@@manikantan9475 pronounciation doesn't matter, JEE or NEET is not oral, by the way that's her accent it doesn't indicate that she is bad in chemistry, she has a lot of knowledge of chemistry .
@@manikantan9475 First of all learn english then rip ur clothes! Atleast she is trying to speak (and succeeding too) And second things second, every state has different accents for english in india. South Indians have different tone whereas North Indians have different so u shouldn’t judge anyone!
@@sanjayvarmora8928 But this guy gave right answer.. below intersection its CO coz its below FeO graph and above intersection its Coke ""C"" coz here this graph is below of FeO
FeO(s) + C(s) --> Fe(s) + Co(g) ng = 1 - 0 = 1 ∆G° = + ve Non Spontaneous FeO(s)+CO(g)-->Fe(s)+CO2(g) ng = 1 - 1 = 0 ∆G° = 0 Co having low ∆G° then C So *Co* consider as good reducing agent
maam answer is C because this one is having graph below the ellingham graph of FeO. and CO will be not suitable since it is having graph above FeO graph
At low temp CO is the best reducing agent because it is spontaneous as it is below the FeO line in the earlier temperature phase!!! Since, after the enthalpy becomes +ve above the horizontal line, C is the best reducing agent at high temperature!!
Comment section is full of ppl blessing you, i wanna do the same too, lol! ... Mam, thanks alot,my brain was getting overheated ,now this video is ice to me! Ughhhh,, thanx alot :D
Mam the relation that you have said is no of moles increases entropy increases but my doubt is as no of moles increases the space between moles decreases so the movement of the moles decreases and the relation becomes no of moles increases entropy decreases 🙄 randomness will be decreased.. please reply mam
Appreceatable..you are teaching much more better than the online educators of pw and unacademy.before watching ur video i watched 2 more videos but could not understand but when i studied from you i got cleared in just one time.....thankyou. 🙏🙏🙏🙏
From c to co2 formation,Delta G =DeltaH.isnt it? How can it become zero.of course Tds will be zeso as dS is zero.so there is no impact on increasing temperature.but how dG will become zero.if anybody knows please let me know.
thank you so much!!! i couldnt understand our book in chem and you did better than my prof. I think the best reducing agent is C cos as you said the metal oxide can only be reduced by the elements below it and CO is above FeO so it cant reduce it.
CO is the better reducing agent among C and CO because CO can act at temperatures lowers than that of C and CO has *delta* G std is negative for but it is positive for C at temperature corresponding to the point of concurrence of the 3 curves. Mam is this right?
In the whole video I was wondered how mam writing with left hand, your hand says that you are brilliant mam,however thanks mam u explained it very well🥰🥰🥰
@@pritysuman6622 i am not trying to offend her.. i also admire her.. but if there is some problem in my understanding she could rectify it.. also i have my youtube channel not to earn subscribers or be a youtuber.. i have made a channel to watch videos of my choice.. so i am not having any kind of offensive attitude towards ma'am.. !!
You are right Megha.. what she meant was that the temperature factor would not affect Gibbs free energy now.. there is nothing like that at eqm Delta H is zero.. all the reactns happening around are in eqm only.. some have a greater extent than others.. but enthalpy of reactn is not zero.
