I have watched a total of 4 hours of your content (in one sitting) in preparation for my ochem test in two days. I have learned more from you than I have this entire semester. I thought I was stupid and not qualified to be in my major. Nope.. just a bad teacher. Thank you dearly.
Cassadee, thank YOU for the kind words 🤓. I'm so happy you found it helpful! Make sure to check out the same video or other videos on my website joechem.io I've made guided worksheets + solutions & video walkthroughs of the worksheet solutions, 100% all free.
Hey, Cristiano! Actually, the name shown is correct, and the reason being is that the alcohol is treated here as JUST a substituent seeing as the ketone is our highest priority functional group. It's the ketone that we are concerned with including in our parent chain and giving the lowest number to. In this case, that is starting our numbering on the ring at the ketone (position 1). From there, as we go around the ring, our next goal is to go in the direction that will give our substituents the lowest numbers overall, regardless of what they are. In that case, we go counterclockwise since that means we'll have a 2-methyl and a 5-hydroxyl versus going clockwise and having a 3-hydroxyl and a 6-methyl. Does that make sense? Let me know if it does/doesn't, and thank you for watching!
5-ethyl-6-hydroxy-4-isopropyloctanal.
*face palm* thank you. Looks like I couldn’t count that day 🙄
@@jOeCHEMI've had professors at university make way more mistakes. Ur the freakin bomb diggity!
I have watched a total of 4 hours of your content (in one sitting) in preparation for my ochem test in two days. I have learned more from you than I have this entire semester. I thought I was stupid and not qualified to be in my major. Nope.. just a bad teacher. Thank you dearly.
Please never, EVER think you are "stupid" or not smart enough
you've taught me more in 9min than my professor has taught me in 6 weeks. THANK YOU!!
Cassadee, thank YOU for the kind words 🤓. I'm so happy you found it helpful! Make sure to check out the same video or other videos on my website joechem.io
I've made guided worksheets + solutions & video walkthroughs of the worksheet solutions, 100% all free.
Your explanation is very great, I watched the video in 2023. And I have benefited a lot. You're so cool. Thank you from 🇱🇾
Sup joe, thanks for your help
For the second one what about the substituent at 5
Thanks
the last one should be 3-hydroxy-6-methyl-1-cyclohexanone since alcohol should be before
before methyl?
Hey, Cristiano! Actually, the name shown is correct, and the reason being is that the alcohol is treated here as JUST a substituent seeing as the ketone is our highest priority functional group.
It's the ketone that we are concerned with including in our parent chain and giving the lowest number to. In this case, that is starting our numbering on the ring at the ketone (position 1). From there, as we go around the ring, our next goal is to go in the direction that will give our substituents the lowest numbers overall, regardless of what they are. In that case, we go counterclockwise since that means we'll have a 2-methyl and a 5-hydroxyl versus going clockwise and having a 3-hydroxyl and a 6-methyl.
Does that make sense? Let me know if it does/doesn't, and thank you for watching!
Thanks but it should be 5_ ethyl instead of 8_ ethyl
Yup, that's correct (a mistake on my part), and it is noted in the pinned comment -- thanks for watching & commenting!