Math Olympiad| Many failed this math question|Algebra.

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  • Опубликовано: 20 сен 2024

Комментарии • 13

  • @devonwilson5776
    @devonwilson5776 3 дня назад

    Greetings. Absolutely intriguing. Blessings.

  • @RyanLewis-Johnson-wq6xs
    @RyanLewis-Johnson-wq6xs 3 дня назад +1

    X^5+X^4+X^3+X^2+X+1=0 X=-1 X=±0.5±0.5Sqrt[3]i=(±1±Sqrt[3]i)/2

  • @key_board_x
    @key_board_x 3 дня назад

    x⁵ + x⁴ + x³ + x² + x + 1 = 0
    (x⁵ + x⁴ + x³) + (x² + x + 1) = 0
    x³.(x² + x + 1) + (x² + x + 1) = 0
    (x³ + 1).(x² + x + 1) = 0
    (x³ + 1³).(x² + x + 1) = 0 → recall: a³ + b³ = (a + b).(a² - ab + b²) → x³ + 1³ = (x + 1).(x² - x + 1)
    (x + 1).(x² - x + 1).(x² + x + 1) = 0
    First case: (x + 1) = 0
    → x = - 1
    Second case: (x² - x + 1) = 0
    x² - x = - 1
    x² - x + (1/4) = - 1 + (1/4)
    [x - (1/2)]² = - 3/4
    [x - (1/2)]² = 3i²/4
    [x - (1/2)]² = [± (i√3)/2]²
    x - (1/2) = ± (i√3)/2
    x = (1/2) ± [(i√5)/2]
    → x = (1 ± i√3)/2
    Third case: (x² + x + 1) = 0
    x² + x = - 1
    x² + x + (1/4) = - 1 + (1/4)
    [x + (1/2)]² = - 3/4
    [x + (1/2)]² = 3i²/4
    [x + (1/2)]² = [± (i√3)/2]²
    x + (1/2) = ± (i√3)/2
    x = - (1/2) ± [(i√5)/2]
    → x = (- 1 ± i√3)/2

  • @HenryEkhator-g9r
    @HenryEkhator-g9r 3 дня назад

    Good

  • @francisamewode233
    @francisamewode233 3 дня назад

    Perfect. Love your class very much.

  • @rajindersingh-jx1xl
    @rajindersingh-jx1xl 3 дня назад +1

    Talented JJ 🎉🎉🎉

  • @RyanLewis-Johnson-wq6xs
    @RyanLewis-Johnson-wq6xs 3 дня назад +1

    It’s in my head.

  • @drashokkumar9209
    @drashokkumar9209 3 дня назад

    X = -- 1