Ik everyone else is saying it but it’s just so true, you’re a wonderful teacher and sound like a wonderful person, and everyone deserves to have a Professor as good as you. You truly help everyone who sees your videos, thank you ☺️ This is coming from a student on the edge of a breakdown an hour before a test, Im feeling very grateful
Hi Charles - You've got this! Methodically think your way through each question on the test. You will do great! Thank you for the kind comment. It means a lot. Have a happy day:)
Hey it’s me again just letting you know that this class was absolute hell for me 😅 but I got through it and managed to pull a B+! Thank you so much, much love.
"Your videos are extremely clear and understandable, thank you very much. Also, love from Turkey. Today was our Ramadan Eid, I prayed for you too. May God bless you."
Hi Abdullah, thank you for your kindness! One of my daughters lived in Turkey (Istanbul) for 4 months in 2021. She was there over part of Ramadan. It was very informative for her. She loved the people. Thanks again! Sending love and prayers to you too!!
I realize this was posted two years ago, but thank you so much for this tutorial! My teacher uses a style where he teaches us the basics, and then throws us a quiz with a much more difficult problem that hasn’t been explained before, like this. This helped so much 💛
Thank you so much for posting this video. My textbook's explanation made my head spin with all the paragraphs but you summarized it beautifully in under 10 minutes. I feel a lot more prepared for my quiz now.
I just want to say I LOVE your videos so much. They have helped me through so many of my homework questions that I wouldn't have been able to figure out if it weren't for your videos! :)
Thank you so much! It was really hard to find a video where the equilibrium step had an intermediate with another reactant for the product so I was struggling to understand how to step up my equation to get a -1 exponent. I didn't give up and found your video! Thank you for giving a great example :)
you really saved me!! i have a test on this later and i didnt know how to do this very well. thank you for posting. its late but i hope you have a great day as well!!
Great video! I could tell you got flustered near the end as students were trying to break into your room! :) If it wasn't for them distracting you, this would have been a flawless explanation for this complex rate law question.
Thank you for this awesome explanation! I watched my professor's lecture video and read our chem book a few times but was still not getting it. So just to clarify, we set the forward rate and reverse rate equal to each other and we solve for the intermediate. Then, what we solve for the intermediate, we will plug that into the overall reaction rate.
Hi, this is a really helpful video! I just would like to ask, shouldn't it be K1[NO2Cl]=K-1[NO2][Cl]+K2[NO2Cl][Cl], since the second slow step is also consuming Cl.
@@OldSchoolChemistry Hi, thank you so much for your reply. I am still a little confused over the subject, since an article published in Chem Libretexts does indeed involve addition. If you have time, could you please look at it? The name of the article is here: 4.12: Steady-State Approximation. Thank you so so much
Hi madam.May i know how many elementary steps in the reaction? Is the reversible reaction considered as 1 elementary step? Since are there k1 and k-1 , i confuse if the reversible reaction has 1 or 2 elementary steps .anyway, thank you for the explanation in the videoo ,it helps me a alot!
Hi, so I am a student taking his MCAT soon. That has nothing to do with my question, I just wanted to announce it because... I am in literal hellfire. Anyways, I was wondering how the rate law is the law for the fast reaction mechanism and not for the slow step or even the overall step? I hope you understand what I am asking. Essentially, why find the rate law of the fast step only, or am I missing something? Thank you in advance.
Hi Just Your Average Cup of Joe: Great job preparing for the MCAT! It will be worth the pain:) You only find the fast step rate laws (both forward and reverse) if there are 2 conditions met. 1. The slow step comes after the fast step. And 2. The slow step includes an intermediate. If both conditions are met then you must solve for the intermediate by setting the forward and reverse fast step rate laws equal to each other. You then substitute that solution into the intermediate species in the slow step rate law. I hope that helps!
Hi UfC, pretend 4 students are simultaneously doing 4 different tasks. Everyone is released when each task for all 4 people is finished. Pretend the third person takes the longest to complete their task. Everyone gets to leave when person 3 is finished, the other 3 people sat and waited because they finished their tasks sooner. That is not a perfect analogy but at least gives you an idea of the rate determining step. You are correct, the time for the fast step is negligible in comparison to the slow step. I hope that helps ! Please subscribe if you haven’t already.😊
The k1 and k-1 just all become one k in the final rate law. They are simply each a number that combine to make one final number at the end. I should have written that k-1. Honestly, it does not matter as long as you write k on the final rate law. I hope that helps. Thanks Beatriz!
