DON'T MISS THIS Rate Law and Rate Constant Question
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- Опубликовано: 5 сен 2024
- If you are given a table where all the trials are completely different and don’t follow a pattern, don’t worry I’ll show you how to determine the rate law and rate constant. You will also learn how to figure out the rate constant units with ease!
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i cant believe you taught this in 3 minuetes so well and i sat in a classroom for 1.5 hours debating if i should change my major lol THANK YOU!!
hey if you have a real joy in solving and understanding your subjects , never ever even think of dropping it.
bruh i’m doing this as a sophomore in high school :(
@@chase4780 I’m in year 1 Uni and I’m doing this lol
@@chase4780 don't take it for granted. i feel like you hs teachers teach better than uni prof's
Holy -every cuss possible-, Melissa, I was just going to go from chemistry being my favourite subject to chemistry being my absolute nightmare until I came across your channel. I'm in love with the way you teach; it's so straightforward and easy to understand and the presentation is neat and really nice to look at.
Thank you so, so much. From now on I hope my chemistry will go better from here!
I been watching melissa since intro to chemistry, I am now in chem 102. Thank you for your videos they are extremely helpful.
You're so amazing at explaining it. You're presentation is satisfying, it keeps me focused and alert. Thank you!
Here I am in Chem 2, reunited with my trusty chem homegirl Melissa! You got me through Gen Chem & I thank you & RUclips for uniting us because I was struggling 😂
Everything you need to know for Kinetics is right here in my Kinetics Notes: melissa.help/kineticsnotes
Seriously this is a grade changer!
Never stop doing this you are so GREAT!!
very extremely helpful that you provided entire ratio so we could see where it came from
Yay! Happy to hear 😊
Chem 1, now Chem 2 your saving my life right now!!! THANK YOU AS ALWAYS!!!!!!!!#TeamMaribel
me too
A lot of effort has been put into this, and I really appreciate it. But what can we do in case there are no like values given among the reactant concentrations, i.e if the concentrations of each reactant used in each trial is different?
You use a variable something like “x” in place of where the concentration would be, then you do k= products/reactants (make sure to include rate order) and solve for x
MY LIFE SAVER THANK YOU 😭💗💗💗💗
soooo helpful! awesome work man, saving chem students everywhere!!
Thank you! Thank you! Thank you! 🥰🥰🥰
love this page! super informative and to the point. the way you organized your notes and explanation in such a condensed amount of time is amazing! appreciate it
You're awesome!!! Thanks, enormously! Your videos saved my day.
This is the best explanation I have seen!
What do we do if there aren't any concentrations that are the same on either side? What if we can't find y in the beginning?
Amazing explanation ma'am
It's important to note that she rounds all her values
THANK YOU OMG
Thank you so much for this video!!!!!! I appreciate the help!
Your videos have been awesome! I hope I pass tomorrow!
I passed! Thank you!
Yay!! Congratulations 🎉
Thanks So much mam from India
Hello Melissa🌹, I would like you to help me with this topic :
Chemical Kinetics
PLEASE
So this video is one of my Rate law videos which is part of Chemical Kinetics. I can also recommend other videos from different youtubers.
ruclips.net/video/irJ4ANrUXPI/видео.html
ruclips.net/video/2LMdj91x2HA/видео.html
so helpful! Thank you so much
I am a fan! Thanks alot
Ms.Maribel I tried it with the equation of trial 3 over trial 2 and it gave me x=0? should that even be possible?
I really like your way to video it's not boring and you clear everything thank you
Hi
In the previous video, why you did not use the same method and take the average ?
Because in the previous video they followed a pattern(the same numbers were found in 2 different trials for both x and y). Here, she found the same x value in a different trial but not the same y value, so they're not following a pattern. For this we take the average of all Ks
I also looked through your notes but I'm not sure which ones to purchase in order to get help with this concept
is there any other way to find the k value without finding the average as this method will be time consuming for me since we don't use calculators
i don't understand what the purpose of a "constant" is if it is changing from trial to trial, to where you have to take an average. that seems very un-constant-y to me.
Thanks so much love you
For 1st order reaction,did the titration value is coming decreased or increased
My best
Only if they can close colleges and stop taking our money for tuition and just let us learn on RUclips. It took me 3 min to understand what I have been reading for 2 days. Thank you for saving me 24 more hours of my life.
You are the best
required ALEKs we need videos how to do this on ALEKS as not to waste time on requirements of that program which is only 15% of my grade but takes hours
Hey is there any way to email questions to you without using twitter?? I don't have one but I really need help with The Clausius-Clapeyron Equation
Just emailed you back
why is it 7.7 x 10 raise to 5? i think its raise to 13?
yeah that is what i got too...
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I hope something like this does not come on MCAT
Women can really explain it 😮