Least Number of Unique Integers after K Removal - Leetcode 1481 - Python
HTML-код
- Опубликовано: 30 июн 2024
- 🚀 neetcode.io/ - A better way to prepare for Coding Interviews
🧑💼 LinkedIn: / navdeep-singh-3aaa14161
🐦 Twitter: / neetcode1
⭐ BLIND-75 PLAYLIST: • Two Sum - Leetcode 1 -...
Problem Link: leetcode.com/problems/least-n...
0:00 - Read the problem
0:22 - Drawing Explanation 1
6:33 - Coding Explanation 1
8:56 - Drawing Explanation 2
13:53 - Coding Explanation 2
leetcode 1481
#neetcode #leetcode #python
I used the bucket sort approach you taught us in Top K frequent elements. I'm going to analyze the time complexity of mine then watch your video but thanks for being such a great teacher. I learned (and will continue to learn) so much from you. I used to be so clueless. Thank youu
me too!
I love the fact that even if I am able to solve the question, I almost always get something useful from Neetcode's solution, somedays It is the optimized approach, and on the other it is better code quality.
so impressive, thanks a lot sir
Great video, thank you
I solved it using bucket sort too!!
Amazing
Today I am happy that I have solved this by myself🎉
congrarts
Seemed like a greedy and sorting problem
Can someone explain the logical mistake in my code
class Solution:
def findLeastNumOfUniqueInts(self, arr: List[int], k: int) -> int:
count = Counter(arr)
arr.sort(key=lambda x: count[x], reverse=True)
n = len(arr)
return len(set(arr[:n - k]))
please...!!
add arr.sort() before sorting by the count. This is because even though you sorted by count, the numbers with the same count can appear in any order. For instance, [1,1,2,2] could get sorted to [1,2,1,2] because 1 and 2 have the same count.
Thanks bro! U saved my streak
You could also do this -
arr.sort(key=lambda x: (count[x], x), reverse=True)
It will first sort by freq and then by value which will fix the order as well