@@OldSchoolChemistry ok noted! thank you again for all your help and content that got me through the semester. i can't wait to start watching your ochem videos in a few weeks to prep for my class this fall!!!
HI potato man, you will only have one slow step, the slowest step. Everything else will be at least slightly faster. The slow step determines the overall rate of the reaction because the reaction cannot go faster than the slow step. I hope that helps!
Hi Lily, If given reaction mechanisms you count the total coefficients on the reactants for the reaction order in the forward direction. If you only have one reactant with a coefficient of 1 then the reaction order is first order for the forward direction. I hope that helps! Thanks:)
REPENT and be BORN AGAIN believing on Messiah Lord Jesus, nothing more important, today is the day of salvation and Jesus can show you the truth, its not blind faith you can see it for yourself if you truly seek like promised. John 3:3 unless a man be born again he cannot see the kingdom of God / Luke 13:3 unless you repent, you will all likewise perish ⚠️❤️⚠️❤️
Why can't someone like her be my Chem professor? I learn more in that 7 minutes than my three 2 hours long lectures.
I would love to have you on my class. I hope the rest of your term goes well!
What I really don’t understand is why “poor” teachers never consider watching videos like these to improve their own teaching.
WOW, THIS MADE IT SO CLEAR, WAS LOOKING FORWARDS FOR MORE EXAMPLES. THANK YOU. CURRENTLY TAKING GEN CHEM.
Ik everyone else is saying it but it’s just so true, you’re a wonderful teacher and sound like a wonderful person, and everyone deserves to have a Professor as good as you. You truly help everyone who sees your videos, thank you ☺️
This is coming from a student on the edge of a breakdown an hour before a test, Im feeling very grateful
Hi Charles - You've got this! Methodically think your way through each question on the test. You will do great!
Thank you for the kind comment. It means a lot. Have a happy day:)
Hey it’s me again just letting you know that this class was absolute hell for me 😅 but I got through it and managed to pull a B+! Thank you so much, much love.
I loved your energy, and the way you explain things simply makes everything clear. Thank you and looking forward to watching more of you videos.
Hi Asim, I’m so glad it was helpful. Please subscribe if you haven’t already. I hope chemistry goes well for you!😊
"Your videos are extremely clear and understandable, thank you very much. Also, love from Turkey. Today was our Ramadan Eid, I prayed for you too. May God bless you."
Hi Abdullah, thank you for your kindness! One of my daughters lived in Turkey (Istanbul) for 4 months in 2021. She was there over part of Ramadan. It was very informative for her. She loved the people. Thanks again! Sending love and prayers to you too!!
Truly impressive teaching style. Concise conceptual explanations to help understand why each step is possible. Fantastic.
Jason, thank you for that very kind and classy comment:)
Teaching at its finest. Thank you for taking the time to help us!
Edoardo, thank you for your kind words. I hope chemistry is a good experience for you’😊
I realize this was posted two years ago, but thank you so much for this tutorial! My teacher uses a style where he teaches us the basics, and then throws us a quiz with a much more difficult problem that hasn’t been explained before, like this. This helped so much 💛
Hi Art3mis. I am so glad it was helpful! I hope you class goes well:)
Thank you so much for posting this video. My textbook's explanation made my head spin with all the paragraphs but you summarized it beautifully in under 10 minutes. I feel a lot more prepared for my quiz now.
I am so glad:) That makes me very happy. Great job watching extra videos to learn. I am so proud of you!
Your an amazing person for this. You have no idea how many people will be helped by your videos.
Hi Maxwell, I appreciate that. That is my prayer. Thank you!!
Wow! That's amazing..This 7 minutes lecture is much better than my physical 1-2 hour classes..Thank you sooo much..💞
I am so glad it was helpful! Thank you for your comment:) !!
absolute life saver, I love how you put it in simple terms thank you so much!
Hi Allison, I am so glad it was helpful. Great job watching extra videos and working so hard. I am proud of you!
I just want to say I LOVE your videos so much. They have helped me through so many of my homework questions that I wouldn't have been able to figure out if it weren't for your videos! :)
Hi Cody, That makes me so happy. Thank you for letting me know. I’m proud of your extra work - way to go! I hope the rest of your class goes well!😊
I was really confused when my chem professor went over this during lecture a few days back, but this makes everything so clear! TYSM
Hi Westside Asians, this is a complex concept. I am SO glad you understand it now. Thank you for letting me know. God bless you!!
