It is 2:27 am, my physics exam is in 6 hours and I am learning all of the material from this channel. Thank you sir, I hope whoever you are, wherever you are, you are getting some head rn
ansd realy this man teaching and u talking bout giving some head not the time for that jeez some people these days so inapropreate i am too but u too far man
sir i just want to comment that our professor doesnt teach anymore and just send links of your video in our class. that's how brilliant you are!! you're brilliant!! idk abt him tho
I like these simple problems bc they simply show how to solve much more complex problems, this literally is good practice for me not to ace a hard question, but I'll at least understand how start to lay out a problem and at least get marks for that
To teach like this just not need ability or mind it need also good heart and knowing what student needs and what they struggle with you know you are good man not only genius😍❤
@@Omar-dq3bk I'm not sure but since this just the basic introduction (as the title states) then it is. If you have notes that came from your teacher then use it as a reference when finding videos on yt, if the one in this vid is the same one in your notes then this is for you.
@@vypr7849 Thanks man I really appreciate your reply. I just finished studying and I’m ready for the exam. If you are wondering it’s nearly 9pm right now in my country so that might be the reason that I have sent the previous message in a weird time.
In the last question with the rock and the cart, if the rock lands in the middle of the cart instead of at the back, since the rock would be initially stationary there would static friction between it and the floor of the cart. As the frictional force would be opposing the direction of motion of the cart, would that static frictional force contribute to slowing the carts velocity down?
Guys for people who still didnt understand the video i have better equation for yall , with these two equations you can solve all these questions with out thinking too much so here it is ❤: M1×V1i=M2×V2f+m3×V3f He used this question in the second question as you can see at the end you set V3f with the answer you dont write number in it place And for the last one you use M1×MV1i+M2×V2i=(m1+m2)vf And again you put the numbers in it place you will set VF= to the numbers and you will get the answers excuse me for my english guys but this is i swear the best two formulas if you memorize them you will have no problem , if you still didnt understand go ask chatgbt about the questions in the video and he will show you the answer with the formuals so you might understand Thank you guys ❤
Okay but indirect proportional 5kg 20m/s 70kg x That would have explained it better imo, since 1.43m/s times 14 (70/5) is 20m/s. It comes out as the exact same, unless this doesn't work in specific occasions and therefore your formula may be better I have not yet looked at the solution, but this should work with 2) as well. Maybe it's good to show newton's 3rd formula to help comprehend, but why would I ever learn a new more complicated formula than just use that? Unless it's the same but presented differently. Sorry if I'm wrong. 50kg v= 30kg v +20kg v ind. p. 30kg 40m/s 20kg x 40m/s x 1.5 = 60m/s. 3. I'm assuming the momentum (kg x m/s) stays the same, so since the weight increased from 200kg to 250kg, it's 1.25 times slower. So either 200/250 or 1/1.25, which is 0.8. So it's 0.8 times the original velocity, which is ((15/5) x 4 = )12m/s. Same as Pı = Pf Loved this video, thanks!
How can the law on conservation apply, when the rock, which wasn't initially in the system is now added to the system? Wouldn't that be an external force (mass of the rock * times the acceleration of the rock due to the gravity)?
Omg !! we have horrible teachers .. my teacher wrote this law m1v1=m2v2 and said alawys put minus sign with the biggest msss and now i know why because this isn't the law of conversation !!!!
Or maybe it still applies Because it's an isolated system, and the force is only from the inside of the system, and the overall mass is still 50kg i guess.. Nvm
he used 0=MAVA+MBVB because there were two objects with completely different velocities that we wanted to find. in the final question there's only one subject we need to find because if we think of the railroad cart and the rock as one object, the object initially moved 15 m/s and then gained mass. so the pi=pf is MVi=MVf. he found the initial momentum, and is looking for the final velocity
@@tofunmio But even if the railroad cart and the rock are one object, wasn't -MAVA=MBVB, because of newton's third law showing that with every object on that video had a negative resultant force in the opposite direction causing the MAVA to be negative.
