thanks a lot sir
Thank you so much sir, the understanding is very simple 🙏
Thank u very much sir!!❤
Thanks sir very helpful full understand
This video is very helpful
Thank you so much....mannnnnnnn!!❤
In the last example i.e Br and Mn example, you said Br- to Br+5 is reduction wherein increase in oxidation no is observed, but as per your previous lecture of oxidation and reduction reactions, Oxidation means increasing oxidation no, reduction means decreasing oxidation no. please explain which is correct.
Thnku sir❤❤
At 11:02 there is mistake bromine is not reduced it is oxidized similarly Mn not oxidized it is reduced