Thanks mam , the concept is now crystal clear .Before watching the video I was like quiting this topic but now I can easily solve the question related to the topic
Thanks mam that you have taught this topic you makes it so easy for me that i have forgotted the tricks you remembered me if you can make videos on organic chemistrx top ic please make it
Mam. U r one of the best teacher I ever seen..... I did not understand this metallurgy lesson more.......U teaching very well mam....love ur teaching very much....well done...do more videos mam.....all the best.....🙏🙏🙏🙏🙏💓💓💓💓💓💞💕💞💕💯💯💯💯😘😘😘😘😍😍😍😍🤩🤩🤩🥳🥳🥳🥳👍👍👍👍👍👌👌👌👌👌👌👌👌👌👌👌👍👍👍👍👍✌️✌️✌️✌️✌️✌️👏👏👏👏👏🔥🔥🔥🔥🔥💥💥💥💥
Tq mam I have one doubt mam last case la 3parts la 1st and 2nd part la carbon reacts with oxygen to give carbon monoxide in this case neenga no of moles changed la product la co so u take one mole in reactant side c+O2 u take one mole in oxygen why u take moles in carbon. We take mole from product_reactant gives no of moles reacted so we take mole from carbon also mam apaa change in moles is negative only
Ma'am you always help me....After completing class12... I will see all the trick that you have uploaded....And clear the doubts of chemistry and physics
@@indianrail-addicts3320 Bhaai mere kehne ka matlab nhi samjhe ......ye sb jo no. Ke peeche bhaagte hain na iska koi mtlb nhi hai....bas ek chalava hai......bhaai agar tumhe koi padhne ke liye bolta hai to tum use ek task ki tarah lete hoge....ki chalo padh ke no. Le aate hain phir exams ke baad padhna band....iska kya mtlb hai....yhee ki tumhara isme interest nhi hai ....wahin agar tumhe koi bol de agar cricket seekhne ya khelne ke liye .....tu tumhe man karega ki poora din khelu...tum isase bor nhi hoge kyunki tumhara interest hai.....to main bas yhee kehna chah rha tha ki bhai no. Ke liye padhaai nhi hoti....ab ye jo bade bade scientists the in sab ne apne paas ke surroundings ko observe kiya to unme jaanane ki iccha jagi ki ue kaise kaam karta hai...to unhone iske baare me padha or kai discoveries ki .....wo no. Lane ke liye thode na padhte the school me .......unka yahi interest tha or hamaaree majboori ki no. Lana hai...(not for all)...so padhai me jahan no. Ki baat ayee waha sajh lo majboori hai.......!! Ok bhaai koi problem??!
@@indianrail-addicts3320 or bhaai kaam isiliye karte hain ki apni rozi roti chala sake.....brillient log kuch aisa kar jaate hai ki unhe janmo tk yaad rakhe .....accha tum man lo padh likh ke IIT ya kisi or exam me top kar diye .....log kuch mahine yaad rakhenge tumhe phir kon pooch rha hai....to thaare itna padhne ka kya mtlb na tum koi change laaye is duniya me...bas padhai kiye pass hue degree liye phir mar gye.....to jeene ka fayda kya bhaai ....mjaa kaha aaya jeene me tum to bas bhaagte rhe majboori ke peeche.....!!!!
@@abhyuday1294 bhai bilkul sahi keh rahe ho lekin jab tak padhai nahi karoge to is duniya mai change kaise la paoge.or jin great scientist ki tum baat kar rahe ho wo great the but padhai to unhone bhi kari thi. But haa ye baat sahi hai ki unhone marks ke liye nahi knowledge ke liye kari thi. But yaar ye jo marks hai na ye na ho to sab padhna hi chodh denge kyuki insaan tabhi padhta hai jab use kisi cheez ka dar ho and ye log bada kehte hai ki nahi mujhe to padhne mai interest hai but seriously kisi ka hota nahi hai. Or last mai yahi kahunga ki padho jaroor khoob padho but target knowledge ko rakho marks to khud aa hi jayenge phir..
![Noob To Max With DRAGON REWORK In Blox Fruits [FULL MOVIE]](http://i.ytimg.com/vi/LnBMOinoOvA/mqdefault.jpg)
I was about to quit this , but when i saw it's on Komali mams Channel a glimpse appeared on my face and whole 15 minutes worth spended
you was about to quit because of her way of pronouncing
@@manikantan9475 that's rude to say
@@manikantan9475 I've seen u hating on a lot of her videos. Who the duck areu ?? Fucked up fool
@@manikantan9475 pronounciation doesn't matter, JEE or NEET is not oral, by the way that's her accent it doesn't indicate that she is bad in chemistry, she has a lot of knowledge of chemistry .
@@manikantan9475 First of all learn english then rip ur clothes! Atleast she is trying to speak (and succeeding too) And second things second, every state has different accents for english in india. South Indians have different tone whereas North Indians have different so u shouldn’t judge anyone!
