Wow! What a brilliant professor with such intelligent analogy of water tank in quasi fermi level. I am taking semiconductor device course in this semester and this professor made my life easy.
To be clear k is equivalent to momentum (velocity) since mv = p = \bar{h} k. So horizontal shifts on the E-k diagram are changes in momentum rather than changes in position. Additionally, changes in momentum (k) require a force (impulse) from the crystal lattice -- a phonon interaction -- that manifests as heat. The mean phonon energy is much less than the bandgap so several phonons are typically required to promote an electron to the conduction band using thermal energy alone; the phonon vector momenta directions are random and add to nearly zero for nearly vertical transitions on the E-k diagram. Also, left-to-right shifts cancel right-to-left shifts on average, but these momentary impulsive currents can be seen as thermal (Johnson) noise.
Lol, our prof at IIITDMJ mentioned the term "Quasi Fermi levels" are here we are Cool topic tho, now i understand why our prof drew a curved fermi level in the active region (of the pn junction diode)
Very bad explanation. If it was taken seriously, the splitting of the quasi Fermi levels will be ALWAYS greater than the gap energy because the lowest state of conduction band is always occupied and the upper edge of the valence band is always empty.
This lecture was a fantastic way to explain such concepts. Thank you sir, and nptelhrd for posting your expertise.
He explained all the topics in a pin point precision. Clear explanation and good analogies made the topic interesting. Thanks a lot Sir , and NPTEL.
seen lots of lectures on this topic,but this is something else,truly amazing 💙
Wow! What a brilliant professor with such intelligent analogy of water tank in quasi fermi level. I am taking semiconductor device course in this semester and this professor made my life easy.
comparing electron with water drop and hole with water bubble is highlight in the whole lecture
One of the best professor that I have ever seen.
Simply awesome...beautiful analogies!
Feels like learning more and more...
wonderful analogy ! Salute you sir !!!
Amazing professor as always!
Beautiful Explanations and wonderful analogies!!!
To be clear k is equivalent to momentum (velocity) since mv = p = \bar{h} k. So horizontal shifts on the E-k diagram are changes in momentum rather than changes in position. Additionally, changes in momentum (k) require a force (impulse) from the crystal lattice -- a phonon interaction -- that manifests as heat. The mean phonon energy is much less than the bandgap so several phonons are typically required to promote an electron to the conduction band using thermal energy alone; the phonon vector momenta directions are random and add to nearly zero for nearly vertical transitions on the E-k diagram. Also, left-to-right shifts cancel right-to-left shifts on average, but these momentary impulsive currents can be seen as thermal (Johnson) noise.
Very helpful, thank you Sir, greetings from Serbia!
Bless you, doctor, thank you very much
shenoy sir love from NIT Dholakpur
extremely good analogy!
Thanks a lot. May Allah bless you teacher.
Lol, our prof at IIITDMJ mentioned the term "Quasi Fermi levels" are here we are
Cool topic tho, now i understand why our prof drew a curved fermi level in the active region (of the pn junction diode)
Great lecture
thanku sir good job👍
T H A N K Y O U !!!!!!!!!!!!!!!! Prof. M. R. Shenoy
Is quasi static process and quasi fermi level same or different
thank you sir
18:31 We can hear the sound of the android inside him.
amazing !!!!!!!!!
lol, the song in the beginning is a Mexican song.
thanks a lot!!!!!!!!
gurudev
10:40
Very bad explanation. If it was taken seriously, the splitting of the quasi Fermi levels will be ALWAYS greater than the gap energy because the lowest state of conduction band is always occupied and the upper edge of the valence band is always empty.
31:00