Rate law calculations when one reactant is not held constant

[@goshiyaarab7693]

Thank you so much!!!!! I am about to write my chem exam in two hours and this is a savior!!!! helped me a lot, even my professor couldn't.

[@kirasmith461]

lifesaving method... one of the only videos on youtube that teaches it... thank you so much!!!!!!!!! Ps this video deserves wayyy more likes and views.

[@elliehague5278]

thank you, this was super simplified and easy to follow

[@madisonbingham7774]

thank you for your services :')

[@gcinangcongo3389]

thank you sooooo much.. am wriring my final chemistry exam tommorow ...this helped so much

[@leticiadeoliveirajustinole481]

Thank you so much for the great class

[@tamaradifc7566]

Nice...makes sense now 🙂

[@gaarasgf]

you are so wonderful

[@aileneroque8320]

Thank you so much!

[@roopamn9691]

Sir, how is m=1...did u cancel 4 and 4 sideways??

[@jamiecamp4014]

No, what I am saying is that 4=4 only if the second 4 is raised to the 1st power like this: 4=4^1. If we had a different problem where 16=4^m, m could only be 2 as 4 squared =16.

[@roopamn9691]

@@jamiecamp4014 Ok.... thank you sir

[@harshilshah9100]

ly bro

[@gil1374]

i got the ap exam tomorrow... thx