Hey people, note this: * Any 3 *all different* numbers. Including 0. * After the first substraction: ignore the negative (-) and consider any two digit number as a three digit number filling with a zero. Example 1: 506-605=-99 change -99 to 099. Its reverse is 990. Finally: 099+990=1089. Example 2: 012-210=-198. change it to 198. Finally: 198+891=1089. Have fun! :)
@@armlatv2260 that's exactly what I was wondering about. Matter fact I chose 666 when my brother watched this video and tried to do the trick on me. Well now here i am in the comments trying to find what u do it someone pics 111 222 ...
It's really a stretch to make it work when the difference is 99. For example 231-132=99. You'd need to see the 99 as 099, then reverse to 990. Adding back 990 to 99 does get you 1089.
Represent the number as: 1*X + 10*Y + 100*Z. The inverse would be: 1*Z + 10*Y + 100*X. Subtract the inverse and get: 99*Z - 99*X. Also can be written as: 99*(Z-X). Lets replace (Z-X) with N: 99*N. Lets rewrite as: 100*N - N. Lets rewrite as 100*(N-1) + 100 - N. Lets rewrite as 100*(N-1) + 90 + (10-N). Thus the inverse is: 100*(10-N) + 90 + (N-1). Add these together and we get: 99*N + 1000 - 100*N + 90 + N - 1. Squish together and get: 1000 + 90 - 1 = 1089 QED
If abc is the 3 different digit number we can write it algebraically as 100a+10b+c Then the reverse digit number will be 100c+10b+a Now subtract the reverse digit number from original one (100a+10b+c)-(100c+10b+a) The new number will be (100-1)a+(10-10)b+(1-100)c Or 99a-99c Or *99(a-c)* ..... (1) Since a and c are single digit numbers i.e a, b belongs [0,1,2,3,4,5,6,7,8,9] So (a-c) will also be a single digit number. [But a≠0 because abc is a 3 digit number] Henc (a-c) belongs to [1,2,3,4,5,6,7,8,9] _We excluded 0 because a-c=0 if and only if a=c And we know that a,b and c are three different digits. a≠c Now lets substitute the other possible values of (a-c) one by one For *a-c=1* (1)=> 99×1=99 Now add reverse 99+99=198 Add reverse digit number again 198+891=1089 For *a-c=2* (1)=> 99×2=198 Now add reversed digits 198+891=1089 For *a-c=3* (1)=> 99×3=297 Now add reversed digits 297+792=1089 For *a-c=4* (1)=> 99×4=396 Now add reversed digits 396+693=1089 For *a-c=5* (1)=> 99×5=495 Now add reversed digits 495+594=1089 For *a-c=6* (1)=> 99×6=594 Now add reversed digits 594+495=1089 For *a-c=7* (1)=> 99×7=693 Now add reversed digits 693+396=1089 For *a-c=8* (1)=> 99×8=792 Now add reversed digits 792+297=1089 For *a-c=9* (1)=> 99×9=891 Now add reversed digits 891+198=1089 Similarly for negative values of (a-c) Ignore the negative we will conclude with the same answers. I have tried to verify it by putting all possible values. I will be more than grateful if you share your kind opinion or correction.
It was sweet and concise until the last part, thanks a lot for the explanation. (but...) (let d = a-c) 99(d)+(inverted_99(d)_) = 99(11) = 1089 I am having a hard time proving that last part but it has to do with prime numbers added to 11. For 2, 2+9 and 9+2, for 3, 3+8 and 8+3, 5 goes with 6, 7 goes with 4. 1 is not a prime number and doesn't go with anything hence i am having a hard time finding the rule that would render the last part of your reasoning slick and concise like the first part was... 1089 is 33 squared, (11)(99), (11)(11)(3)(3). I know the answer is somewhere in this haystack, someone please find my needle lol. Thanks
proof: it starts from the fact that the difference of 2 3 digit numbers following the mentioned rule will always be a product of 99 and any number from 1 to 9(which can be taken as x) and the subsequent result can be represented as a 3 digit number as mentioned below: 100(x-1) +10×9+(10-x) the result when added with its reverse that is 100 (10-x)+ 10×9+(x-1) will exactly give 1089 always after the cancelation of x(the initial variable we took that is from 1 to 9, which is formed from the difference of the first and the last digit of the 3 digit number we initially assumed)
how the 3 digit number representation equation was derived: suppose the initial number we took is 100x +10y+z, the difference with its reverse would be 100x+ 10y +z-100z -10y -x= 99x-99z=99(x-z) x-z will always be a variable from 1 to 9, and can be taken as another variable r so the equation now is 99r=100r-r in order to get the number into 3 digit equation format by removing the last negative digital we can carry 1 from the first digit of the 3 digit number and then the second digit and write it as 100(r-1)+10×9+(10-r) now the 3rd digit will always be positive as r is a number from 1 to 9..hence the equation 100(x-1)+10×9+(10-x) is derived
That's so awesome..thank you....unless it's not. Ramanujam taxi number(story) is 1729 which is the smallest number which can be expressed as the sum of two different cubes in two different ways.
When I was 8 I discovered that you can take any number larger than 9 and up to infinity and subtract its opposite and that number is ALWAYS perfectly divisible by 9, or 3 because 3 squared is obviously 9
The claim should be that the difference of any number (greater than 9 and not equal to its mirrored version) and its mirrored version, is always divisible by 9. Essentially, it all comes down to this: If a>0; x, y ≥ 0; x>y and a, x, y are all integers: D = a * (10 ^ x) - a * (10 ^ y) = = a * ((10 ^ x) - (10 ^ y)) = a * M D is divisible by 9 if M is also divisible by 9. M is always divisible by 9 for the same reason the differences 1000-10=990 and 100-1=99 are all divisible by 9.
