Factoring and Simplifying in Algebra. You MUST understand FACTORING to PASS Algebra!

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  • Опубликовано: 15 янв 2025

Комментарии • 14

  • @russelllomando8460
    @russelllomando8460 Год назад +3

    got it, good one, thanks.

  • @tomtke7351
    @tomtke7351 Год назад +1

    [6u^6-24u^4-10u^2]/[-2u^2]
    first get rid of -2 in denominator
    [-3u^6-l+12u^4+5u^2]/u^2
    next get rid of u^2 in denominator
    [-3u^4+12u^2+5]
    then contemplate general forms of (x+a)(x+b)
    = x^2+x(a+b)+ab
    then expand to (cx+a)(dx+b)
    =x^2(c+d)+x(cb+da)+ab

  • @devonwilson5776
    @devonwilson5776 Год назад +2

    Greetings. The answer is
    -(3U^4-12U^2-5), after dividing all the terms in the numerator by -2U^2.

  • @pmw3839
    @pmw3839 Год назад +5

    I got the correct answer by dividing each of the 3 components of the numerator by the denominator. No factoring necessary.

    • @ryanwilson9555
      @ryanwilson9555 Год назад

      Same with me

    • @iainmckinnon2738
      @iainmckinnon2738 Год назад

      You are on my phone all the time I can't switch on without engaging your app so please stop if I want a lesson I will down load

  • @tomtke7351
    @tomtke7351 Год назад

    first observation -- u^6 suggests there's 6 solutions to this
    second observation -- a single u term in the denominator means u/=0 as u=0 in the denominator yields = "undefined."

    • @mudshark5393
      @mudshark5393 Год назад

      For your first observation:
      This is not an equation, so there are no solutions, this is just a number.
      Pick any value for U and see what you get.

  • @johnnyllooddte3415
    @johnnyllooddte3415 Год назад +1

    i dont remember exactly how to factor but here goes.. -(3u>4 - 12u>2 +5) =??? apparently u can be anything since it doesnt equal anything.. i messed that up a few times

  • @richardhoner7842
    @richardhoner7842 Год назад

    One of the reasons students get turned off by math is the insistence on "you must know" by teachers referring to problems and methods that have little to no practical value. If it is "super critical" then give us a practical example of when anything like this would be useful.

  • @b213videoz
    @b213videoz Год назад

    I factored -2u² 😊

  • @danieldennis9831
    @danieldennis9831 Год назад +1

    -3u⁴+12u²+5 ... we cannot go further because we don't know if this is equal to 0 or not.