CN | IP address Subnetting Supernetting | Supernetting or Aggregation | Ravindrababu Ravula
HTML-код
- Опубликовано: 5 окт 2024
- For Course Registration Visit: ravindrababura...
. For Any Queries, You can contact RBR on LinkedIn: / ravindrababu-ravula
Telegram: t.me/ravindrab...
Instagram: / ravindrababu_ravula_rbr
For Full Computer Networks Playlist: • Computer Networks - GA... In this video Supernetting or aggregation is discussed in detail
![Tee Grizzley - Robbery 8 [Official Video]](http://i.ytimg.com/vi/34_vkNV6wrU/mqdefault.jpg)
Mind Blowing Teaching . Never seen such a soft CS Teacher
One of the best instructors ever. God bless you!
one of the best subnetting class on youtube
Man you're a good teacher - I've used your videos for about 3 to 4 subjects so far, awesome work !
sir, thanku very much your lectures are very helpful. i m student of IT . toc n compiler are not core subjects of mine........but the way u r teaching is wonderful............Thank u again........
very comprehensive lecture. Thank you very much it helped a lot. Keep up the good Work..
guys for all who have a doubt a 24:50 about how ip addresses are contigous, read this explanation
You have 25 bits for the Network ID. (Actually the range of hosts for that particular network is contigous)
100.1.2.0/25 's range is 100.1.2.00000000 to 100.1.2.01111111 and
100.1.2.128/25's range is 100.1.2.10000000 to 100.1.2.11111111. You can observe that both are contiguous
yes its pretty obvious
this helped thanks :)
You are a True teacher Sir.....
Awesome work..
Excellent clarity of content beautifully presented
Very nice way of teaching with proper voice modulation... Thank You Sir
a lots of thanks to you sir, no teacher teach these things so much clearly.
It is very helpful . Keep the good work !!
'Till now we have seen' that u r the best
Simply Awesome Sir... Drauncharya of GATE (Y)
Last example is not clear...about contigous 24:50
Great explanation!!! Thanks from Brazil
Thanks a lot mr.Ravula it was helpful
Thank you so much. I've been struggling with this
Hey,
Thanks for the Videos.Please post some more videos on protocols ,IP etc it really helps !
Nicely explained. Thank You
Sincerely appreciate all the effort you put in these high quality videos. People like you make the world a better place :)
Sir why you have deleted new videoo...It was really helpful for study from new videoos.please upload that videos which you have deleted.
Great great explanation 👏👏
Thank you dear , Very well explained lecture....
Excellent Tutorial,Thx~
Thank you sir for this video
Awesome video sir, was struggling with this topic... tysm
awesome sir.. thanks alot .. i was gives my full day to learn subneting but after watch your this video finally i got it what is subneting and how i can do subneting .. thanks ones again..
Actually it is supernetting..not subnetting...
very helpful this...
im confused with my teachers instruction. what if we used 200.200.201.0/24 on router
then 200.200.200.0/24 on pc
the difficult part is some of the ip overlaps
Thank You sir, Very informative and helpful video
Awesome lecture. I have a doubt though, how is 100.1.2.0 and 100.1.2.128 contiguous?? Please help
You have 25 bits for the Network ID.
100.1.2.0/25 's range is 100.1.2.00000000 to 100.1.2.01111111 and
100.1.2.128/25's range is 100.1.2.10000000 to 100.1.2.11111111. You can observe that both are contiguous
Thanks Sir....thanks a lot...
@19:20 @Ravindrababu Ravula Sir, can you kindly provide us references from any standard research/university resources regarding the rules/constraints as discussed here? I am having a hard time in just believing you blindly. Couldn't find such statements in Tanenbaum :(
Really superb. Thanks much..
Thank you so much sir it is very useful to me sir
Thank you so much
so nice .. stay blessed,,
super cool
how that and operation is performed
sir I have a question.....in the last example 100.1.2.128/26 and 100.1.2.192/26 y cant the supernet value be 100.1.2.128/26 instead of 100.1.2.128/25 Did u do it for the sole purpose of getting into the same size network as that of the 100.1.2.0/25....and then y the supernet value of 100.1.2.0/25 and 100.1.2.128/25 as 100.1.2.0/25 instead of 100.1.2.0/24
Size of the network depends on the host id part of the IP address. In the last example, he merged the two networks of size 2^7 so we got new supernet of size 2^8.(8 is the host ID part and remaining bits are 25 that is network ID).
so now we can merge two networks of size 2^8 (the network id of both networks are 25).
I can not write the whole explanation, I hope it will help you understand what point you were missing.
Here first you have aggregate 100.1.2.128/26 and 100.1.2.192/26. Then you have aggregate resulting 100.1.2.128/25 and 100.1.2.0/25 into 100.1.2.0/24.My question is how many entries there will be in the routing table ? only the last one ?