@@m1n7o if after subtracting with the reverse number leaves you with two digit than you put 0 For e.g. 152-251= -99 Now you have to put 0 after 99 So it makes 990+099= 1089 Hope I was clear enough 😂😅
I paint cars for one job, but I work in a bar for my second job and this simple thing has blown a few minds. It’s fun to see the reaction on new customers. It’s a great way to generate fun conversation and I don’t know how many will start watching your channel, but the comments I get have been fantastic. I’ve been using a few card tricks and it’s brought in new people as well. Thank you so much for teaching me. Magic brings the inner child out in everyone. Thank you so much again! I do know one card trick, that you may know, and if I get my internet connection back up and running after my home improvements I’ll make you a video to show you. I can’t wait. Hopefully you won’t know it, but I’m sure you do. Unfortunately I never new it’s name though. I’ll practice it more so it will be as seamless as possible like your videos. Take care❤
Very nice, this will score many free drinks at the pub for me here in Ireland. Thanks for always offering easy doable tips and tricks. Love the channel
I don't get many free drinks but I do know how to get the cheapest drinks. You see it's this magic power I have, I can drink your drink and then make it appear back in the glass. Don't believe me? Well, I don't wanna take all your money, I'm that confident, so bet you 10c i can do it. *Drink is drunk* *Weird mystic hand gestures and mumbling* Ah well, guess it didn't work, here's your 10c If you do it right whoever you got will start laughing and probably send all his mates round to you as well.
453 - 354 = 99 to in some cases where there is a difference of 1 between first and last digit you would have to add 0 to the first result to get 1089 but it will still work just add extra step by saying: " Add 0 in the end if you got a two digit result".
the number only needs to be not symmetrical. Two of the same are fine as long as they are something like 221 oder 667. Only problem is something like 121 or 444. edit: even 998 is fine as long you treat the result of { 998 - 899 = 99 } as a three digit number of 099. 099 + 990 = 1089
Mathematical explanation: Let's say that the hundreds digit is greater than the units digit (if its the other way you will need to negate the result which is basically like negating the first operation and -(x-y)=y-x so we can continue as if it was this way to begin with) and let's call the hundreds digit "a" and the units digit "b" so a>b. I will also represent the numbers with their digits divided by commas so I would be able to represent digits with algebraic expressions (132=1,3,2) Step #1: subtract the reverse: Let's separate the subtraction into steps: A. Subtract the middle digit: the middle digit will be subtracted by itself so it does not matter. We are left with a,0,b - b,0,a B: Subtract the hundreds digit: as a>b we know that the result will only affect the hundreds digit. Now we are left with (a-b),0,b - a C: Subtract the units digit: as b
198 is also a magic number, connected to same rule. If we choose a 3 digits ending with 0, by subtracting reverse, they get 99, by adding reverse it becomes 198. Eg: 120 120-021 =99 99 +99 =180.
Nothing magic, sacred geometry..space,time and matter does end to 9... Just count the single digits ..like 360 degree is 9, 45, etc 3600 sec in hour..😊
90s baby here. When the gameboy got boring i used to play with a calculator and discovered this when i was a wee kid. I thought i was a genius xD showed everyone in school the next day
Such a delight sitting here here india and want to learn a little 🎉 fun skill to pass your my only way to learn really liked your videos and my favourige vedio of uours is sybic cut which was done 7 years ago !!!!!!!!! But nonethless you look toooo beautiful thank you man😅❤
*Let three digit number:* xyz= 100x +10y+ z *Reverse:* zyx = 100z + 10y + x *Subtract:* xyz-zyx = a9b After subtraction, the result is a9b.. where Middle digit is always 9 and sum of a and b is always 9. *Reverse again:* b9a *Add:* a9b + b9a = (a+b)/18/(a+b) We know a+b = 9 Let's put the values: 9/18/9.. Carry 1 of 18 to hundredth place, so it becomes 10/8/9.. i.e. 1089. No it's not magic.. simple maths...
Have them turn to a book that you provide them that has at least 109 pages … have them go down 8 lines and have them read the first word. Then reveal that word magically on a piece of paper you prepared earlier. Makes this trick a little more astonishing … as long as you do it only once for the person :)
Here's why it happens: 1. **Three-Digit Number**: Consider any three-digit number where the first and last digits differ by at least two. Let's call it ABC, where A, B, and C are its digits. 2. **Reversing and Subtracting**: When you reverse this number, you get CBA. Subtracting CBA from ABC (assuming A is greater than C) gives a new number. This subtraction aligns with the form (100A + 10B + C) - (100C + 10B + A) = 99A - 99C. 3. **Result of Subtraction**: Simplifying 99A - 99C, you get 99(A - C). Since A and C are at least two digits apart, the minimum value for (A - C) is 2 (e.g., if A is 3 and C is 1), and the maximum is 9 (e.g., if A is 9 and C is 0). This results in a number that is two digits long, and its first digit is always 9. 4. **Intermediate Number Characteristics**: The intermediate number (after subtraction but before adding the reverse) is always of the form 9X9, where X is a digit. This is because the hundreds and units place will always be 9 due to the subtraction process described above. 5. **Reversing the Intermediate Number**: When you reverse this number, it becomes 9X9 again, as reversing doesn't change the position of the digits due to its symmetry. 6. **Final Sum**: Adding the intermediate number and its reverse, both being 9X9, will always lead to 1089. This is because 900 + 90 + 9 equals 999, and adding it to another 999 (since the reverse is the same) results in 1089. In summary, the specific properties of base-10 subtraction and the constraints placed on the original number (three digits, first and last digits differ by at least two) ensure that this trick works, leading to the consistent result of 1089.
@@harshitgaming9962 The reverse of 2002 is itself, and not a different number (with the emphasis on ‘a different number’); hence it doesn’t count. Any number could divide itself, so what! We are talking about the nontrivial reverse divisors. Palindromic numbers have reflectional symmetry across the vertical axis.