Since the railroad cart was moving wouldn't there be a negative resultant force, causing him to use the equation -MAVA=MBVB to figure out that force just like he did with the rest of the questions figuring out the new velocity
@@juniorasare272 sorry for late reply, this isnt newton's third law, more like conservation of energy, or in this case momentum. its the momentum from before has to equal the momentum after, if in a closed system
I need assistance with a problem using Conservation of Momentum. We are studying ET objects in space. We are working on a project Comet Impact. Here is the problem: Below i the Conservation of Momentum equation: (Vcomet) x (Mcomet) = (Vimpactor) x (Mimpactor) Where: Vcomet = sideways velocity in miles/hr of Comet Buttercup after the detonation (what we need to figure out), Mcomet = 1,100,000,000 ton (1.1 x 109 ton), Vimpactor = 7,800 miles/hr Mimpactor = 800,000 ton (8.0 x 105 ton) Remember, we won’t be actually hitting the comet. But the energy of the explosion will be like hitting the comet with a fast-moving object Step 1: Re-arrange Equation to solve for Vcomet, then calculate the sideways velocity in miles/hr that the comet would have after the detonation of the bomb.
The national government announced ECQ over the NCR and decided to distribute 1000php worth of goods. A delivery truck carrying 80 cavans of rice is traveling at 10.0 m/s to Southern Luzon. The mass of the truck and one cavan of rice are 3500 kg and 50 kg, respectively. The driver of the truck has a mass of 80 kg. (a) What is the magnitude of the momentum of the truck with the driver and the cavans of rice? (b) At a particular city, the driver unloaded eight cavans. What is the new momentum of the truck with the driver and the cavans of rice if the driver maintains the same speed? can u solve this?
or if you don't remember all these formulas, you could just take 100 (product of 5kg times 20m/s) and divide it by 70 and you'll get the same answer. Don't forget to make it negative though.
Here is a problem for you . We are spinning at 1000mph and moving at 590,000mph through the galaxy. At what point does a space craft speed up to 590,000mph?
Let's say you have a 1 kg mass moving to the right at 20 m/s that collides with a stationary 2 kg mass and bounces off to move to the left at 10 m/s with the 2 kg mass moving to the right at 5 m/2. The time of collision is the same for both masses, but the net force is different since the impulse or change in momentum on the 2 kg mass is 10 kg*m/s and the impulse or change in momentum on the 1 kg mass is -30 kg*m/s. How does this figure or how is momentum conserved with the momentum lost by the 1 kg mass not being equal with the momentum gained by the 2 kg mass? How can the net forces be different?
The numbers you gave at the beginning they are wrong that's why your result is wrong see the equations for the elastic collision and you will find the right numbers
A represents the first object and B represents the other. In the Astronaut example, the astronaut threw the ball and we are find the astronauts velocity He chose to represent the astronaut as A and the ball as B. You can choose any letter or picture or whatever to represent something in physics.
Dr! What if the helicopter files at the speed of 990km/h. The pilot fire a missile forward out of a gun barrel at the speed of 2520km/h. The respective masses of the helicopter and the missile are 500kg and 50kg respectively. Use the principle of conservation of momentum to calculate the new speed of the helicopter immediately after the missile had been fired.
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egg
It is 2:27 am, my physics exam is in 6 hours and I am learning all of the material from this channel. Thank you sir, I hope whoever you are, wherever you are, you are getting some head rn
did u pass?
@@tlili3990 86% 🤝
@@michaelhartley8277 that's rlly good! Congrats!
ansd realy this man teaching and u talking bout giving some head not the time for that jeez some people these days so inapropreate i am too but u too far man
@@BloodHound-ld2eg tell everyone search is over and thanks for helping, we finally found the dude who gets no bitches
I want to cry because of physics
Me too😭😭😭😩
Same ✊😔
my friend asked yesterday why I had disappeared, that was my exact reply.
She said she also wanted to cry just thinking about it.
same
😭😭😢
when i graduate, imma yell out the organic chemistry tutor, man has helped me so much
LMAO DO IT
When do you?
@@aannmoo9666 end of June
@@vlvt-things don't forget
@@cursuscruor5080 graduating in 2 weeks from now, still remeber this
sir i just want to comment that our professor doesnt teach anymore and just send links of your video in our class. that's how brilliant you are!! you're brilliant!! idk abt him tho
lmfaooo oct does it best
i must admit that you are my best youtube tutor ever....Thank you so much for your good work...
Thanks bro you make physics soo easy...
I hated momentum before but now you have made it easier.
