Every Function with a Bounded Derivative is Uniformly Continuous Proof

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  • Опубликовано: 23 июл 2024
  • In this video I prove that every function with a bounded derivative is uniformly continuous. I hope this video helps someone out there who is studying mathematical analysis/advanced calculus.
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    / @themathsorcerer
    Thank you:)

Комментарии • 28

  • @jazmineesparza4152
    @jazmineesparza4152 4 года назад +6

    Awesome. I've been drowning in my class and was praying you'd upload more real analysis stuff. Your videos are seriously the best out there for this course, thank you!!

  • @davidj2452
    @davidj2452 4 года назад +1

    Its so fun to see your thought process! I am taking a class on nonlinear control systems and I never had any background in real analysis or proofs. So seeing how you go through them step by step is a tremendous help!

  • @jake_lizzard9303
    @jake_lizzard9303 4 года назад +1

    Hey fantastic video! I would like to see more videos where you try to prove things on the spot and take us through your thought process like in this video. Have a nice day!

  • @mgarner7439
    @mgarner7439 4 года назад +1

    Thank you for these videos! You are seriously saving my sanity

    • @TheMathSorcerer
      @TheMathSorcerer  4 года назад

      You are welcome, I'm so happy this is actually helping someone:)

  • @learngrowentertain2510
    @learngrowentertain2510 4 года назад +1

    Very Well explained respected Sir. Great explanation...

  • @maxpercer7119
    @maxpercer7119 4 года назад +2

    Uniform continuity is a hurdle I never completely got over.

  • @letpieau1660
    @letpieau1660 4 года назад +1

    Thank you for your video. I am wondering do we need to show f is closed on a closed interval to use MVT, since it is not given.

    • @patrickmederitsch1380
      @patrickmederitsch1380 Год назад +1

      If you assume the domain of f to be the reals, then it follows that f is continuous on the reals, since we know that f is differentiable (this is something you might need to prove). But when f is continuous on the reals, it is for sure continuous on any closed interval, since this closed interval must be contained in the reals. Hope that answers your question.

  • @ratulchoudhury9144
    @ratulchoudhury9144 11 месяцев назад

    Well explained

  • @DineshSingh-qw8oh
    @DineshSingh-qw8oh 3 года назад +3

    Thank you Sir 🤗

  • @NirodhaLL
    @NirodhaLL 4 года назад +1

    Just when i thought i was done with uniform continuity, great video!

  • @chanukyachowdary1252
    @chanukyachowdary1252 6 месяцев назад

    Sir, Is this an if and only if conditions for uniform continuity?

  • @N7_CommanderShepard
    @N7_CommanderShepard 4 года назад +4

    This is why I’m a physics major. I don’t understand proofs haha.

  • @jakepete
    @jakepete 3 года назад

    i'm still unsure why you can use MVT without first proving that it's continuous?

    • @Aman_iitbh
      @Aman_iitbh 9 месяцев назад

      derivative exist means its continous

  • @tanish6035
    @tanish6035 9 месяцев назад +1

    Infact, f becomes lipschitz and hence uniformly continuous.

    • @Aman_iitbh
      @Aman_iitbh 9 месяцев назад

      lipschitz isnt imply diffrentiablity , consider |x| its lipschitz (consider reverse triangle inequality) .u mean to say uniformly cont

    • @tanish6035
      @tanish6035 9 месяцев назад

      @@Aman_iitbh oh yaa, i just wrote it mistakenly, thanks for correction.

  • @HitheshAvishka0215
    @HitheshAvishka0215 2 года назад +1

    You look like JEFF BEZZOS !!

  • @oscardavidalarcon2673
    @oscardavidalarcon2673 4 года назад +1

    Yeah lml