Left hand writter ...super mam😍
C is the best reducing agent among both, since ∆G = -ve and the reaction occurs at low temperature
No CO is the best reducing agent which is below the oxide and it's ∆G is -ve
How
Frnds below 710 C, CO is best reducing agent....and above 710 C, C is best reducing agent....pls refer ncert of 12th std
@@ramkyhariharan5649 thank you my friend
Thank you from south korea! I didn’t understand from my thermodynamics class but clearly understand by watching your video!
OpPa SaRaNgHaE ,lol jk
if u know hinndi i think u will pray for physics wallah..he is a teacher but teaches in hindi ..check out.. u will get good notes from him
@@anwesha1202 😹😹😹👍🏻
Woh South Korea? Impressive
한국에서 당신이 속한 지역은??
Below intersecting lines FeO , CO acts as a reducing agent , above the intersect of FeO carbon acts as a reducing agent....
C act as a reducing agent right?
@@sanjayvarmora8928 bhai mera bhi answe C hi aa rha h
@@sanjayvarmora8928 But this guy gave right answer.. below intersection its CO coz its below FeO graph and above intersection its Coke ""C"" coz here this graph is below of FeO
it depends on temp at higher temp C can be used and at lower temp co can be used as the best reducing agent
FeO(s) + C(s) --> Fe(s) + Co(g)
ng = 1 - 0 = 1
∆G° = + ve
Non Spontaneous
FeO(s)+CO(g)-->Fe(s)+CO2(g)
ng = 1 - 1 = 0
∆G° = 0
Co having low ∆G° then C
So *Co* consider as good reducing agent
Hey bro
If ∆n= +ve then randomness increases so entropy increase
∆G= ∆H- T∆S
So ∆G = -ve , spontaneous
maam answer is C because this one is having graph below the ellingham graph of FeO.
and CO will be not suitable since it is having graph above FeO graph
That's my opinion too
Same answer here also..
CO is the best reducing agent at lower temperature.
At low temp CO is the best reducing agent because it is spontaneous as it is below the FeO line in the earlier temperature phase!!! Since, after the enthalpy becomes +ve above the horizontal line, C is the best reducing agent at high temperature!!
@@govardhanaprabhu7736 yes u are correct
Mam coke (C) will react as reducing agent as it's value of Delta Gis zero where as CO have positive Delta G value
Best Chemistry Educator.
I have ever seen in my life.
Mam Love ❤️ from North India
Best explanation ever, greeting from indonesia
Simplest explanation of ellingham diagram
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Mam,Your Passion Reflects In Your Voice ...
Thank you for all effort
Well said...
Comment section is full of ppl blessing you, i wanna do the same too, lol! ... Mam, thanks alot,my brain was getting overheated ,now this video is ice to me! Ughhhh,, thanx alot :D
Coke will act as a reducing agent for FeO.
Mam am I right.??
Ur the queen of chemistry..💓🙏🙏We are lucky to have u mam💪💞
Mam u are the best teacher ever !!!!
Ma'am you are best reducing agent..You have reduces all the problem of metallurgy.. Love u ma'am
wildlife explorer did she get oxidised?
🤭🤭🤭
@@zaynahmed4506 🤣🤣🤣🤣
Legend see this vedio .after five year
Thank u soo much maam... I dint understand this from class... But now i am clear with the concept... May God bless u maam...
Happy to listen this 😊. Study well 👍
Thank u maam...
Thank u mam
Same here
Same here
For last question C is good Reducing agent as it lies below the FeO line
At lower temperatures CO is better reducing agent than C and At higher temperatures C better reducing agent than CO
Thanks for the confirmation 🙂
Mam the relation that you have said is no of moles increases entropy increases but my doubt is as no of moles increases the space between moles decreases so the movement of the moles decreases and the relation becomes no of moles increases entropy decreases 🙄 randomness will be decreased.. please reply mam
C is the better reducing agent right?
Yes
CO
Appreceatable..you are teaching much more better than the online educators of pw and unacademy.before watching ur video i watched 2 more videos but could not understand but when i studied from you i got cleared in just one time.....thankyou.
🙏🙏🙏🙏
I started my preparations today for ISC 2019. After going through your channel
I guess I will make it in time
Simplest explanation of ellingham diagram
ruclips.net/video/eajgq-1A1V8/видео.html
Please subscriber this channel
Keep making more tricks...
Janta ko inke zarrorat hai....