The phenomenon you're describing with the number 1089 is a well-known mathematical trick. It works with most three-digit numbers, as long as the first and last digits differ by at least two. Here's how it works: Choose any three-digit number where the digits are not all the same (like 651). Reverse the digits to form a new number (156 from 651). Subtract the smaller number from the larger number (651 - 156 = 495). Reverse the digits of this result (594 from 495). Add this number to the original difference (495 + 594). The final result is almost always 1089. This trick works because of the properties of number manipulation and digit rearrangement
The first operation is to keep the number within the range of three or two digits that are multiples of 99. The second operation is to sum symmetrical numbers that are multiples of 99. The symmetrical number, the reversed one, is a multiple of 99, too. The sum of those symmetrical numbers is always 1089 = 99 * 11. Where 11 is the number of cases between 0 and 10. For more details, look at the comments below.
To everyone! Every 3 different digits works if it's done in the right way! 🙃 Edit To replies:- I can't calculate every number so here are the two common mistakes- 1) Listen carefully in the video if you get an answer in negative ➖ remove that and make it positive! 2) If you get an answer as a two digit number (most commonly 99) add 0 before the number so 99 becomes 099 then add 099+990 = 1089 🤓
If they get a negative number after the first step, ignoring it is a bad idea, because if they don't clear it out and re-type it correctly as a positive number, this will not work.
Look it in this way... Take any 3 digit number and calculate it's difference from it's opposite number. Use word difference. Difference of any two numbers is considered positive.
No need to clear it out. Simply multiply by "-1", OR subtract its reverse instead of adding it, OR click on the change sign (+/-) function (if one is available).
When I first heard this, I was told no repeat numbers. But it doesn't work if you say: 132 or 796 , 495, 738, etc. If the 1st and 3rd numbers are sequential, the inverce makes 99.
Let the unique digits of the number be *x* , *y* , *z* in order. So the number is: *100x + 10y + z* And the reverse of it is: *100z + 10y + x* Subtracting the reverse from original gives: *99(x-z)* If *x>z* let *t=x-z* , else let *t=z-x* So the number we have, ignoring the sign, is: *99(t) = 100(t) - t* *= 100(t-1+1) - t* *= 100(t-1) + 100 - t* *= 100(t-1) + 10(9) +(10 - t)* Possible values of *t* : 1 to 9 *(t-1)* : 0 to 8 *(10 - t)* : 1 to 9 so they are single digits. So the number we have is: *100(p) + 10(9) + q* where *p = (t-1)* *q = (10-t)* The reverse of this number is: *100q + 10(9) + p* Adding these together, we have: *101(p + q) + 180* *= 101(t-1 + 10-t) + 180* *= 101(9) + 180* *= 1089*
You can technically do it with larger than 3 digit numbers, but you need to start adding in a decimal place to make it equal 1089. Otherwise you start getting things like 108090.
@@USE_YOUR_BRAIN So, I realize it's not how you would probably normally treat a decimal. But yeah, if you use ###.# instead of ####, it will work. Last I tried at least.
Not a native English speaker, my problem is with using the word "number" once for something I would also call a "number" ("Zahl" in German) but also for what I would rather call a "digit" ("Ziffer" in German). _"Start with a number of any three but mutually diffferent digits ..."_ would have been my way to start this game.
Below is a very very long and rather convoluted mathematical explanation of this problem. Let the first digit of the first number be a, second digit be b and third digit be c. Then, first number = 100a + 10b + c Reverse of this number= 100c + 10b + a First number - its reverse = 100a + 10b + c - (100c + 10b + a) = 99a - 99c = 99 (a - c) The next set of calculations is to find the 3-digit formula of the above number. = 99 (a - c - 1) + 99 = 100 (a - c - 1) - a + c + 1 + 90 + 9 = 100 ((a - c) - 1) + 90 + (10 - (a - c)) Thus, we have the first digit of the difference as (a - c) - 1, second digit as 9, and third digit as 10 - (a - c). The reverse of the above number is = 100 (10 - (a - c)) + 90 + ((a - c) - 1) Sum of the above 2 numbers = 100 ((a - c) - 1) + 90 + (10 - (a - c)) + 100 (10 - (a - c)) + 90 + ((a - c) - 1) = 100(a - c) - 100 + 90 + 10 - (a - c) + 1000 - 100(a - c) + 90 + (a - c) - 1 = 1000 + 90 - 1 = 1089 One peculiar scenario where this rule might fail is when the difference of the first number and its reverse is 99. E.g. 201 - 102 = 99 In this case, 99 + 99 = 198 which is not equal to 1089. However if we consider 99 as a 3-digit number, that is 099, then we have 099 + 990 = 1089.
I choose 524 and it can't reverse 99 in the end I got 198 answer But your ideas work People are trying some like yours and some comment on your video Great 👍
If you take 756 and subtract it reverse from original 756-657=99 Now adding reverse of 99 which is 99 we get 198 Edit:I found a new thing that if the last and first digits have a difference of 1 then after subtracting the reverse of the number from the original we get 99 and adding reverse of 99 which is 99 we get 198 👍
@@mayankbaber9384Never Proposed it, Most People really don't appreciate his far more superior work in Advanced Number Theory as much as Trivial Results in ordinary Arithmetic which they claim he discovered it(It's the case of Cultural Superiority).
Hey people, note this:
* Any 3 *all different* numbers. Including 0.
* After the first substraction: ignore the negative (-) and consider any two digit number as a three digit number filling with a zero.
Example 1: 506-605=-99 change -99 to 099. Its reverse is 990. Finally: 099+990=1089.
Example 2: 012-210=-198. change it to 198. Finally: 198+891=1089.
Have fun! :)
but if I take 111;222;333?
@@armlatv2260 that's exactly what I was wondering about. Matter fact I chose 666 when my brother watched this video and tried to do the trick on me. Well now here i am in the comments trying to find what u do it someone pics 111 222 ...
@@armlatv2260he said 3 different numbers
But, how possible to add 0 in fron of 99 in calculator?
00:07 choose any 3 different numbers
Pro tip - don't ask same person twice.