I have been looking for this everywhere online and finallyyyy came across this video. Thank you so much!
Hi Rueb, I’m so glad it was helpful. Great job putting in all this extra effort. It will pay off!😊
Oh this is so much better than this other video where he doesn't explain why stuff is ommitted or assumed, just ipse dixit.
Hi Origamigek, I am glad you think it was helpful. Thanks! I hope your class goes well:)
BEST VIDEO EVER!!! you earned a new subscriber!!! will be sharing this with my classmates :)) many thanks professor! love your enthusiasm ❤❤❤
Mariam, thank you so much! I am so pleased it was helpful and thank you very much for sharing:)
One of my best lecture everything is so clear to understand!! If you were in india then I surely choose as my chemistry teacher🙏🙏
Thank you so much! It was really hard to find a video where the equilibrium step had an intermediate with another reactant for the product so I was struggling to understand how to step up my equation to get a -1 exponent. I didn't give up and found your video! Thank you for giving a great example :)
Hi Charm, I am so glad it was helpful! I hope your class goes well. I am proud of you:)
ur energy is so nice, and your teaching is perfect
Reem, thank you for the positive feedback. I hope your class goes well!!
wow you made this so much simplier than my professor, U taught me the basics now i can do this myself. OMG thanks so much
Hi Tynecia, I am SO glad! I hope your class goes well. Please subscribe if you have not already. Thanks:)
you really saved me!! i have a test on this later and i didnt know how to do this very well. thank you for posting. its late but i hope you have a great day as well!!
Hi Lamice, I am so glad. I hope the rest of your class goes well. Good job working hard!!😊
Great video! I could tell you got flustered near the end as students were trying to break into your room! :) If it wasn't for them distracting you, this would have been a flawless explanation for this complex rate law question.
Thanks Michael;)
This was explained beautifully....... i was exhausted beacause i could not understand it now i know the concept..... Thank you ma'am💜💜💜💜💜
Hi Stawberry! I am so glad you feel good about it now. I am proud of your hard work! :)
thank you so much !!! i was really struggling with this but now i am concetually clear about this. this is going to help me in jee exam
Hi Meet Modh, that make me so happy! Thank you for letting me know. God bless you on your exam:)
Thank you so much for the video! I understood it way clearer than before!
Hi Linda, that makes me so happy!
oh my goodness you are like the chemistry version of professor leonard! This was so well explained!
Hi Saxy, I am glad you think so. Thank you for your comment! :)
Thank you for this awesome explanation! I watched my professor's lecture video and read our chem book a few times but was still not getting it.
So just to clarify, we set the forward rate and reverse rate equal to each other and we solve for the intermediate.
Then, what we solve for the intermediate, we will plug that into the overall reaction rate.
Perfect! You've got it. Good luck☺
For step 1, why did you say to write the overall equation when we dont use it?
thank you for all you help btw
Because it shows us what is not included in the final reaction - the intermediates and/or catalysts. Those cannot be in the final rate law. Thanks!
I am a Neet aspirants from India and this was helpful. Thank you mam
Hi Omkar, I am so glad. God bless you in your endeavors!
Omg thank you so much you explained this wayyy better than my professor did.
Hi Nala, I am so glad it was helpful! Thank you for letting me know. God bless you in your class:)
Thank you so munch, this channel is gonna be my go to for chemistry 2 this semester
Hi Jorge, I am so glad! I hope your class is terrific. You've got this😉
Thank you so much for this video! You explained this more clearly than my prof. This is the only vid that explained it the way my prof did!
Hi Lexia, I’m so glad it was useful. I hope your class goes well!!😊
@@OldSchoolChemistry I did well on my midterm exam because of this! Thank you again!!☺️
Awesome! I am so very proud of you. Well done🎉
Hi, this is a really helpful video! I just would like to ask, shouldn't it be K1[NO2Cl]=K-1[NO2][Cl]+K2[NO2Cl][Cl], since the second slow step is also consuming Cl.
Hi Mr. Rabbit, there is only multiplication and division in rate laws, no addition or subtraction. Thank you for your comment!
@@OldSchoolChemistry Hi, thank you so much for your reply. I am still a little confused over the subject, since an article published in Chem Libretexts does indeed involve addition. If you have time, could you please look at it? The name of the article is here: 4.12: Steady-State Approximation.
