If we add 100 ml of NaCl (sodium chloride) to 1000 ml of water (H2O), the total volume of the solution will not remain 1100 ml because the addition of NaCl will change the volume of the solution due to changes in density and other factors. However, assuming that the density of NaCl solution is the same as that of water, the volume of water in the solution can be calculated as follows: First, convert 100 ml of NaCl to its equivalent mass using the density of NaCl solution. The density of a 1 M NaCl solution is approximately 1.06 g/ml. Therefore, the mass of NaCl added is: Mass of NaCl = Volume x Density = 100 ml x 1.06 g/ml = 106 g Next, subtract the mass of NaCl added from the total mass of the solution to get the mass of water: Mass of water = Total mass - Mass of NaCl = 1000 ml x 1 g/ml - 106 g = 894 g Finally, divide the mass of water by the density of water to get the volume of water: Volume of water = Mass of water / Density of water = 894 g / 1 g/ml = 894 ml Therefore, the volume of water in the solution is approximately 894 ml.
If we add 100 ml of NaCl (sodium chloride) to 1000 ml of water (H2O), the total volume of the solution will not remain 1100 ml because the addition of NaCl will change the volume of the solution due to changes in density and other factors.
However, assuming that the density of NaCl solution is the same as that of water, the volume of water in the solution can be calculated as follows:
First, convert 100 ml of NaCl to its equivalent mass using the density of NaCl solution. The density of a 1 M NaCl solution is approximately 1.06 g/ml. Therefore, the mass of NaCl added is:
Mass of NaCl = Volume x Density = 100 ml x 1.06 g/ml = 106 g
Next, subtract the mass of NaCl added from the total mass of the solution to get the mass of water:
Mass of water = Total mass - Mass of NaCl = 1000 ml x 1 g/ml - 106 g = 894 g
Finally, divide the mass of water by the density of water to get the volume of water:
Volume of water = Mass of water / Density of water = 894 g / 1 g/ml = 894 ml
Therefore, the volume of water in the solution is approximately 894 ml.
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Well explained, thakyou sir
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thank you... i was always thinking how can water vapour be present in dry air?
Sir specific humidity ka temperature se kya relation hota h
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Specifc humidity,absulati humidity,relivetive humidity me kya kya difrence hai
I made all videos of relative absolute specific please search by topic name and alibaba online learning and watch your all dout will be clear
Thank you sir now I got it
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Water vapour in Dry air but the confusion comes when you explain the ratio with water vapour in Dry air and water vapour