PAPER Solution JEE Mains 2025 | 22 Jan Morning | Physics | Part 02

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PAPER Solution JEE Mains 2025 | 22 Jan Morning | Physics | Part 02
Your Queries :
Find the dimensional formula of 𝐵/𝜇0.
(1)[AL-1] (2)[AL]
(3)[MALT1] (4)[MALT-1]
Two metals Cs and Li have work function ΦCs = 1eVand ΦLi = 2.5eV. When light of wavelength λ = 550 nm falls on both plates, which plate will show photoelectric effect.
(1)Cs (2)Li
(3)Both (4)None
Two batteries are connected in parallel.
Statement-1 : Net emf is less than the emf of any one ofthem.
Statement-2 : Net internal resistance is less thanindividual resistance.
(1)Statement-1 is true and Statement-2 is false
(2)Statement-1 is false and Statement-2 is true
(3)Both Statements are true
(4)Both Statements are false
A parallel plate capacitor of capacitance 40μF is connected to a 100 V power supply now the intermediate space between the plates is filled with a dielectric material of dielectric constant k = 2. due to the introduction of dielectric the extra charge and the change in electrostatic energy in the capacitor respectively are
Statement-1: VSD is always less than MSD.
Statement-2: Vernier constant is product of number ofMSD × No. of VSD.
(1)Statement-1 is true and Statement-2 is false
(2)Statement-1 is false and Statement-2 is true
(3)Both Statements are true
(4)Both Statements are false
Entire YDSE setup is immersed in medium.
Assertion : Fringe width reduces
Reason : Speed of light decreases while frequencyremains constant
(1)Assertion is correct and Reason is false
(2)Both Assertion and Reason are correct
(3)Assertion is false and Reason is correct
(4)Both Assertion and Reason are false
Find distance ‘x’ of the object so that the object & image coincide.
An electron in the ground state of the hydrogen atom has the orbit radius of 5.3 × 10-11 m, while that for the electron in third excited state is 8.48 × 10-10 m. The ratio of the de-Broglie wavelength for electron in the excited state to ground state is
Three lenses are arranged as shown.
Find the power of equivalent lens in terms of R1 & R2.
From the given options, identify the diode connected in forward bias.
A closed organ pipe of length 10 cm filled with gas of density 𝜌1 , while an open organ pipe of length ‘L’ is filled with gas of density 𝜌2. Closed organ pipe vibrates in 7th harmonic while open organ pipe vibrates in 4th harmonic with same tunning fork. If 𝜌1/ 𝜌2 = 1/3 , and both gas have same bulk modulus ‘𝛽’. Find ‘L’
Find out equivalent capacitance for the situation shown in figure.
An electron is made to enter symmetrically b/w two parallel and equal oppositely charged metal plates, each of 10 cm length. The electron energy out of the electric field region with a horizontal component of velocity 106 m/s. if the magnitude of the electric field between he plates is 9.1V/cm, the vertical component of velocity of electron is (mass of electron = 9.1 × 10-31 kg, and charge of electron 1.6 × 10-19C).
Find MI of body after removing the disc of radius R/2 from the disc of radius R as shown in figure about central axis perpendicular to disc.
Two soap bubbles of radius 2 cm and 4 cm coalesce then find radius of common surface.
Two spheres of radius r1 = 0.2 m and r2 = 0.8 m, have temperature 800 K and 400 K respectively. If energy radiated by sphere of radius r1 is E, Find the energy radiated by sphere of radius r2.
Find heat required to convert 1 gm ice at -10°C to steam at 110°C.

A body of mass M at rest explodes into three pieces, in the ratio of masses 1 : 1 : 2. Two smaller pieces fly off perpendicular to each other with velocities of 30 m/s and 40 m/s respectively. The velocity of the third piece will be:
A solid sphere of constant mass density 𝜌 applies force F1 on mass ‘m’ when a spherical cavity of radius R/3 is made, the force acting on ‘m’ is F2 . Find F1/F2.

A particle is thrown with speed 60 m/s at an angle 30° with horizontal. If h1 is height of particle after 1 sec. and h2 is height covered 1 sec before it reaches max. height. Find ratio h1h2 = ?
Particle is given velocity v0 so that string becomes slack at highest point. If K.E. is KB at an angle 60° with lower vertical and KC is K.E. at an angle 60° with upper vertical then 𝐾𝐵/𝐾𝐶 = ?
Find current through battery. Jockey is at middle point on 1Ω as shown in figure.