At the 4:40 mark, you went over the OsO4 in review of the alcohol synthesis reactions. You also used NaHSO3. Instead of using NaHSO3, would it also be possible to use H2O2?
hey thanks for the vid, excellent stuff. just a quick question. the vid said the diff in EN between Al and H is higher than for B and H, making it's Hydrogen more partially negative (at about 18:00 min in the video). I looked at a ptable and saw Boron has an EN of 2 while Al has an EN of 1.61, so Im a bit confused. Should I just ignore the ptable in this specific case?
It wasn't the absolute value of the electronegativity we were looking at, but the difference in electronegativity. For 2 atoms bonded together, the larger the difference in electronegativity, the more polar the bond. Hydrogen has a value of 2.1 (2.2 in some sources). Using your values that would result in an electronegativity difference of 0.1 for the B-H bond and ~0.5 for the Al-H bond. The bigger difference in electronegativity between Al and H indicates a more polar bond (or we could say more ionic character) which is ultimately what I used in the video to explain why it was more reactive. Hope this helps!
ohhhh I gotcha. yep that nails it, I was thinking just magnitudes. great stuff, great vids, I've been going through all of them the past 2 weeks and liking them all. have a great night :D
Being a dyslexic, these videos have been a game changer for me- thanks Chad!
Glad they've helped!
that explanation about oxidation state was superb. i finally understand it. thanks so much.
congrats for 100K subscribers!
Thank you so much 😀
All your videos are extremely helpful, thank you!!!!
Glad you like them, Leona - Happy learning!
Thanks Chad!
You're very welcome!😊
I learned so much more than I had hoped. Thank you, king 🙌
Glad to hear it - you're welcome.
Thank you Chad
Very welcome
AMAZING VIDEO!!!!
Thank you!
Thank you for teaching so complete and great 😍😍
Glad you found this so helpful :)
Really helpful!
Great!
06:52 Is there a way to selectively reduce just the ketone, but not the aldehyde, or vice versa?
At the 4:40 mark, you went over the OsO4 in review of the alcohol synthesis reactions. You also used NaHSO3. Instead of using NaHSO3, would it also be possible to use H2O2?
Absolutely Siddharth! You'll commonly see NaHSO3, Na2SO3, or H2O2 all used after OsO4 in the second step of syn-dihydroxylation.
Thank you 🙏🏾
Most welcome
hey thanks for the vid, excellent stuff. just a quick question.
the vid said the diff in EN between Al and H is higher than for B and H, making it's Hydrogen more partially negative (at about 18:00 min in the video).
I looked at a ptable and saw Boron has an EN of 2 while Al has an EN of 1.61, so Im a bit confused. Should I just ignore the ptable in this specific case?
It wasn't the absolute value of the electronegativity we were looking at, but the difference in electronegativity. For 2 atoms bonded together, the larger the difference in electronegativity, the more polar the bond. Hydrogen has a value of 2.1 (2.2 in some sources). Using your values that would result in an electronegativity difference of 0.1 for the B-H bond and ~0.5 for the Al-H bond. The bigger difference in electronegativity between Al and H indicates a more polar bond (or we could say more ionic character) which is ultimately what I used in the video to explain why it was more reactive. Hope this helps!
ohhhh I gotcha. yep that nails it, I was thinking just magnitudes.
great stuff, great vids, I've been going through all of them the past 2 weeks and liking them all. have a great night :D
Nice, especially the bigger picture
Glad to hear it, Daniel - Happy Studying!
Please reduce your speed of teaching and add some more informations about the catalysts and their names.
Chad, I bet you thought you saw the last of me. I made it to ochem 2
Ha! All the best!