Since we are combining the networks the entries in routing table will increase. so 254 entries in the routing table for the n/w
Could supernetmask for last example be 255.255.255.0?
at 26:47 How can that three networks are contiguous 100.1.2.0, 100.1.2.128, 100.1.2.192?
these are network ids representing networks containing 128, 64, 64 addresses respectively
Thanks a ton sir. I have a question regarding subnetting. If we have to subnet a given network (10.10.0.0/24), into at least 4 networks of 32 Addresses and 2 networks of at least 64 Addresses, will it always be a network with /24 or it can be something else also like 10.10.0.0/23, 10.10.0.0/25 or 10.10.0.0/26
it will be 10.10.0.0/27 , 10.10.0.32/27, 10.10.0.64/27, 10.10.0.96/27, and 10.10.0.128/26 AND 10.10.0.192/26
With Class C 10.10.0.0/24, only have 254 host addresses. With 6 subnets will lose 10 more host addresses. So can't be done practically. Need 10.10.0.0/23, for example, to start with
How do you find out the size of a network?
Kudos to you ,sir
15:40, it is not supernet id actually it is network id.
its supernet id genius.
@@kipa_chu so we have to give a network id to router.please help me with it.
Thank you! This was very helpful! :)
Excellent lecture!!!!!!
thank you sir
Sir if we have 7 IP addresses given with mask /24 how can we check the 3rd rule because the total size =7*2^8 which is equal to 1792 and it can taken as bits ??...like in your 1st example u take 4*2^8 which is equal to 2^10 so we check last 10 bits of 1st IP is divisible by 2^10 or not.. So how can we do it for 7*2^8
Before going to 3 rd rule 2 nd rule is already failed...
(Because rule 2: all have same size & size of all n/w's must be in power of 2 .)
And
Here total N/w s =7 which are not in power of 2....
hi can you please post a video of supernetting of class B address with different subnet?
Sir when will remaining lectures of CN will get uploaded
Day after tomorrow
Given a network of 10.10.0.0/24, subnet the network into at least 4 networks of 32 Addresses and 2 networks of at least 64 Addresses.
can anyone please help me with this ... i am not getting how to do this....
It is not possible. Either CIDR should be /23. You want 256 hosts and 6 subnets.
Excellent !!!!!!!!
@14:48 confused me with the IP address adding into the SNM. I still don't know what you mean.
AND OPERATION perform krna h ... ADD nh :)
15:00 how to add IP and subnet ??
Summarize the following into 1 single summary route
192.168.68.0/24
192.168.96.0/24
192.168.80.0/24
my question is how we will find the block size here without converting into binary option, here they didn't mentioned how many networks we are going to summarize right? so how we will find the block size?
block size will be 32-24=8 then 2^8
thank u for the reply..after revising the video i understand ..
192.168.64.0/18
@@retsvus 64 is not even in the list of given networks.
Check @29:20. I think supernetting is not possible for 3 networks. For the block size, each block is of size 2^8. But, on total we have 3 times 2^8. i.e. 2^ 24
In the last question how the address are contiguous? And if the are contiguous then the size of network should be 2^7*2^7=2^14, but you are doing size is 2^8..how
uttam kumar it is not 2^7*2^7. it is 2^7+2^7=2^8
can you explain me how the size is 2^7 for each?
@@subbulekshmi6424 This is Binary calculations. 2 times 2^7 means
(2^1)*(2^7) = 2^(7+1) = 2^8
Sir, I have little confusion at
15:10 as 200.1.0.0 is supernet mask as you have mentioned but as I have learnt from your lactures it should be supernet ID can you please clarify that
Same doubt bro.
I guess he told it by mistake.
Thank you. How can I join you in teaching. I like your teaching skills.
marry him, simple!
sir can u tell me how is the size 2^8?
32-24=8 so 2^8
thank you
Thanks sir
Thank you
sir i need switching with full lecture
U shud be more clear regarding divisibles
How does 2⁷+2⁷= 2⁸?
128 + 128 = 256. What's the problem here?
thanks
sir,the last problem discussed is wrong...isn't it?
How are they contiguous? 0, 128 and 192?
yes they are contiguous...
@@xof8256 yes they are contiguous...
You are amazing :) .... thank u soo much
Is it 200 is your lucky no sir? ☺️🤔
Any thing But IT industry need like you people sir. Who not only teach but also inspire to other person to learn and do the same. Thank you very much.
100.1.2.0
100.1.2.128
100.1.2.192
how all dey r contigous .. meanz how dey r sharing common border ???
previous it waz said dat in continous manner like .11 ,, .12,, 13 !!@26:04...
It is contiguous. Remeber the VLSM example for CIDR. Something like that.
here contiguous means there must not be any gaps between blocks ..The 1st IP of the next network is the (last IP of previous network+1)..
Means last IP of 100.1.2.128/26 is 100.1.2.191
and first IP of 100.1.2.192/26 is 100.1.2.192..
and also last IP of 100.1.2.0/25 is 100.1.2.127
so they are contiguous
i was struggling with the same confusion....thanks...
+Koustabh Chatterjee Suppose that second id is 100.1.2.193/26 . Are they still contiguous ?
+Nazmus Takib no, then it will not be contiguous :)
BINOD
.
.
.
🤣🤣
I cannot understand one word you are saying???? English bro!