Solving Collision Problems with Momentum Conservation

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  • Опубликовано: 29 янв 2025

Комментарии • 20

  • @franzvicsandoval5432
    @franzvicsandoval5432 2 года назад +1

    Still watching your videos since I have Physics this term. You've been a huge help to me and I wanted to thank you again for what you're doing. Keep at it man!

    • @PhysicsclassroomVideos
      @PhysicsclassroomVideos  2 года назад

      Great to hear! Thanks for the feedback. And thanks for supporting the channel.

  • @shiroeuwu797
    @shiroeuwu797 3 года назад

    This helps me clear my questions in Physics New to physics So im having a hard time solving My hw Thx!

  • @A3temii
    @A3temii 3 года назад

    Thank you for the lesson, it's very easy to understand!

  • @dedehyman
    @dedehyman 2 года назад +1

    12:30 wouldn't it be 'cm/s' not 'm/s'?
    because in the question it said 'cm/s' not 'm/s'

    • @PhysicsclassroomVideos
      @PhysicsclassroomVideos  2 года назад +2

      Yes. My mistake. Its cm/s.

    • @dedehyman
      @dedehyman 2 года назад +1

      @@PhysicsclassroomVideos other than that this video really helped me a lot thank you sir

  • @AlbertoTuber
    @AlbertoTuber 3 года назад

    Thank you for the lesson

  • @amitsharma-hr3in
    @amitsharma-hr3in 3 года назад

    What will be the calculations when colliding bodies are not free bodies. e.g. if I use a hammer to punch on a stationary flat body, how we will calculate impact force in that case? i have built an experimental setup where i have to model the impact force on the surface by a linearly movable arm attached to a motor (like: sewing machine)

    • @PhysicsclassroomVideos
      @PhysicsclassroomVideos  3 года назад

      One would typically use the impulse equal momentum change theorem for that.

  • @Physics072
    @Physics072 7 месяцев назад

    Note: Momentum is only conserved in elastic collisions, no external forces at work. In real life there are generally some external forces at work ie. friction. Its close but not zero. Also an obect at rest has zero momentum only in that frame of reference. Ie. the car parked in the street MxV= Mx0=0. But the earth is moving and so is the car. So in a different frame of reference the stationary car can have momentum.

  • @samanthaeaves6923
    @samanthaeaves6923 2 года назад

    How do you find each carts momentum after the crash? I have found each cart's momentum BEFORE the crash, but I am struggling to find the momentum of each cart after the crash. Someone please help! Please... I'm struggling over here!!!!

    • @PhysicsclassroomVideos
      @PhysicsclassroomVideos  2 года назад +1

      Momentum is mass*velocity. To calculate one (or both) of the two carts' momentum you will need to know a mass and a velocity value.

    • @samanthaeaves6923
      @samanthaeaves6923 2 года назад

      @@PhysicsclassroomVideos thank you for such a quick reply!

  • @kennethsicat4041
    @kennethsicat4041 3 года назад

    👍

  • @foyezhaque9440
    @foyezhaque9440 3 года назад +1

    no number of likes will explain my love for thisvdis

  • @ariane2872
    @ariane2872 3 года назад +1

    Can you help me in my homework

  • @genesisruvielleduran7660
    @genesisruvielleduran7660 3 года назад

    awit bayaw