No ncees pe hb 1.1, p. xx to reference. Cody is right -- pure logic and arithmetic. Manual has info on axles but in an unrelated context. Got false solution at D. . One of the 1st keys here is to understand what an axle is and how different vehicles have different axle counts. . 2nd key is to setup 2 eqns/2 unknowns. .. 2X + 5Y = 1067 .. -0.15X + 0.85Y = 0 . 3rd is to make a 2x2 matrix and have your machine solve it. Like so: X Y K 2 5 1067 -0.15 0.85 0 Thus X= 370.18, Y=65.33 . 4th is to add up the # cars and # trucks. X + Y= 435.51 vehicles. Ans "C".
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I don't think that much calculation is needed. If n is the total number of vehicles, then 2*0.85n + 5*0.15n = 1067 would provide the value of n as 435
No ncees pe hb 1.1, p. xx to reference. Cody is right -- pure logic and arithmetic. Manual has info on axles but in an unrelated context.
Got false solution at D.
. One of the 1st keys here is to understand what an axle is and how different vehicles have different axle counts.
. 2nd key is to setup 2 eqns/2 unknowns.
.. 2X + 5Y = 1067
.. -0.15X + 0.85Y = 0
. 3rd is to make a 2x2 matrix and have your machine solve it. Like so:
X Y K
2 5 1067
-0.15 0.85 0
Thus X= 370.18, Y=65.33
. 4th is to add up the # cars and # trucks. X + Y= 435.51 vehicles. Ans "C".
Trail and error method might be simpler - just a thought
that's what I did