Math Behind Qubit | Quantum Computing Chapter 03

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  • Опубликовано: 1 фев 2025

Комментарии • 11

  • @legitwhiffs07
    @legitwhiffs07 Месяц назад +4

    Doing Gr8 Job the awareness regarding Quantum Computing is very less in India and it needs to be spread. I believe in next upcoming decade and two, QC is gonna be the next Superpower and Countries and their big tech companies are gonna compete for building advance Quantum Computers. Super excited to see QC

  • @artwizard848
    @artwizard848 Месяц назад +5

    @rajan chopra
    Firstly alot of love from all of us (the science freaks😅)
    Bro i have a doubt(not related to this topic)🖐️
    In the derivation of hamiltonian equation from Schrödinger's equation the partial double differentiation is written as in the form of laplacian operator {∆}
    But,while differentiating at the second last step where the hamiltonian operator is separated as psi is taken common out...how on earth is it possible to seperate a operator from it's operand
    For ex:- 5*log10+4*10≠(5*log+4)10 here we can't common out 10 from log without solving the Operation of 'log'. So how in the derivation psi is taken common out without solving the laplascian operator 😢
    I Hope u'll reply 🙌

    • @mohitpaul1206
      @mohitpaul1206 8 дней назад +2

      @artwizard848 I randomly came across your comment on a randomly recommended RUclips video on my YT. But it's a question worth replying and I remember asking this question myself once. So here's some explanation that might help: first you must understand what an operator IS actually, what is the purpose and what it maps from and what it maps to. In abstract maths, Operators are defined on maps or a manifold and but you don't need to go that deeper - since your question will be mainly answered by what is the nature of the operator. Whether it's linear or nonlinear. To put it with an example: in Hamiltonian (read Schrödinger's Equation) in the position basis, we can separate the operator due to its linear nature. The nature of differential operator on some manifold, is generally linear. However, the same is not true for log (your counter example), the log operator comes from the exponent maps, the nature of which is nonlinear. Thus you're right, you cannot separate log from the operand. To further extend on this, you CANNOT separate operand in the Nonlinear Schrödinger's Equation (often used in Photonics and Bose Einstein Condensate). Hope that clears it, kudos to the good question. Keep asking more!

  • @SUBH__098
    @SUBH__098 8 дней назад

    Pls continue this series ❤

  • @Dhruvktj
    @Dhruvktj Месяц назад +1

    Bhaiya please continue this series,👏 please ❤

  • @SujanDas-zb7fj
    @SujanDas-zb7fj 11 дней назад

    Please complete the series.

  • @studymany
    @studymany Месяц назад +2

    Sir mujhe ak bat btao ki ham quntom computer ko kese btayenge ki hme usse do numbers ka addition karwana h ya multiplication 🤔🤔

  • @adi_justlive
    @adi_justlive Месяц назад +2

    Bhai koi book Jo iske sath follow kar sakte hai

  • @G4B-w3h
    @G4B-w3h Месяц назад +4

    firstttttttt
    🫶💕💕💕

  • @thelogicless9040
    @thelogicless9040 Месяц назад +1

    Graphics use karo aise video kam interactive hoti h. Intrest kam ata h log nai dekhenge aise

  • @animegod-agod
    @animegod-agod 6 дней назад

    New video