*CO is better reducing agent than C because it can reduce FeO at lower temperature!*
i think u r a fool
if u can answer this u r a boss
g
@@satyasaisivasrinivas173 g
@@satyasaisivasrinivas173 u r awessome
Thankyou soo.muchh ma'am.
its a very explanation.❣️❣️❣️❣️
and ans of last q is CO is best reducing agent.
Thank you from Tamilnadu ☺️👍🏻
Tq frm tirunelveli 😇
From c to co2 formation,Delta G =DeltaH.isnt it? How can it become zero.of course Tds will be zeso as dS is zero.so there is no impact on increasing temperature.but how dG will become zero.if anybody knows please let me know.
Tq so much....luv u to the core....now i'm clear with the concept😍😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙😙luv from tamilnadu
Y these much emojies😂
Left hand writer super mam dermodynamics
Madam. Before watching your video I want to quit ellingham diagram. But after listening your class I want to read ellingham diagram ❤️👍👍
I have gone through so many videoes...but this is best video with less time....tq Mam....
0:15 according to the dhermodynamics😂😂
It's so bored so I kept this topic unstudied...but u taught easy way mam I have understood clearly tq mam
thank you so much!!! i couldnt understand our book in chem and you did better than my prof. I think the best reducing agent is C cos as you said the metal oxide can only be reduced by the elements below it and CO is above FeO so it cant reduce it.
U r wrong
@@balajipedamallu1551 no he/she is right , according to NCERT C can reduce FeO and it itself gets reduced to CO
CO is the better reducing agent among C and CO because CO can act at temperatures lowers than that of C and CO has *delta* G std is negative for but it is positive for C at temperature corresponding to the point of concurrence of the 3 curves.
Mam is this right?
In the whole video I was wondered how mam writing with left hand, your hand says that you are brilliant mam,however thanks mam u explained it very well🥰🥰🥰
No one in the world like you mam
Ma'am didn't understand one thing, in part B if delta S is 0 .. the delta G should be equal to delta H right.. ??not 0
Don't have a correcting nature always.... that's why u have no subscribers and she has 50k+
@@pritysuman6622 i am not trying to offend her.. i also admire her.. but if there is some problem in my understanding she could rectify it.. also i have my youtube channel not to earn subscribers or be a youtuber.. i have made a channel to watch videos of my choice.. so i am not having any kind of offensive attitude towards ma'am.. !!
At equilibrium delta H is zero
@@deepikapeddireddy5725You cannot say anything about enthalpy change in equilibrium....delta G is zero at equilibrium
You are right Megha.. what she meant was that the temperature factor would not affect Gibbs free energy now.. there is nothing like that at eqm Delta H is zero.. all the reactns happening around are in eqm only.. some have a greater extent than others.. but enthalpy of reactn is not zero.
You are a good teacher +1 subscriber
Finally understood after watching 3 videos.
Very nice explanation.👌👌
Thanks mam your s teaching helping me a lot in covid 19 leaves 🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝🤝💕
In part a ∆ng=1/2 while if we compare part c it is -1/2 how it is possible.
Same same i have been wondering the same. M not getting the ans!!
Carbon is the reducing agent
Thank you so much mam
I'm a neet candidate
Ur classes are really helpful to me.. A teacher like u is always overwhelmed ❤❤🙏🙏
Simplest explanation of ellingham diagram
ruclips.net/video/eajgq-1A1V8/видео.html
Please subscriber this channel
Coke is the best reducing agent is it right madam
I too thinking ..
in Feo c is the best reducing agent.
plzz reply maam is it correct.
Zufeshan fatma zno me v C is best reducing agent
Zufeshan fatma no .in feo co is best reducing agent
As c is below of Zno....obiusly you are right
komali maam supremacy 😎😎
if i study metallurgy, i leave this topic particularly But after seeing your video Its very useful MAM. THANK YOU SO MUCH MAM FOR YOUR EFFORT
Thank you mam😍
Love from Assam ❤️
How delta G is zero when delta S is zero
By relation G = H - TS
H is constant..so ∆G is 0
Simplest explanation of ellingham diagram
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Thanks mam , the concept is now crystal clear .Before watching the video I was like quiting this topic but now I can easily solve the question related to the topic
Exactly
💯 💯
Maam plzzz keep making videos like this we love your videos i would also love to personally come to your home for tuitions..