Thanks,
This man taught me better understanding physics than all of the teacher's ive seen
Actually just learned more about momentum here in 12 mins than i did in months of school. Thank you so much
Samee😭😭😭
I like these simple problems bc they simply show how to solve much more complex problems, this literally is good practice for me not to ace a hard question, but I'll at least understand how start to lay out a problem and at least get marks for that
Thank u so much couldn’t focus in class and completely missed this lesson but your video helped tons
its crazy that just by having a good explainer how easy a concept can be to understand! thank you so much for sharing your skill of education.
I don't know how to thank you but one thing you made this topic more easier to me than expected........
Thank you sooooo much sir.....
You explained this so well!! better than any teacher 😅😅
i love how we all run to organic chemistry tutor right before an exam
My physics book sucks at explaining things. You are so much more efficient at explaining physics.
do you play fortnite
@@JoeyBeene lmao
Thank youu! Kinda got bored in class and missed all of this 😂
u aint the only one g😂. phy gets me bored
same, the fact that the class is online does not help!
Bro. The way u teach is amazing. ❤️
i've been st4rruggling so long with this. you explained this super well! thank you very much!
studying for physics quiz the morning before, GG
Omg same 💀
Studying early for the next unit. Hope your quiz went well!
Same except i have it in an hour lmao
How did it go?
@@sp5216 i think it went alright from what i can remember
Cramming for physics final tomorrow
Carlos pedraza haha same
Buttery Biscuit how did it go ?
THE Mobile Pro pretty good actually got a 94% on it thanks to this video
@@guapdoctor4534 You must be smart
lovely, lovely a bunch lovely not really bro my chem Mark is a 65
I’m so grateful honestly I didn’t hear anything my teacher was saying 😭
You just helped me pass my Physics test. Thank you!
absolute lifesaver, I understand this so much more better, tmrw midterms for science 😨😨😨😩😩 thank you!
I used to hate physics previously but after learning from you I love physics 💗 a lot.....
Y u literally tech better then my school teacher?!! Life saverrrrrr
To teach like this just not need ability or mind it need also good heart and knowing what student needs and what they struggle with you know you are good man not only genius😍❤
Every physic class i often cooked but that man makes me feel better
Well sh*t, got two hours left before the test and I haven't learned anything...
How did it go
@@7nsm975 I passed and now in college XD
@@Omar-dq3bk I'm not sure but since this just the basic introduction (as the title states) then it is. If you have notes that came from your teacher then use it as a reference when finding videos on yt, if the one in this vid is the same one in your notes then this is for you.
@@vypr7849 Thanks man I really appreciate your reply.
I just finished studying and I’m ready for the exam.
If you are wondering it’s nearly 9pm right now in my country so that might be the reason that I have sent the previous message in a weird time.
@@Omar-dq3bk I see. Welp, best of luck in your exams.
Physics ang nag papahirap sa akin🌿
You are literally my savior 😮
when im rich im gonna donate a lot of money to you man
Thank u sir .
Finally I feel like I got something about momentum ❤
Nice! Thank you I liked the closure at the end!
This is my last challenge because of physics its my last test in freshman final exam thanks sir you are with me for this day
THIS HELPED A LOT .THANK YOU
going to take removal exam for physics this upcoming thursday after failing my finals, i hope to pass and i will pass, thank you for this!
The only way I passed my test 🙏😌
Super helpful 💕💞☘ much appreciated🙏🏻👏🏻
Great, concise video!
In the last question with the rock and the cart, if the rock lands in the middle of the cart instead of at the back, since the rock would be initially stationary there would static friction between it and the floor of the cart. As the frictional force would be opposing the direction of motion of the cart, would that static frictional force contribute to slowing the carts velocity down?
Thank uh sir 😀😀
Excellent video! Thank you!
i would legit fail physics if it wasnt for this guy lol
Guys for people who still didnt understand the video i have better equation for yall , with these two equations you can solve all these questions with out thinking too much so here it is ❤:
M1×V1i=M2×V2f+m3×V3f
He used this question in the second question as you can see at the end you set V3f with the answer you dont write number in it place
And for the last one you use
M1×MV1i+M2×V2i=(m1+m2)vf
And again you put the numbers in it place you will set VF= to the numbers and you will get the answers excuse me for my english guys but this is i swear the best two formulas if you memorize them you will have no problem , if you still didnt understand go ask chatgbt about the questions in the video and he will show you the answer with the formuals so you might understand
Thank you guys ❤
YOU ARE A SAINT THANK YOU
Who's here still striving to study because they exams tommorow?