Then they get it 😂
Then they get it 😂
Then they get it 😂
Then they get it 😂
Why are you all replying the same 👁️👁️
Legends who got 2 same numbers like 99 and couldn't reverse it
099+990= 1,089
Why add 0? @@fredinelgolosino5201
Wo 999-999=0+0=0 😂😂😂😂
152
998-899=99
It's really a stretch to make it work when the difference is 99. For example 231-132=99. You'd need to see the 99 as 099, then reverse to 990. Adding back 990 to 99 does get you 1089.
Must be 3 digits not 2
I did it with 352, got the same
I didn't get with 857
123-321=-198
-198+891=693
Beated
@kundapatil9601 ignore the negative sign so -198 becomes 198+891=1089
Represent the number as: 1*X + 10*Y + 100*Z.
The inverse would be: 1*Z + 10*Y + 100*X.
Subtract the inverse and get: 99*Z - 99*X.
Also can be written as: 99*(Z-X).
Lets replace (Z-X) with N: 99*N.
Lets rewrite as: 100*N - N.
Lets rewrite as 100*(N-1) + 100 - N.
Lets rewrite as 100*(N-1) + 90 + (10-N).
Thus the inverse is: 100*(10-N) + 90 + (N-1).
Add these together and we get: 99*N + 1000 - 100*N + 90 + N - 1.
Squish together and get: 1000 + 90 - 1 = 1089
QED
I'm teacher of math. Thank you!!! 😊
I came up to 100*N-N, then I saw your comment.😂
Adding and subtracting 100 was a brilliant move.❤
Genius bro
Its real🔥🔥🔥
جامد ياسطا
I love the way you say "let's learn". I only wish my teachers in school would have encouraged me like you have.
No your just disappointed and wish to get back in school times😂
Stop blaming teachers dude
Well stop blaming others, many have learnt and excelled even if it wasnt fun. 😂😂
What have you learnt exactly from the short?
@devrajdwivedi01 blaming? Who's blaming teachers, blaming them for what?
Love your smile, when you talk
❤❤
This got me laid. Thank you
😂
Tf
😂😂😂
Bruh 😂😂😂😂
Broo really?
If abc is the 3 different digit number we can write it algebraically as 100a+10b+c
Then the reverse digit number will be 100c+10b+a
Now subtract the reverse digit number from original one
(100a+10b+c)-(100c+10b+a)
The new number will be
(100-1)a+(10-10)b+(1-100)c
Or
99a-99c
Or *99(a-c)* ..... (1)
Since a and c are single digit numbers i.e
a, b belongs [0,1,2,3,4,5,6,7,8,9]
So (a-c) will also be a single digit number.
[But a≠0 because abc is a 3 digit number]
Henc (a-c) belongs to [1,2,3,4,5,6,7,8,9]
_We excluded 0 because
a-c=0 if and only if a=c
And we know that a,b and c are three different digits. a≠c
Now lets substitute the other possible values of (a-c) one by one
For *a-c=1*
(1)=> 99×1=99
Now add reverse
99+99=198
Add reverse digit number again
198+891=1089
For *a-c=2*
(1)=> 99×2=198
Now add reversed digits
198+891=1089
For *a-c=3*
(1)=> 99×3=297
Now add reversed digits
297+792=1089
For *a-c=4*
(1)=> 99×4=396
Now add reversed digits
396+693=1089
For *a-c=5*
(1)=> 99×5=495
Now add reversed digits
495+594=1089
For *a-c=6*
(1)=> 99×6=594
Now add reversed digits
594+495=1089
For *a-c=7*
(1)=> 99×7=693
Now add reversed digits
693+396=1089
For *a-c=8*
(1)=> 99×8=792
Now add reversed digits
792+297=1089
For *a-c=9*
(1)=> 99×9=891
Now add reversed digits
891+198=1089
Similarly for negative values of (a-c)
Ignore the negative we will conclude with the same answers.
I have tried to verify it by putting all possible values. I will be more than grateful if you share your kind opinion or correction.
Reasonable. 💀👍🏼
Nobody care 😂
It was sweet and concise until the last part, thanks a lot for the explanation. (but...)
(let d = a-c)
99(d)+(inverted_99(d)_) = 99(11) = 1089
I am having a hard time proving that last part but it has to do with prime numbers added to 11.
For 2, 2+9 and 9+2, for 3, 3+8 and 8+3, 5 goes with 6, 7 goes with 4. 1 is not a prime number and doesn't go with anything hence i am having a hard time finding the rule that would render the last part of your reasoning slick and concise like the first part was...
1089 is 33 squared, (11)(99), (11)(11)(3)(3).
I know the answer is somewhere in this haystack, someone please find my needle lol.
Thanks
111*99=
Do it with 584 😐
This concept has already describe by our great mathematician RAMANUJAN
True❤❤
By ye to chota mota chiz hain sir ramanujan ki theories black hole ke eqn tak me use hoti hain 🔥🔥🔥🔥🔥🔥
Y man you are bringing ramanujam here😂
Hahaha😂
@@mrameshmrkbeacause Ramanujan our proud❤🤨
proof: it starts from the fact that the difference of 2 3 digit numbers following the mentioned rule will always be a product of 99 and any number from 1 to 9(which can be taken as x) and the subsequent result can be represented as a 3 digit number as mentioned below:
100(x-1) +10×9+(10-x)
the result when added with its reverse that is 100 (10-x)+ 10×9+(x-1) will exactly give 1089 always after the cancelation of x(the initial variable we took that is from 1 to 9, which is formed from the difference of the first and the last digit of the 3 digit number we initially assumed)
how the 3 digit number representation equation was derived:
suppose the initial number we took is 100x +10y+z, the difference with its reverse would be 100x+ 10y +z-100z -10y -x= 99x-99z=99(x-z)
x-z will always be a variable from 1 to 9, and can be taken as another variable r so the equation now is 99r=100r-r in order to get the number into 3 digit equation format by removing the last negative digital we can carry 1 from the first digit of the 3 digit number and then the second digit and write it as 100(r-1)+10×9+(10-r) now the 3rd digit will always be positive as r is a number from 1 to 9..hence the equation 100(x-1)+10×9+(10-x) is derived
once you are able to derive this amazing maths trick it becomes even more magical!