Respected Madam, for an equilibrium process ∆G = 0 but not ∆G°, is it true?
No, it is not true. we always calculate delta G°
@@shashankpahariya but Gibbs-Helmholtz equation says otherwise
Very well explained in just 15 minutes ♥️🙂
I always skip this... but this is amazing.......... Made my day... Thanks a lot mam
Thank you maam.
CO is better reducing agent
Absolutely Perfect explanation! Best explanation available on RUclips
Hy king of hawkins
C is best ☑ reducing agent... Answer of last question
is topic ne to mujhe hila diya tha ab stable ho paya hu 🤣😅😁😁 thanku
Thanks mam that you have taught this topic you makes it so
easy for me that i have forgotted the tricks you remembered me if you can make videos on organic chemistrx top
ic please make it
Puch rha hai ki bta raha hai bhai?
Thank you mam. Carbon (coke) act as a reducing agent and at low temp.
Thanx maam i cant understand from any coaching classes ..
But i can understand from ur video in one time .....maam thank you so much...
Really i was not able 2 understand this concept frm my classes , but now its 💯 clear mam tqq such
Sis...Should I learn ellinghams graph for neet Or will they provide the graph for the particular question
Mam your concepts are crystal clear 😍😍
Not crystal clear ... Made confusing in the last questions
Tq mam .if didn't understand any topic 1st I saw ur video mam
Mam unga voice so nice to hear & the concepts are well teached for me to score good marks in board xm
Mam. U r one of the best teacher I ever seen..... I did not understand this metallurgy lesson more.......U teaching very well mam....love ur teaching very much....well done...do more videos mam.....all the best.....🙏🙏🙏🙏🙏💓💓💓💓💓💞💕💞💕💯💯💯💯😘😘😘😘😍😍😍😍🤩🤩🤩🥳🥳🥳🥳👍👍👍👍👍👌👌👌👌👌👌👌👌👌👌👌👍👍👍👍👍✌️✌️✌️✌️✌️✌️👏👏👏👏👏🔥🔥🔥🔥🔥💥💥💥💥
Meru super mam
Hiiii Ma'am I guess u r from Tamil... no??? But ur voice ur teaching both r awesome.... Thanks a lot
Aqsa kibria, she is from hindi... u can notice that while speaking she used one word in hindi 👍👍👍
Mam is from bangalore...!
Mam is from bangalore
@@sathiyasheila3587 is she
@@abinathao2953 Ur profile is awsome
CO is a better reducing agent than C as the line containing co rxn is lower to feo
Thank you so much ma'am.. Really very crystal clear with this topic ❤ God bless you mam. Love from Maharashtra ✔🙌
Sis....Should I learn ellinghams graph for neet Or will they provide the graph for the particular question
Really she is goddess of chemistry and superb tricks also...
Mam video is unavailable!!
Trick for test your self
Mam why don't we consider the moles of C in part B and A....., and why we are considering in part C
Mam u r lefty....Lefty peoples are very intelligent 😘😍
@@bhawnachauhan1975 abe lefty are hard workers and nt intelligent
@@syedosamakashif30 What did he wrote and what you're telling him... haaa....
@@shikharrai4854 I said lefty people are harworkers and not that intelligent
@@syedosamakashif30 God help you magnificent Human!
@@shikharrai4854 THANK you bro
CO is better reducing agent.
Because it is below the graph of metal oxide.
Thank you Mam .My concept is now clear :)
Mam there is mistake with the *A* point on the graph ∆ng value should be = 1-(1+1/2)
No mole of C will not be taken as it is taken as solid in coke form and not in gaseous form
Mam please organic conversions pe bhi vd upload kijie 😕😕
Haa plzz mam
Tq mam I have one doubt mam last case la 3parts la 1st and 2nd part la carbon reacts with oxygen to give carbon monoxide in this case neenga no of moles changed la product la co so u take one mole in reactant side c+O2 u take one mole in oxygen why u take moles in carbon. We take mole from product_reactant gives no of moles reacted so we take mole from carbon also mam apaa change in moles is negative only
Thank you ma'am for this really useful video.