Thank you so so much
That is new to me! Thanks for the info so I can look into it.👍
Thank you very much for helping me to understand this problem
Hi Mohamed, I am so glad! Thank you for your comment:)
You are amazing!! Please don't stop posting videos.
Thank you Carolynn! It is a joy to teach chemistry to great students like you!!
Wow! You made everything easier than what it look in my slides,
thank you 💜💜
Hi Munira, I am so glad!! I hope it goes well for you:)
Why did we solve for Cl? I thought we did not include the intermediates into our overall rate law? Thank you!
Hi Ayleen, we solved for Cl so we could then SUBSTITUTE for Cl and remove it from the overall rate law. I hope that helps. Thanks!
keep making these videos, we need them
Hi Raghd, I’m glad you can use them. Please subscribe if you have not already. Good luck with your class!😊
Good explanations, appreciated.
Thanks Barask!! :)
thank you so much for this! also you look like courtney cox!
Hi Arcia, what a nice compliment. Thank you. I am glad the video was helpful;)
concept clear .....thanku so much
You saved me and my sister!!!! ❤️❤️❤️
Hi Deena, I am SO glad:) I hope the rest of your class goes well!
We should just play your videos in class. Thank you for everything
Hi Angel, That is a very gracious comment. Thank you!! I hope your class goes well;)
Love this video, good energy .
Thanks Jomar! I hope your class goes well😊
Thank you so much for this I learned so much
Hi the25viole, I am so glad! Thank you for your comment:)
Awesome video, really helps me.
Hi Xu, I am so glad! Thank you for your comment:)
Superb! Very well done! THANK YOU.
Hi Tomas, thank you for that kind comment. I am glad it was helpful! Good luck in your class:)
Merci beaucoup
Je t'en prie!
it was really cool thanks for explaining so well😇
Hi Sia, I am so glad it was helpful. Thank you for your comment!
Hi madam.May i know how many elementary steps in the reaction? Is the reversible reaction considered as 1 elementary step? Since are there k1 and k-1 , i confuse if the reversible reaction has 1 or 2 elementary steps .anyway, thank you for the explanation in the videoo ,it helps me a alot!
Hi Izy, it is considered one elementary step that is reversible and reaches equilibrium. I hope that helps! Thanks:)
Really Helpful! Thank you.
WOW!! This was such an amazing video!!! You are such a slay teacher :)
Hi Andre, I am so glad it was helpful. I hope your class goes well!
Hi, so I am a student taking his MCAT soon. That has nothing to do with my question, I just wanted to announce it because... I am in literal hellfire. Anyways, I was wondering how the rate law is the law for the fast reaction mechanism and not for the slow step or even the overall step? I hope you understand what I am asking. Essentially, why find the rate law of the fast step only, or am I missing something? Thank you in advance.
Hi Just Your Average Cup of Joe: Great job preparing for the MCAT! It will be worth the pain:) You only find the fast step rate laws (both forward and reverse) if there are 2 conditions met. 1. The slow step comes after the fast step. And 2. The slow step includes an intermediate. If both conditions are met then you must solve for the intermediate by setting the forward and reverse fast step rate laws equal to each other. You then substitute that solution into the intermediate species in the slow step rate law. I hope that helps!
Can u elaborate on why slow step is rate determining step ? Do we neglect the time consumed by fast step?
Hi UfC, pretend 4 students are simultaneously doing 4 different tasks. Everyone is released when each task for all 4 people is finished. Pretend the third person takes the longest to complete their task. Everyone gets to leave when person 3 is finished, the other 3 people sat and waited because they finished their tasks sooner. That is not a perfect analogy but at least gives you an idea of the rate determining step. You are correct, the time for the fast step is negligible in comparison to the slow step. I hope that helps ! Please subscribe if you haven’t already.😊
@@OldSchoolChemistry Thank you mam.
😊👍
Hello. What happened to that k constant at the bottom at 6:20 you didn't include it. Did it just disappear or ?(:
The k1 and k-1 just all become one k in the final rate law. They are simply each a number that combine to make one final number at the end. I should have written that k-1. Honestly, it does not matter as long as you write k on the final rate law. I hope that helps. Thanks Beatriz!
Thank you so much! This was really helpful!
Hi Yamna, I am so glad! I hope your class goes well:)
literally amazing
Hi Majd, I am so glad you think so! Thank you for your comment:)
Exam tomorrow!!! Thank you!