Спасибо, это было очень достойно для фокусов с числами 👍
This was discovered by Ramanujan while sitting in a taxi...
The Math Genius of the millennia...
Ok bro we get it
That's so awesome..thank you....unless it's not. Ramanujam taxi number(story) is 1729 which is the smallest number which can be expressed as the sum of two different cubes in two different ways.
Ramajuna, who is that?
@@mockingbird8734 its 'SRINIVASA RAMANUJAN'
He was the one of the greatest Indian Mathematician of modern time.
@@rahulpathak1992correct
When I was 8 I discovered that you can take any number larger than 9 and up to infinity and subtract its opposite and that number is ALWAYS perfectly divisible by 9, or 3 because 3 squared is obviously 9
Wow
11?
@@blahblahyaps11-11=0 and 0 is divisible by 9 as 0/9 = 0
The claim should be that the difference of any number (greater than 9 and not equal to its mirrored version) and its mirrored version, is always divisible by 9. Essentially, it all comes down to this:
If a>0; x, y ≥ 0; x>y and a, x, y are all integers:
D = a * (10 ^ x) - a * (10 ^ y) =
= a * ((10 ^ x) - (10 ^ y)) = a * M
D is divisible by 9 if M is also divisible by 9.
M is always divisible by 9 for the same
reason the differences 1000-10=990 and 100-1=99 are all divisible by 9.
@@blahblahyapsare you in grade 1? 11-11 is 0, 0 is divisible by all natural numbers.
What if they have all three digits the same? E.g - If they pick 111, you subtract the reverse, 111. But then you get 0. And 0 + 0 isn’t 1089
*rule. 3 different digits
@@starr980 152???
@@m1n7o consider every resulting 2digit no. To b 3 digit lyk
152-251=-99
Ignore negative n consider as 3 digit
099+990=1089
@@m1n7o if after subtracting with the reverse number leaves you with two digit than you put 0
For e.g. 152-251= -99
Now you have to put 0 after 99
So it makes 990+099= 1089
Hope I was clear enough 😂😅
@@johndawnson did she mentioned that?? Maybe i missed it
Three, that's the magic number, yes it is! It's the magic number!🕷️🕸️
For 3 digit its 1089
For 4 digit its 10890
For 5 digit its 109890
For 6 digit its 1098900
And carry on.....if we do the same process....😍😍😍
Doesn't work for any 3 digit #.
Needs to be 103 or higher
102 = 99
101 = 0
100 = 0
😊
111
@XYZyt if you get 99 then add it with 990 because 99 can also be written as 099😊😊
564 doesn't work
For 2 digit ??
I paint cars for one job, but I work in a bar for my second job and this simple thing has blown a few minds. It’s fun to see the reaction on new customers. It’s a great way to generate fun conversation and I don’t know how many will start watching your channel, but the comments I get have been fantastic. I’ve been using a few card tricks and it’s brought in new people as well. Thank you so much for teaching me. Magic brings the inner child out in everyone. Thank you so much again!
I do know one card trick, that you may know, and if I get my internet connection back up and running after my home improvements I’ll make you a video to show you. I can’t wait. Hopefully you won’t know it, but I’m sure you do. Unfortunately I never new it’s name though. I’ll practice it more so it will be as seamless as possible like your videos.
Take care❤
Do you do car wrapping ?
☺️
I remember reading about this trick in children's books for riddles when I was a kid!
When 3rd digit must finish with 1 ....then your formula 🏎️ wins...
His formula wins at any 3 digit no. You think
Not necessarily
You are absolutely right, thumbs up
@@divyanshkori6209 Try 726, if the subtracted value is just 2 digits 1089 is high value to reach
231
Very nice, this will score many free drinks at the pub for me here in Ireland. Thanks for always offering easy doable tips and tricks.
Love the channel
Why ya mingy Leprechaun!!, and how about if everyone in every pub everywhere has watched this video already!? 🤓🤣😆
I don't get many free drinks but I do know how to get the cheapest drinks.
You see it's this magic power I have, I can drink your drink and then make it appear back in the glass. Don't believe me? Well, I don't wanna take all your money, I'm that confident, so bet you 10c i can do it.
*Drink is drunk*
*Weird mystic hand gestures and mumbling*
Ah well, guess it didn't work, here's your 10c
If you do it right whoever you got will start laughing and probably send all his mates round to you as well.
453 - 354 = 99 to in some cases where there is a difference of 1 between first and last digit you would have to add 0 to the first result to get 1089 but it will still work just add extra step by saying: " Add 0 in the end if you got a two digit result".
99 in the same as 099. Also this works with as many digits. With 4 digits it’s 10,989. And so on
Solve this my number is 323
@@peacelover5571they all have to be different number
@@peacelover5571brother it should have three different numbers 🙄 but your number is 323 - where three is repeated twice.
263 also
Cannot ignore the negative. When negative, you cannot ADD the reverse but must substract the reverse.
I used 123 and didn't work. Now it does. Negative but it does.
I love her demeanor
Three different numbers is key, dont forget that.
Works for 100, but not 101😅
the number only needs to be not symmetrical. Two of the same are fine as long as they are something like 221 oder 667. Only problem is something like 121 or 444.
edit:
even 998 is fine as long you treat the result of { 998 - 899 = 99 } as a three digit number of 099.
099 + 990 = 1089
Yap like 102-201=99+99😂😂😂 do u even knw Math
@@ApayeYaksaya 99 read as a three digit number is 099...
099 + 990 = 1089 ✌🏻
@@ApayeYaksaya is 099
I've watched all your videos .I love magic. Since I was 15.57 now...your very beautiful. I learned a lot. Don't stop practicing magic..
