Fellow Pre-Med here...I HAVE to comment and say that I am in Orgo II because of YOU! You taught me how to think in Ochem, and even after practically failing my first Orgo 1 Exam I knew with your videos I would continue to get reps in and do better. Studying for the MCAT now too and totally believe your teaching has showed me what I need to know. Thank you for your content, kindness, and skillset. God Bless you!
I took organic chemistry in 1985. I wish my professor framed this reaction like you did in your intro. It would have given the reaction some context and meaning to an otherwise rote class. I found the textbook more interesting than the professor. However, it was a long time ago
Not a silly question! The difference is really down to their action. Both bases and nucleophiles are electron rich species which donate electrons to electron deficient species. The definition of a Lewis base is an electron pair donor, so nucleophiles are Lewis bases which donate a pair of electrons to an electron deficient species, for example a carbon in C=O. The definition of a Bronsted Lowry base is 'accepting' i.e. forming a bond to a proton (H+) so the bases in these reaction pathways are Bronsted Lowry bases. So in organic reaction mechanisms we use the term 'Nucleophile' to describe a Lewis base, i.e. an electron rich species that attacks something other than hydrogen and 'Base' to describe an electron rich species that attacks hydrogen. I hope that is clear :)
thanks for the video, it's great! just a quick question, isn't the H3O+ for all 3 of the reactions at 8:00 a type of protic solvent? Or does hydronium not really count as a solvent and something else is supplying it? Now that I'm checking again, I'm guessing the fact that it's sequential 1. and then 2. means that it can't take H+ from the H3O+ right?
Grignard reactions tend to use ether as a solvent. Protic solvents wouold protonate the Grignard and prevent the reaction from happening. For this reason H3O+ is added in the second step of these reaction (i.e. after the Grignard reagent has already reacted)
Thank you! if there are two groups of aldehyde attached to the same reactant should we use Grignard twice? also what if the reactant were ester or O-CH3-CL or acid chloride?
Yes. If you have two aldehyde functional groups on a reactant then the reactant could react with 2 equivalents of the grignard. Esters, acid halides, and acid anhydrides can also react with two equivalents of a grignard too. I cover this in lesson 20.4: ruclips.net/video/_1ATaPMZrRQ/видео.html Hope this helps!
@@ChadsPrep Thank you so much! I should watch that lesson before the exam yesterday :) The question was Ester carbonyl group attached to O-Ch3Cl I am not sure if O-Ch3Cl treated as leaving group or not?
Thank you! You've helped me get through all of my chemistry classes. Quick question: If the attachments are 2 ethyl groups and a benzine ring, would there still be a 3rd way to synthesize?
If any two of the groups were identical there would only be two ways to produce a tertiary alcohol beginning with a ketone. However, you will learn later in the semester that as long as two of the groups are identical you could actually start the synthesis with an ester and add excess grignard. So in this case if you started with a benzene ester (for example methyl benzoate) and then added two equivalents of an ethyl grignard (aka excess) you would get exactly the same product. This will be presented in lesson 20.4. Hope this helps!
Fellow Pre-Med here...I HAVE to comment and say that I am in Orgo II because of YOU! You taught me how to think in Ochem, and even after practically failing my first Orgo 1 Exam I knew with your videos I would continue to get reps in and do better. Studying for the MCAT now too and totally believe your teaching has showed me what I need to know. Thank you for your content, kindness, and skillset. God Bless you!
Thank you - Glad the channel is helping you out!
I started enjoying chemistry
because of you. Thank you!
You're welcome and Thank you!
Your videos are AMAAAAAAAZING! God bless you dearly!
Thaaaaaank you - same to you!
Thanks a ton man, I've been forced to cram a lot of organic them and you've made it a lot easier than it would've been otherwise!
Glad the channel is helping you - Happy Studying!
I took organic chemistry in 1985. I wish my professor framed this reaction like you did in your intro. It would have given the reaction some context and meaning to an otherwise rote class. I found the textbook more interesting than the professor. However, it was a long time ago
I'm glad you are enjoying the content!