You are a life saver♥️
Ma'am you always help me....After completing class12... I will see all the trick that you have uploaded....And clear the doubts of chemistry and physics
Who is preparing for class 12 exam and want to score good like me
Jyada no. La ke kya ukhad loge bhaai.....marne ke baad thode na tumhe koi yaad rakhega.....
@@abhyuday1294 to yaar aaise to insaan kaam karna hi chodh de matlab ki mujhe marne ke baad koi yaad thodi rakhega 😒😒😒
@@indianrail-addicts3320 Bhaai mere kehne ka matlab nhi samjhe ......ye sb jo no. Ke peeche bhaagte hain na iska koi mtlb nhi hai....bas ek chalava hai......bhaai agar tumhe koi padhne ke liye bolta hai to tum use ek task ki tarah lete hoge....ki chalo padh ke no. Le aate hain phir exams ke baad padhna band....iska kya mtlb hai....yhee ki tumhara isme interest nhi hai ....wahin agar tumhe koi bol de agar cricket seekhne ya khelne ke liye .....tu tumhe man karega ki poora din khelu...tum isase bor nhi hoge kyunki tumhara interest hai.....to main bas yhee kehna chah rha tha ki bhai no. Ke liye padhaai nhi hoti....ab ye jo bade bade scientists the in sab ne apne paas ke surroundings ko observe kiya to unme jaanane ki iccha jagi ki ue kaise kaam karta hai...to unhone iske baare me padha or kai discoveries ki .....wo no. Lane ke liye thode na padhte the school me .......unka yahi interest tha or hamaaree majboori ki no. Lana hai...(not for all)...so padhai me jahan no. Ki baat ayee waha sajh lo majboori hai.......!! Ok bhaai koi problem??!
@@indianrail-addicts3320 or bhaai kaam isiliye karte hain ki apni rozi roti chala sake.....brillient log kuch aisa kar jaate hai ki unhe janmo tk yaad rakhe .....accha tum man lo padh likh ke IIT ya kisi or exam me top kar diye .....log kuch mahine yaad rakhenge tumhe phir kon pooch rha hai....to thaare itna padhne ka kya mtlb na tum koi change laaye is duniya me...bas padhai kiye pass hue degree liye phir mar gye.....to jeene ka fayda kya bhaai ....mjaa kaha aaya jeene me tum to bas bhaagte rhe majboori ke peeche.....!!!!
@@abhyuday1294 bhai bilkul sahi keh rahe ho lekin jab tak padhai nahi karoge to is duniya mai change kaise la paoge.or jin great scientist ki tum baat kar rahe ho wo great the but padhai to unhone bhi kari thi.
But haa ye baat sahi hai ki unhone marks ke liye nahi knowledge ke liye kari thi.
But yaar ye jo marks hai na ye na ho to sab padhna hi chodh denge kyuki insaan tabhi padhta hai jab use kisi cheez ka dar ho and ye log bada kehte hai ki nahi mujhe to padhne mai interest hai but seriously kisi ka hota nahi hai.
Or last mai yahi kahunga ki padho jaroor khoob padho but target knowledge ko rakho marks to khud aa hi jayenge phir..
Very nice explanation..and ..
Madam your way of approaching concept clarity also very excellent 👌👌👌👌👌
You made me understood it easily and your voice is beautiful
She is really explaining everything very nicely. .. i. really enjoying. her class
Another Good Thing Is Handwriting Is too Nice that Makes Remembering Easier
mam c + o2 gives CO2 here how deltang becomes zero? no of moles of product is 1 and no of moles of reactant is 2?
Thanku mam for wonderful explanation
Mam ur really supr mam ...Im big fan of u in ur teaching....really loves ur teaching...
Ya finally I understand it 😁 ... Thank you mam 💞
C is good reducing agent
Thanks chapter Ka topics achy se samjh me a Gaya
Very nice explanation mam my doubts are cleared
The best explanation for ellingham diagram on RUclips
tysm mam:)
FeO + C is best suitable
Thank you mam for explaining very clearly...😃u r amazing chemistry lecture mam..I am going to write jee advanced exam I need your blessings mam..🙏🙏
p
Awesome trick mam 💖💖💖💖