🙋🏽
Super helpful ❤❤❤❤❤
10:10 Newtons Third Law* If i am not wrong
Okay but
indirect proportional
5kg 20m/s
70kg x
That would have explained it better imo, since 1.43m/s times 14 (70/5) is 20m/s. It comes out as the exact same, unless this doesn't work in specific occasions and therefore your formula may be better
I have not yet looked at the solution, but this should work with 2) as well. Maybe it's good to show newton's 3rd formula to help comprehend, but why would I ever learn a new more complicated formula than just use that? Unless it's the same but presented differently. Sorry if I'm wrong.
50kg v= 30kg v +20kg v
ind. p.
30kg 40m/s
20kg x
40m/s x 1.5 = 60m/s.
3. I'm assuming the momentum (kg x m/s) stays the same, so since the weight increased from 200kg to 250kg, it's 1.25 times slower. So either 200/250 or 1/1.25, which is 0.8. So it's 0.8 times the original velocity, which is ((15/5) x 4 = )12m/s.
Same as Pı = Pf
Loved this video, thanks!
Who's here is studying because he/she work as a CFD Engineer? 😅😂
How can the law on conservation apply, when the rock, which wasn't initially in the system is now added to the system? Wouldn't that be an external force (mass of the rock * times the acceleration of the rock due to the gravity)?
In 10:08, u meant third law right?
i think he meant newton's forth law
@@celeryystick Nah he meant newton's 69th law. Oh wait no he died a virgin.
Yes, the 2nd law is F=ma
Omg !! we have horrible teachers .. my teacher wrote this law
m1v1=m2v2
and said alawys put minus sign with the biggest msss and now i know why because this isn't the law of conversation !!!!
enjoy
6:10
Conservation of momentum law doesn't apply if the mass changes, does it?
;-;;;
Or maybe it still applies
Because it's an isolated system, and the force is only from the inside of the system, and the overall mass is still 50kg i guess..
Nvm
I like the way he says "Astronaut" 😊
yessss and the way he says de-crease lol
Thank you once again
Can anyone explain how to solve cart A and Cart B problems when you need to find the conversation of momentum of Vi and Vf of both carts
Why do you use -MAVA=MBVB equation for every question on this video apart from the last question ?
he used 0=MAVA+MBVB because there were two objects with completely different velocities that we wanted to find. in the final question there's only one subject we need to find because if we think of the railroad cart and the rock as one object, the object initially moved 15 m/s and then gained mass. so the pi=pf is MVi=MVf. he found the initial momentum, and is looking for the final velocity
so his equation turned from MV=MV TO (200kg)(15m/s)=(200+50kg)(v?) which is 3000=250V
@@tofunmio But even if the railroad cart and the rock are one object, wasn't -MAVA=MBVB, because of newton's third law showing that with every object on that video had a negative resultant force in the opposite direction causing the MAVA to be negative.
Since the railroad cart was moving wouldn't there be a negative resultant force, causing him to use the equation -MAVA=MBVB to figure out that force just like he did with the rest of the questions figuring out the new velocity
@@juniorasare272 sorry for late reply, this isnt newton's third law, more like conservation of energy, or in this case momentum. its the momentum from before has to equal the momentum after, if in a closed system
Didn’t show up to class so trying to teach myself an hour before my exam hahahaha
For number 3 before you did it i divided 15 by 4 and got 3.75 then I subtract that from 15 because I knew that the weight would slow it down?????
Thank you.
I need assistance with a problem using Conservation of Momentum. We are studying ET objects in space. We are working on a project Comet Impact. Here is the problem: Below i the Conservation of Momentum equation:
(Vcomet) x (Mcomet) = (Vimpactor) x (Mimpactor) Where: Vcomet = sideways velocity in miles/hr of Comet Buttercup after the detonation (what we need to figure out), Mcomet = 1,100,000,000 ton (1.1 x 109 ton), Vimpactor = 7,800 miles/hr
Mimpactor = 800,000 ton (8.0 x 105 ton)
Remember, we won’t be actually hitting the comet. But the energy of the explosion will be like hitting the comet with a fast-moving object Step 1: Re-arrange Equation to solve for Vcomet, then calculate the sideways velocity in miles/hr that the comet would have after the detonation of the bomb.