Since you were 15.57? You track hundredths of your years?
I was suprised 😀 But my friend chose 999😂😂😂😂
It should be 3 different number
@@Mechantrechyrmang574
It needs debugging😂
The first and last digits have to be different for it to succeed. 899 or 994 or something is fine, but not 999.
Everyone gangster till they choose 111, 222, 131, 232, etc.
Three different numbers
Love the way she says "LetsLearn"❤
Gets me everytime
Mathematical explanation:
Let's say that the hundreds digit is greater than the units digit (if its the other way you will need to negate the result which is basically like negating the first operation and -(x-y)=y-x so we can continue as if it was this way to begin with) and let's call the hundreds digit "a" and the units digit "b" so a>b.
I will also represent the numbers with their digits divided by commas so I would be able to represent digits with algebraic expressions (132=1,3,2)
Step #1: subtract the reverse:
Let's separate the subtraction into steps:
A. Subtract the middle digit: the middle digit will be subtracted by itself so it does not matter. We are left with a,0,b - b,0,a
B: Subtract the hundreds digit: as a>b we know that the result will only affect the hundreds digit. Now we are left with (a-b),0,b - a
C: Subtract the units digit: as b
152?
102 ?
857 and 859?
Great work
Phenomenal..
"Pull up ur calculator"
Ipad user : 😳😳😳
198 is also a magic number, connected to same rule.
If we choose a 3 digits ending with 0, by subtracting reverse, they get 99, by adding reverse it becomes 198.
Eg: 120
120-021 =99
99 +99 =180.
Nothing magic, sacred geometry..space,time and matter does end to 9... Just count the single digits ..like 360 degree is 9, 45, etc 3600 sec in hour..😊
Okay, now let's learn how to make that paper box.
😂
Waiting..😂
She heard you. The very next video is the box.
😂
yes she did! (now aggresively practicing making the box)@@themacocko6311
She has a soothing voice
❤❤you are great. So nice smile teacher. Amarr. Magician. I practice every thing you teach❤. My guru Devi you are.
I was just admiring the phone instead. Google Pixel phones just looks absolutely captivating.
90s baby here. When the gameboy got boring i used to play with a calculator and discovered this when i was a wee kid. I thought i was a genius xD showed everyone in school the next day
The game boy got boring?! That's wild.
Magic with maths... Kudos to S Ramanujan
We live in the Six house❤
Yes he studied mosa al alkhwarzmi mathematics
@@loveboy_forever 🤣🤣
Choose any number. Double that number. Add eight to the result. Divide the new total by two. Subtract the original number. Your answer will be four.
Such a delight sitting here here india and want to learn a little 🎉 fun skill to pass your my only way to learn really liked your videos and my favourige vedio of uours is sybic cut which was done 7 years ago !!!!!!!!! But nonethless you look toooo beautiful thank you man😅❤
*Let three digit number:*
xyz= 100x +10y+ z
*Reverse:*
zyx = 100z + 10y + x
*Subtract:* xyz-zyx = a9b
After subtraction, the result is a9b.. where
Middle digit is always 9 and sum of a and b is always 9.
*Reverse again:* b9a
*Add:*
a9b + b9a = (a+b)/18/(a+b)
We know a+b = 9
Let's put the values:
9/18/9.. Carry 1 of 18 to hundredth place, so it becomes 10/8/9.. i.e. 1089.
No it's not magic.. simple maths...
Bro
Prabhu 😳🙏🙏🙏
Mai aapke charno me sparsh hu prabhu🎉🎉😂😂
It's not magic, but just a magical number.
Nerd
She's using Google Pixel. Instant like
YAYAYAYA
Yes
💯 agree 👍
Mam 728 not get 1089
@@kennithiria6342change first minus (-) into zero (0). Ex : -99 become 099 then +990
Have them turn to a book that you provide them that has at least 109 pages … have them go down 8 lines and have them read the first word.
Then reveal that word magically on a piece of paper you prepared earlier.
Makes this trick a little more astonishing … as long as you do it only once for the person :)
Your voice is delightful ❤
Here's why it happens:
1. **Three-Digit Number**: Consider any three-digit number where the first and last digits differ by at least two. Let's call it ABC, where A, B, and C are its digits.
2. **Reversing and Subtracting**: When you reverse this number, you get CBA. Subtracting CBA from ABC (assuming A is greater than C) gives a new number. This subtraction aligns with the form (100A + 10B + C) - (100C + 10B + A) = 99A - 99C.
3. **Result of Subtraction**: Simplifying 99A - 99C, you get 99(A - C). Since A and C are at least two digits apart, the minimum value for (A - C) is 2 (e.g., if A is 3 and C is 1), and the maximum is 9 (e.g., if A is 9 and C is 0). This results in a number that is two digits long, and its first digit is always 9.
4. **Intermediate Number Characteristics**: The intermediate number (after subtraction but before adding the reverse) is always of the form 9X9, where X is a digit. This is because the hundreds and units place will always be 9 due to the subtraction process described above.
5. **Reversing the Intermediate Number**: When you reverse this number, it becomes 9X9 again, as reversing doesn't change the position of the digits due to its symmetry.
6. **Final Sum**: Adding the intermediate number and its reverse, both being 9X9, will always lead to 1089. This is because 900 + 90 + 9 equals 999, and adding it to another 999 (since the reverse is the same) results in 1089.
In summary, the specific properties of base-10 subtraction and the constraints placed on the original number (three digits, first and last digits differ by at least two) ensure that this trick works, leading to the consistent result of 1089.
Wow you got so much time ⏲️ to waste
😂😂😂. We r doing this from school
Appreciated . Thank you❤
If you Add 2 time's 999 it give you 1998 not 1089
For that one number must b only 99 and another 999
You are very very correct
The firsr and last digit should differ by atleast 2 which she didnt say
Thanks
Exception:- Don't take the same number on first and 3rd digit 😊
😂 yes, it acts as a barrier
Yeah that’s why she said pick 3 different numbers at the beginning!
