[6u^6-24u^4-10u^2]/[-2u^2] first get rid of -2 in denominator [-3u^6-l+12u^4+5u^2]/u^2 next get rid of u^2 in denominator [-3u^4+12u^2+5] then contemplate general forms of (x+a)(x+b) = x^2+x(a+b)+ab then expand to (cx+a)(dx+b) =x^2(c+d)+x(cb+da)+ab
first observation -- u^6 suggests there's 6 solutions to this second observation -- a single u term in the denominator means u/=0 as u=0 in the denominator yields = "undefined."
i dont remember exactly how to factor but here goes.. -(3u>4 - 12u>2 +5) =??? apparently u can be anything since it doesnt equal anything.. i messed that up a few times
One of the reasons students get turned off by math is the insistence on "you must know" by teachers referring to problems and methods that have little to no practical value. If it is "super critical" then give us a practical example of when anything like this would be useful.
got it, good one, thanks.
[6u^6-24u^4-10u^2]/[-2u^2]
first get rid of -2 in denominator
[-3u^6-l+12u^4+5u^2]/u^2
next get rid of u^2 in denominator
[-3u^4+12u^2+5]
then contemplate general forms of (x+a)(x+b)
= x^2+x(a+b)+ab
then expand to (cx+a)(dx+b)
=x^2(c+d)+x(cb+da)+ab
Greetings. The answer is
-(3U^4-12U^2-5), after dividing all the terms in the numerator by -2U^2.
Nope
@@davidcawthorne7115 Greetings. Why nope? What is your answer?
I got the correct answer by dividing each of the 3 components of the numerator by the denominator. No factoring necessary.
Same with me
You are on my phone all the time I can't switch on without engaging your app so please stop if I want a lesson I will down load
first observation -- u^6 suggests there's 6 solutions to this
second observation -- a single u term in the denominator means u/=0 as u=0 in the denominator yields = "undefined."
For your first observation:
This is not an equation, so there are no solutions, this is just a number.
Pick any value for U and see what you get.
i dont remember exactly how to factor but here goes.. -(3u>4 - 12u>2 +5) =??? apparently u can be anything since it doesnt equal anything.. i messed that up a few times
One of the reasons students get turned off by math is the insistence on "you must know" by teachers referring to problems and methods that have little to no practical value. If it is "super critical" then give us a practical example of when anything like this would be useful.
I factored -2u² 😊
-3u⁴+12u²+5 ... we cannot go further because we don't know if this is equal to 0 or not.