BOD GATE Previous Year Problem | Waste Water Engineering

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Have solved some of the previous year GATE problems related to Biochemical Oxygen Demand with thorough explanation.
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[@akcreator4181]

Concentration of organic matter in a sealed water sample after remaining in dark for 4 and 8 days at
20 °C is calculated to be 160mg/L and 60mg/L respectively. ? (CLO-1,PLO-1,C1) (15 marks)
a) Calculate value of k at 20 °C and at 25 °C.

[@anurang13]

love the way teach!

[@PankajYadav-cs4je]

very nice sir

[@arpankanungo8688]

thank you very much sir :) it is really very helpful.

[@sriharishmudholkar2804]

I came across this question, where they are asking to find the distance from the point of discharge, at which the DO would be minimum when waste water is discharged into the river.
Given are
D.O of waste water,
BOD-5 of both waste and river water
De - oxygenation constant of both, discharge of both,
Which de- oxygenation constant should be considered?
velocity of river.

[@Shaiifalii]

If in the question it is mentioned deoxygenation rate constant how to know if it is base e or base 10?

[@niketanchettri5650]

K 0.1 IS BASE 10 , K 0.2 IS BASE E

[@manikantaanusuri153]

sir very awesome idea sir....thanku so much

[@shikhaingale29]

How to solve 2nd ques equation in virtual calcy

[@84arunkumar]

@12.4 (to convert /hour to /day) sir you mention divide by 24.. but we suppose to multiply.. pls correct if I was mistaken..

[@sandeepsingh-ni7cx]

Bro the way he divided is correct because it will get reciprocaled and get multiplied.

[@ishfaqahmad1493]

Excellent sir thank you so much..😘

[@APSEDUVERSE]

Welcome Ishfaq, have you checked our site learn.apseduverse.com/ ? Video lectures covering entire syllabus with study material, test series and most importantly, doubt support! Starting from Rs.1399/-

[@gauravpandey5297]

Sir in the 2nd question BOD for 5days was given as 180mg/l but you have used the same value of BOD for 2.5days also can we do it like that also? Because i hope BOD will change from 2.5 to 5days

[@APSEDUVERSE]

BOD also depends upon the Temperature because the bacterial activities depend on the temperature and as the Temperature increases bacterial activity also increases upto 60 degree Celsius. The BOD value for 5 days is given for a temperature of 20 degree Celsius and if you increase the temperature then same value of BOD can be exerted in lesser time so the question asks the temperature at which the BOD5 = BOD2.5

[@v_naveen_9676]

in 22nd que how did u get the K value as 0.36. am confused with antilog and e steps...plz explain bro.

[@kajalnirmal780]

Sir same problem

[@psychedelickid369]

kajal nirmal take exponential on one side and solve it, then use log on both sides, remember log e=1

[@v_naveen_9676]

oh i have to take ln instead of log.. am cleared bro...

[@robinborah1884]

Sir e bala part kese calculate kia

[@jankiramanjha280]

aditya sir in avg BOD quest ....i have reffered a coaching material and ans they have given is 109.8mg/l. its confusing

[@APSEDUVERSE]

Yes! I am aware of that but what I have told is correct. If it says clearly that the BOD becomes zero on the 5th day then you can take it to find out the average but here nothing like that is mentioned so you can do it as I have mentioned. Sorry for the late reply.

[@Sam-lv7xr]

Dear sir sample is tested after 5 day we found DO zero ....it may be consumed in 1 or 2 or 3 or 4th day ......so the third result will give misleading result..so we should not use this?

[@RohitKumar-qq5cx]

solution of question 2 is quite lengthy......it can be solved in just few steps

[@bhootkaal3391]

What i put at place of e?

[@sofftmud]

nothing e mean exp at math you can find it at calculater

[@shambhvimiracleofgod4215]

Thanks sir

[@harvindersingh2539]

how to solve 1:37....?

[@ahmedasifmalik5940]

plz send typing wright not hand..
becoz ur wrigt not readable

[@ranjithalluri604]

Bhai base10 waala problem chaiye

[@amarnathbhusse6935]

Gate 1998 Bod question ka ans batao

[@hemantdhaked1903]

Thanks sir