That was my 10 year old's initial move. I told him he broke it. He thinks he's hilarious now.
@@torigroves1048102 are three different numbers and it gives an end result of 0.
685 is chilling 😎
Pro tip, don't use the same number like 555.
According to school house rock, 3 is the magic number.
Bro my mother chose 333 and I got roasted so bad 💀
Now a friend chose 231 💀💀💀
She told to choose 3 different numbers
🤣🤣🤣
@@hemu1668yeah i didn't listen carefully
Doesn't work with 756 either
@@mihirambekar9997its 099 so you need add 990😊
Well done…. This blew my daughter mind away 😅
If the result of the first subtraction is negative, then you have to subtract the third number and you will get -1089.
60% of the time, it works every time.
1089 and 2178 are reverse-divisible numbers; the only four-digit numbers that divide their reverse.
2002
@@harshitgaming9962 The reverse of 2002 is itself, and not a different number (with the emphasis on ‘a different number’); hence it doesn’t count. Any number could divide itself, so what! We are talking about the nontrivial reverse divisors. Palindromic numbers have reflectional symmetry across the vertical axis.
@@harshitgaming9962were not talking about palindromic numbers, because she said three different numbers.
The phenomenon you're describing with the number 1089 is a well-known mathematical trick. It works with most three-digit numbers, as long as the first and last digits differ by at least two. Here's how it works:
Choose any three-digit number where the digits are not all the same (like 651).
Reverse the digits to form a new number (156 from 651).
Subtract the smaller number from the larger number (651 - 156 = 495).
Reverse the digits of this result (594 from 495).
Add this number to the original difference (495 + 594).
The final result is almost always 1089. This trick works because of the properties of number manipulation and digit rearrangement
Thank you, this flew right above my head. 💯♥️
This isn’t an explanation, you just said the same thing she said
@@MrFuzziiWuzzii no, she said any, he said most as long as there is a difference of 2.
If not it does not work, for example
555-555=0
000+000=000
@@PietroSperonidiFeniziowell I think you didn't watched it properly. She said "any" three "different" numbers not any three numbers.
You can apply the same trick on four digits and also result in 9999💯💯 try this
I got ZERO! I asked my wife to choose any 3 digit number and she said “555” lol
Other than that, I keep coming up with 1089 😊
948 do this anyone 😅 anyone who gets 1089 will always be blessed 😊
1089 is also knowns as Ramanujan's no. He was a great mathematician and he gave it❤😊
Before he gave it away, we used to count 1086, 1087, 1088 and 1090 directly. Later on 1089 was added between 1088 & 1090.
I think 1729 is the Ramanujan number
@@tribalgroupinc😂😂😂😂😂❤
it's 1729
@@sreenathmaths I searched just after reediing above @masalamagicwithmona8117 , He went in flow without searching it.
I am doing this in my childhood 😂 and I fool my friends many time to see this 😁😂
The first operation is to keep the number within the range of three or two digits that are multiples of 99.
The second operation is to sum symmetrical numbers that are multiples of 99.
The symmetrical number, the reversed one, is a multiple of 99, too.
The sum of those symmetrical numbers is always 1089 = 99 * 11. Where 11 is the number of cases between 0 and 10.
For more details, look at the comments below.
Actually worked ❤
This doesn't work if the number is followed by the same digits at the start and end, eg 565, if you subtract the reverse the result is 0.
should be 3 different number
@@MahamudHasan72 but the numbers 152 doesn't work and they're diffrent
She said any 3 different no dude
152 minus 251 = -99
Ignore the negative = 99
Make it 3 digits = 099
Add the reverse 099+990=1089
Every time u learn from ma'am it seems easy because of let's learn ❤️
I love you dude 😍
121 left the group 😂
I love your voice, it's giving me chills
To everyone!
Every 3 different digits works if it's done in the right way! 🙃
Edit To replies:- I can't calculate every number so here are the two common mistakes-
1) Listen carefully in the video if you get an answer in negative ➖ remove that and make it positive!
2) If you get an answer as a two digit number (most commonly 99) add 0 before the number so 99 becomes 099 then add 099+990 = 1089 🤓
Do 184
Do 958
847
354?
675
that so cool❤
It works in some cases only.
Try out
121
120 etc
She makes me happy every time she pops up on my feed.
The new definition of beauty.
Stuff i used to do in 4th grade...
I like the video with your son.
Thanks for this...now I gonna shine in the evening gatherings😎
Wow her children gonna be magicians and mathematicians!!
it is also magic because when multiplied by 9, it makes a palindrome version of itself: 9801. (Thanks, the great Lilavati!)
Take this number 786 to see the magic of the magical number
If they get a negative number after the first step, ignoring it is a bad idea, because if they don't clear it out and re-type it correctly as a positive number, this will not work.
Look it in this way...
Take any 3 digit number and calculate it's difference from it's opposite number.
Use word difference. Difference of any two numbers is considered positive.
Its correct ! I noticed too !
@@pankhurisingla5879 a negative number minus a positive number is a negative number. Math is math.
No need to clear it out. Simply multiply by "-1", OR subtract its reverse instead of adding it, OR click on the change sign (+/-) function (if one is available).
"Ignoring negative", she basically ask you to subtract the smaller number from the larger one. It's the same.
Your trick breaks if you put the smallest number in the middle. The result ends up 99 or -99., which then adds up to 198, not 1089.
Happened to me when I tried 485
485-584 = - 99 🤦🏻♂️🤦🏻♂️
Just got 99 lol
Three different number ….
Yeah it's true
I took number 918 it will end up in 99 so yeah this is not true for all numbers
Amazing
I used to do this trick in my 3rd standard back in 2007😂😂😂
When I first heard this, I was told no repeat numbers. But it doesn't work if you say: 132 or 796 , 495, 738, etc. If the 1st and 3rd numbers are sequential, the inverce makes 99.
