I am just beginning to take these classes where we are using this stuff, which make my head actually feel like it has a black hole in it, but you have pulled me out, thank you!
Thanks a lot for appreciation. I am trying to develop a website and organise the video for efficient use by the students. I will appreciate if you could post something there along with your picture. At present development work is going on. I will request my Admin to do it on your behalf, if you send a picture along with text on my email, anil.anilkhandelwal@gmail.com Some Courses Uploaded for Testing only on the Website. Here is link to the website being developed: www.globalmathinstitute.com/ Thanks a Lot!
@@MathematicsTutor Thanks a lot for this opportunity. I will be definitely in touch with you through mail. This is an honour to me. I am eagerly looking forward for this upcoming website and I can clearly see rather predict there will be exponential growth in the number of visits / likes to this website and above all millions of people will get benefit out of it, video lectures etc. I wish you all the success for this endeavour and your way of teaching is fabulous. A great work for the betterment of mankind and a great service to make the universal tool mathematics interesting and easy to understand. Thanks a lot.
7. From a common starting point on a circular path around a park, five persons started moving in the clockwise direction with speeds X1, X2, . . . , X5 meters per second, respectively. Suppose that the total length of the circular path is 200 meters. Assume that X1, X2, . . . , X5 are independent and identically distributed as Uniform (0,2) variables, and each person takes several laps around the park. If T denotes the time for the first instance when two persons meet after starting, find the expected value of T. Sir can uhh solve this question plzz
8 does not fall in between -4 to 6. So should not the answer be 1. I understand the concept behind to calculate the area but here a value should have been taken between -4 to 6 to explain here.
Hi, edwin. Nice to meet you Regarding your qn: Hello, what if i have interval [2, a] and f(4) = 0.8, how do I find a? Solution: (4 - 2) / a - 2 = 0.8, 2 / a - 2 = 0.8 / 1 Cross multiplying, we have: 0.8(a - 2) = 2 × 1 = 2 Subsequently, from multiplying both sides by 1.25, We have: a - 2 = 1.25 × 2 = 2.5 Therefore, a = 2 + 2.5 = 4.5 Hope this is helpful
Hi, professor anil. Your handwriting is phenomenal 🍀. And your teaching skills stand at the top of the mountain 🏔
Thanks a lot!
@@MathematicsTutor you are welcome, sir...
I am just beginning to take these classes where we are using this stuff, which make my head actually feel like it has a black hole in it, but you have pulled me out, thank you!
The best video on uniform distribution ever.. thank you sir
Thanks for appreciation.
Crystal clear explanation Sir... Thank you very much.
Thanks. Here are some video on this topic: ruclips.net/p/PLJ-ma5dJyAqqj15J32Fb-hg6w7UogB3U6
@@MathematicsTutor Thank you Sir.
It's a good explanation. Lucid. Presentation was excellent!
Thank you sir. What a beautiful explanation with a simple and easy to understand examples. Really great.
Thanks a lot for appreciation. I am trying to develop a website and organise the video for efficient use by the students. I will appreciate if you could post something there along with your picture. At present development work is going on. I will request my Admin to do it on your behalf, if you send a picture along with text on my email, anil.anilkhandelwal@gmail.com Some Courses Uploaded for Testing only on the Website. Here is link to the website being developed: www.globalmathinstitute.com/ Thanks a Lot!
@@MathematicsTutor Thanks a lot for this opportunity. I will be definitely in touch with you through mail. This is an honour to me. I am eagerly looking forward for this upcoming website and I can clearly see rather predict there will be exponential growth in the number of visits / likes to this website and above all millions of people will get benefit out of it, video lectures etc. I wish you all the success for this endeavour and your way of teaching is fabulous. A great work for the betterment of mankind and a great service to make the universal tool mathematics interesting and easy to understand. Thanks a lot.
God Bless you! This has been extremely helpful! Thank you so much!
7. From a common starting point on a circular path around a park,
five persons started moving in the clockwise direction with speeds
X1, X2, . . . , X5 meters per second, respectively. Suppose that the total
length of the circular path is 200 meters. Assume that X1, X2, . . . , X5
are independent and identically distributed as Uniform (0,2) variables,
and each person takes several laps around the park. If T denotes the
time for the first instance when two persons meet after starting, find
the expected value of T.
Sir can uhh solve this question plzz
Thank you, Professor Kumar!
thanks .. you just saved my exam..
Saved me, Thanks!
Awesome lecture Sir
Keep it up
Hi, thank you for the very elaborate and clear introduction. However, I have a question; how can I find the values of a and b whilst only given the k?
thank you so much, sir!
Served the purpose sir, Thanks.... :)
man i hate when teachers only show simple question until the exam and at exam boom something tricky and confusing like a) ...
8 does not fall in between -4 to 6. So should not the answer be 1. I understand the concept behind to calculate the area but here a value should have been taken between -4 to 6 to explain here.
What a beatiful explanation. Thank you.
Thanks for appreciation and your time.
Thank You ! Sir :)
Your the best
Thanks for appreciation
Hi , i have one game based on it it's called Robbet crash ,, can you decide this?
Thank you, I understand it now. :)
Thnk you sir
Hello, what if i have interval [2, a] and f(4) = 0.8? Could you shortly write how i should find a?
Hi, edwin. Nice to meet you
Regarding your qn:
Hello, what if i have interval [2, a] and f(4) = 0.8, how do I find a?
Solution:
(4 - 2) / a - 2 = 0.8,
2 / a - 2 = 0.8 / 1
Cross multiplying, we have:
0.8(a - 2) = 2 × 1 = 2
Subsequently, from multiplying both sides by 1.25,
We have:
a - 2 = 1.25 × 2 = 2.5
Therefore, a = 2 + 2.5 = 4.5
Hope this is helpful
@@aravindssingapore4327 What ever formula you used is for CDF right ?
Sir