I hope it went well!!!
Just got out of it. There wasn’t a question about this LOL
Helped me a lot. Thank you 😃
Hi Sofia, I’m so glad. Please subscribe if you haven’t already. Good luck with your class!😊
this helped so much thank you!!
Hi Lina, I am so glad. I hope your class goes well. Please subscribe if you have not already. Thanks!
Thanks a lot, this really helped
Hi ARM_J, I am so glad! Please subscribe if you have already:) Thanks!
Can you be my professor?? Literally, this was such a helpful video TY!
Hi Lamia, I’m so glad it was helpful. I would love to have you in my class! 😊
wonderful and clear! thank you
Hi Jacqueline, I’m so glad. Thank you! I hope your class goes well 😊
How we can plot Langmuir Adsorption Isotherms and what data is necessary for that??
Hi Shafi, I am sorry I am not familiar with Langmuir Adsorption Isotherms! Good luck:)
Thank u for such a really nice explaination🥺💜
I hope your class goes well!!😊
@@OldSchoolChemistry thank u🥰 today i'll do my exam. It's about rx mechanism and catalyst. Wml🙏
🙏 💕
Thank you for all you do!!
Hi Leo, my pleasure. I hope your class goes well.😊
thank you
Just perfect!want you here in India💜.where you from mam?
Hi Payne, thank you for your comment! I would love to visit India. I am from the United States of America.💗 God bless you in your home!
@@OldSchoolChemistry thank you for keep eye on me.How can I touch with you personally if I have any doubt....?
@@payne7792 You can leave a comment in RUclips. Thanks!
@@OldSchoolChemistry okay thank you mam!
Hi Payne, I’m glad this was helpful. I’m in the USA. Grinds to you in beautiful India!
Very helpful ✊🏿
Thank Mulima. Please subscribe if you have not already. Have a great day!😊
if the rate determining step is the second reaction, will the first fast reaction always be in equilibrium like this?
Hi Tess! It is nice to hear from you again. Yes! The fast step preceding the slow step is always in equilibrium. Thanks😊
@@OldSchoolChemistry ok noted! thank you again for all your help and content that got me through the semester. i can't wait to start watching your ochem videos in a few weeks to prep for my class this fall!!!
I’m so proud of your hard work!!
What if you have two slow steps?
HI potato man, you will only have one slow step, the slowest step. Everything else will be at least slightly faster. The slow step determines the overall rate of the reaction because the reaction cannot go faster than the slow step. I hope that helps!
How do you know if its 1st order, 2nd order, etc, if it is not given?
Hi Lily, If given reaction mechanisms you count the total coefficients on the reactants for the reaction order in the forward direction. If you only have one reactant with a coefficient of 1 then the reaction order is first order for the forward direction. I hope that helps! Thanks:)
Thank you very much.
You're welcome.💕 I hope your class goes well!😊
THANK YOU SO MUCH
Hi dieah - you are welcome. Thanks for watching:)
Thank you so much for this 😭
Hi Charis, You are so welcome! I hope your class goes well:)
you just saved me
Hi Reshmahakani, I am so glad it was so helpful! :)
Fantastic. Thank you
You’re welcome:) I hope your class goes well!
i love you. thank youuuuu
Wow! Thank you!!!
Hi Jenni, thanks for your comment! Please subscribe if you have not already. Thanks!!
THANK U 💜💜💜
You are so welcome:)🙂
I want to give you a hug
Hi Mackenzie, I am so glad it was helpful. I am sending a hug and smiles:)
God bless youuu!!! Thankss
Hi Sanam, You are welcome. God bless you too:) Thank you!
I can't help but notice that professor looks like Courtney Cox from friends
Hi Harikesh, that is a kind comment. Thank you. I hope your chemistry class goes well:)
*screams internally*
I know - there is a lot to digest in this. Go over it slowly, practice, and make it make sense in your mind. Good luck!
i love you
REPENT and be BORN AGAIN believing on Messiah Lord Jesus, nothing more important, today is the day of salvation and Jesus can show you the truth, its not blind faith you can see it for yourself if you truly seek like promised. John 3:3 unless a man be born again he cannot see the kingdom of God / Luke 13:3 unless you repent, you will all likewise perish ⚠️❤️⚠️❤️
Hi Bisrat, I’m a believer and love Jesus.💕
@@OldSchoolChemistry Amen! 🙏 ❤️ ‼️‼️