Read the pinned comment
382 also
@twinkles5114 I got to it after I posted this. By then, It was too late.
@@ramagupta6055 that falls under the category of " ect. "
It still actually works..
132-123=-99
Then I tried to work in 3 digits, so calculation was done as:
099+990=1089
Let the unique digits of the number be *x* , *y* , *z* in order.
So the number is:
*100x + 10y + z*
And the reverse of it is:
*100z + 10y + x*
Subtracting the reverse from original gives:
*99(x-z)*
If *x>z* let *t=x-z* ,
else let *t=z-x*
So the number we have, ignoring the sign, is:
*99(t) = 100(t) - t*
*= 100(t-1+1) - t*
*= 100(t-1) + 100 - t*
*= 100(t-1) + 10(9) +(10 - t)*
Possible values of
*t* : 1 to 9
*(t-1)* : 0 to 8
*(10 - t)* : 1 to 9
so they are single digits.
So the number we have is:
*100(p) + 10(9) + q*
where
*p = (t-1)*
*q = (10-t)*
The reverse of this number is:
*100q + 10(9) + p*
Adding these together, we have:
*101(p + q) + 180*
*= 101(t-1 + 10-t) + 180*
*= 101(9) + 180*
*= 1089*
Man I fukin hate polynomials or whatever is that
good explanation, thanks
@@alrickfernandes6715 It's just tedious the way he did. Although the logic is same.
@@Akim375 i couldn't think of a simpler proof
This is the exact I have done ✅. Mathematics is really love ❤
I choose
716
Now I subtract
716-617 = 99
Now
99+99 = 198
Very old thing, we have been doing it since childhood.😅😅😅
You can technically do it with larger than 3 digit numbers, but you need to start adding in a decimal place to make it equal 1089. Otherwise you start getting things like 108090.
@@USE_YOUR_BRAIN So, I realize it's not how you would probably normally treat a decimal. But yeah, if you use ###.# instead of ####, it will work. Last I tried at least.
Don't talk or ask an Engineer or Mathematician...they'll prove you wrong before playing
Then they got shocked 😂
@@BS89.
no
try 796
Don't use numbers that end in 00 or start and end with the same number.
Not a native English speaker, my problem is with using the word "number" once for something I would also call a "number" ("Zahl" in German) but also for what I would rather call a "digit" ("Ziffer" in German).
_"Start with a number of any three but mutually diffferent digits ..."_ would have been my way to start this game.
Here's the exception, those subracted numbers should result in a 3 digit number.
This was given by great Indian Mathematician Srinivas Ramanujan ❤
amazing
Hahahahahahahahhahhaha
Try 666 the devil number lol
@@Itzandrew_GoDz3 different numbers
@@praveeng3351 then try 756
Below is a very very long and rather convoluted mathematical explanation of this problem.
Let the first digit of the first number be a, second digit be b and third digit be c.
Then, first number = 100a + 10b + c
Reverse of this number= 100c + 10b + a
First number - its reverse
= 100a + 10b + c - (100c + 10b + a)
= 99a - 99c
= 99 (a - c)
The next set of calculations is to find the 3-digit formula of the above number.
= 99 (a - c - 1) + 99
= 100 (a - c - 1) - a + c + 1 + 90 + 9
= 100 ((a - c) - 1) + 90 + (10 - (a - c))
Thus, we have the first digit of the difference as (a - c) - 1, second digit as 9, and third digit as 10 - (a - c).
The reverse of the above number is =
100 (10 - (a - c)) + 90 + ((a - c) - 1)
Sum of the above 2 numbers
= 100 ((a - c) - 1) + 90 + (10 - (a - c))
+ 100 (10 - (a - c)) + 90 + ((a - c) - 1)
= 100(a - c) - 100 + 90 + 10 - (a - c) + 1000 - 100(a - c) + 90 + (a - c) - 1
= 1000 + 90 - 1
= 1089
One peculiar scenario where this rule might fail is when the difference of the first number and its reverse is 99.
E.g. 201 - 102 = 99
In this case, 99 + 99 = 198 which is not equal to 1089.
However if we consider 99 as a 3-digit number, that is 099, then we have 099 + 990 = 1089.
Yes, you have to assign zero value to the hundreds column before reversing it.
that's a task. thanks!! ❤
Needed this thanks
😊 👍
U r a math genius 👍👍👍
651 is a Twin Cities zip code.
I choose 524 and it can't reverse 99 in the end I got 198 answer
But your ideas work
People are trying some like yours and some comment on your video
Great 👍
We can ask them if the sum is negative you have to subtract it by the opposite of your answer this will give you -1089
If you take 756 and subtract it reverse from original
756-657=99
Now adding reverse of 99 which is 99 we get 198
Edit:I found a new thing that if the last and first digits have a difference of 1 then after subtracting the reverse of the number from the original we get 99 and adding reverse of 99 which is 99 we get 198 👍
try 291
136 try
You should have added 99+990=1089
898
102 also
I like your north face t shirt ❤
My daughters loved it
Kon kon video dekhne ke baad apne phone ke calculator me check karne gaya 😂😂😂😂😂😂
Bhosdiwale yha to English me likh lo. 😂😂
Me lol 😂😂
Me😂😂😂
Me😂😂😂😂😂😂
Yes u r right... I checked it😂😂😂😂😂
Salute to the great Indian mathematician
Sir ramanujan for this theory
What? he proposed it?
@@mayankbaber9384yes he's
@@mayankbaber9384hes the person who knows the value of infinite ♾️ 😅
No I think the magic no ramanujan has given is not 1089 it's 1729
@@mayankbaber9384Never Proposed it,
Most People really don't appreciate his far more superior work in Advanced Number Theory as much as Trivial Results in ordinary Arithmetic which they claim he discovered it(It's the case of Cultural Superiority).
The edge case is when the first difference is less than three digits it'll be a problem
Three digits number 888 reverse number is 888 by subtracting both we got 0 and by adding 594 in 0 the answer is 594😅😂