Post in physics forums or physics stackexchange. Not Here.
Thank you
Thank you 🤞🏾
Not sure y'all guys what learnin', but m learniin english most here))))
The national government announced ECQ over the NCR and decided to distribute 1000php worth of
goods. A delivery truck carrying 80 cavans of rice is traveling at 10.0 m/s to Southern Luzon. The
mass of the truck and one cavan of rice are 3500 kg and 50 kg, respectively. The driver of the truck
has a mass of 80 kg. (a) What is the magnitude of the momentum of the truck with the driver and the
cavans of rice? (b) At a particular city, the driver unloaded eight cavans. What is the new momentum
of the truck with the driver and the cavans of rice if the driver maintains the same speed? can u solve this?
Yes
Thank you sir
Physics have me dying😭
or if you don't remember all these formulas, you could just take 100 (product of 5kg times 20m/s) and divide it by 70 and you'll get the same answer. Don't forget to make it negative though.
Our school teacher told us that if we stop the moving object the final velocity is 0, then the formula is mu-mv/t. Is it correct?
It's 12:40am and Im falling asleep but I need to push through a little longer
What if you're doing a cannon problem and the cannon doesnt move? Won't that just give you a velocity of zero for both?
First question, how could it be an astro of 150kg would only have to throw at half of the speed (1.43m/s?
When will the momentum be conserved ? ( sorry I might of missed that in the video).
Dragon Blade in elastic and inelastic collisions, momentum will be conserved. So basically always
for anyone that reads this later, it's when the total external forces on the system equals 0. That's when momentum is conserved
@@liahe2146 thx
When the external forces acting on the masses equal 0
Here is a problem for you . We are spinning at 1000mph and moving at 590,000mph through the galaxy. At what point does a space craft speed up to 590,000mph?
I wanna cry :) i still don't get it what is wrong with my brain
I love you 😭
For the first question I took the P = MA and applied that to the Astro dude so V = P/M is that wrong
In the second example why did the Mass become -ve negative when moved to the other side
1000 thoughts a day, 999 of them are y the organicchemestrytutor isn't my physics teacher instead
My brain left me… i have no clue i can’t wait to be out of this class this video was 6years ago
I GET IT NOW 😭😭😭😭
Let's say you have a 1 kg mass moving to the right at 20 m/s that collides with a stationary 2 kg mass and bounces off to move to the left at 10 m/s with the 2 kg mass moving to the right at 5 m/2. The time of collision is the same for both masses, but the net force is different since the impulse or change in momentum on the 2 kg mass is 10 kg*m/s and the impulse or change in momentum on the 1 kg mass is -30 kg*m/s. How does this figure or how is momentum conserved with the momentum lost by the 1 kg mass not being equal with the momentum gained by the 2 kg mass? How can the net forces be different?
The numbers you gave at the beginning they are wrong that's why your result is wrong see the equations for the elastic collision and you will find the right numbers
V inital=(MFinal x VFinal)/(M Iinital) or Vfinal=(Minital x Vinital)/(M final)
How can the astronaut throw something eastward?
He is in Space
It probably looks like the astronaut throws the ball eastward relative to his spacestation
Is that even the point?
iMaGinE
WHAT IS THE MEANING OF A AND B
A represents the first object and B represents the other.
In the Astronaut example, the astronaut threw the ball and we are find the astronauts velocity
He chose to represent the astronaut as A and the ball as B. You can choose any letter or picture or whatever to represent something in physics.
@@gordonchiew7341 thanks dude
i love u man
Thank you!
Came here confused, and ended up leaving more confused.
good
one thing i don't understand is that why is the velocity to the left negative?
Check out the cartesian plane
My exam is in 1 hour 17 minutes and I don’t think I’m passing this course :(
im trash at science doubt this will help me 100% but ik u r smat af ggs
I feel like the wording is massively over complicated
Dr!
What if the helicopter files at the speed of 990km/h. The pilot fire a missile forward out of a gun barrel at the speed of 2520km/h. The respective masses of the helicopter and the missile are 500kg and 50kg respectively. Use the principle of conservation of momentum to calculate the new speed of the helicopter immediately after the missile had been fired.
😭😭😭, just cry it , ty
JUSKO, AYAW KO NA MAG ARAL 😔
My brain is still not braining right now
ily bro no homo