This made it easy for me to understand..so helpful😊
Excellent - glad to hear it!
hmm, this may seem like a silly question but what is the difference between a base and a nucleophile
Not a silly question! The difference is really down to their action. Both bases and nucleophiles are electron rich species which donate electrons to electron deficient species. The definition of a Lewis base is an electron pair donor, so nucleophiles are Lewis bases which donate a pair of electrons to an electron deficient species, for example a carbon in C=O. The definition of a Bronsted Lowry base is 'accepting' i.e. forming a bond to a proton (H+) so the bases in these reaction pathways are Bronsted Lowry bases. So in organic reaction mechanisms we use the term 'Nucleophile' to describe a Lewis base, i.e. an electron rich species that attacks something other than hydrogen and 'Base' to describe an electron rich species that attacks hydrogen. I hope that is clear :)
Could you please suggest some of your personal favorite chemistry books? I would appreciate your recommendations."
You deserve millions of views and subscribers for all the valuable knowledge and hard work. 😊
you are literally the best THANK YOU!!!
You're welcome and Thank You!
would you consider covering organoboron or organoaluminum grignard reactions and synthesis of them?
thank you my techer,you very good❤❤❤
You're welcome and Thank You.
Amazing video thank you so much
You're welcome - thank you!
Thank you
You're welcome
This is so helpful, thank you!
Would we be able to use other agents besides H3O+ in the second step as an acid workup? Would H2O work?
Thank you god
Happy Studying!
Thanks a lot
You're welcome.
thanks for the video, it's great!
just a quick question, isn't the H3O+ for all 3 of the reactions at 8:00 a type of protic solvent? Or does hydronium not really count as a solvent and something else is supplying it?
Now that I'm checking again, I'm guessing the fact that it's sequential 1. and then 2. means that it can't take H+ from the H3O+ right?
Grignard reactions tend to use ether as a solvent. Protic solvents wouold protonate the Grignard and prevent the reaction from happening. For this reason H3O+ is added in the second step of these reaction (i.e. after the Grignard reagent has already reacted)
Thank you!
You're welcome, Rohan!
thank you your way so clear
You’re welcome, Sura! 😊
can't LiAlH4 lead to a 3° alcohols?
Thank you! if there are two groups of aldehyde attached to the same reactant should we use Grignard twice? also what if the reactant were ester or O-CH3-CL or acid chloride?
Yes. If you have two aldehyde functional groups on a reactant then the reactant could react with 2 equivalents of the grignard. Esters, acid halides, and acid anhydrides can also react with two equivalents of a grignard too. I cover this in lesson 20.4: ruclips.net/video/_1ATaPMZrRQ/видео.html
Hope this helps!
@@ChadsPrep Thank you so much! I should watch that lesson before the exam yesterday :)
The question was Ester carbonyl group attached to O-Ch3Cl
I am not sure if O-Ch3Cl treated as leaving group or not?
ty!
You're welcome!
Thank you! You've helped me get through all of my chemistry classes. Quick question: If the attachments are 2 ethyl groups and a benzine ring, would there still be a 3rd way to synthesize?
If any two of the groups were identical there would only be two ways to produce a tertiary alcohol beginning with a ketone. However, you will learn later in the semester that as long as two of the groups are identical you could actually start the synthesis with an ester and add excess grignard. So in this case if you started with a benzene ester (for example methyl benzoate) and then added two equivalents of an ethyl grignard (aka excess) you would get exactly the same product. This will be presented in lesson 20.4. Hope this helps!
@@ChadsPrep Whoa! I understand it now, super helpful. You are the G.O.A.T.
Thanks!
ur awesome!
Thank you!
Chad you are the best. your vedios are still useful todate ❤️⭕
Thank you!
@@ChadsPrep you are welcome
Continue doing the great work❤️
@@KelvinPhiri750
ofc our professor would want the grignard synthesis 🤡