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why it is sin^2 but not sin*cos, are not x = r.cos and y= r.sin?
Thank you soooo much for this video!!!! It really helped me : )
why did u substract at the end when u wrote formula for ixx to be iab+A*(distance)^2?? i got confused
we are trying to find iab not ixx, therefore it got reversed haha😂
Well taught 👏 ❤
Parallel axis theorem would be Ixx=Iab + ah2
No, actually I ab = Ixx + ah^2. Phir vo shift hoga Lhs se
Sir, determine by direct integration the moment of inertia of a semicircular area with respect to their centroidal axis?Iski solve keya isbala hain??
No
D=2r/pi hota hai na??
Issay pehlay circle wali b bahut achi thi
Acha. Bhai
Thank you sir
Welcome 🙏
Sir in last calculation of {(π/128)-(1/π*18)=0.0068590.11 is not coming please explain
Multiply with 16 Bcz answer is given in radius
The answer always will be in minus even with R or D
4r/3pi kaise nikale??
Minus kyu Kiya last me??
Kis jgh bhai
@@TECHNICALCLASSES_TC last me parallel axis theorem me
Okay bhai let me check out.
Tnx
Welcome ramya😊
End may + likha hua hai upar or subtract kr dia bhai aapnay
Ok
how y=4R/3pi?
I'm already upload video for centroid of semi circular body
My doubt too
5:38 how ?
Same dought
That you can find when you are finding centroid of a semicircle
What is Iyy
Moment of inertia about yy axis
@@TECHNICALCLASSES_TC what it's formula?
Zabardast bro exam hai mera 2 ko or sab clear ho gya.
Thank you bhai
why it is sin^2 but not sin*cos, are not x = r.cos and y= r.sin?
Thank you soooo much for this video!!!! It really helped me : )
why did u substract at the end when u wrote formula for ixx to be iab+A*(distance)^2?? i got confused
we are trying to find iab not ixx, therefore it got reversed haha😂
Well taught 👏 ❤
Parallel axis theorem would be Ixx=Iab + ah2
No, actually I ab = Ixx + ah^2. Phir vo shift hoga Lhs se
Sir, determine by direct integration the moment of inertia of a semicircular area with respect to their centroidal axis?
Iski solve keya isbala hain??
No
D=2r/pi hota hai na??
Issay pehlay circle wali b bahut achi thi
Acha. Bhai
Thank you sir
Welcome 🙏
Sir in last calculation of {(π/128)-(1/π*18)=0.006859
0.11 is not coming please explain
Multiply with 16
Bcz answer is given in radius
The answer always will be in minus even with R or D
4r/3pi kaise nikale??
Minus kyu Kiya last me??
Kis jgh bhai
@@TECHNICALCLASSES_TC last me parallel axis theorem me
Okay bhai let me check out.
Tnx
Welcome ramya😊
End may + likha hua hai upar or subtract kr dia bhai aapnay
Ok
how y=4R/3pi?
I'm already upload video for centroid of semi circular body
My doubt too
5:38 how ?
Same dought
That you can find when you are finding centroid of a semicircle
What is Iyy
Moment of inertia about yy axis
@@TECHNICALCLASSES_TC what it's formula?
Zabardast bro exam hai mera 2 ko or sab clear ho gya.
Thank you bhai