Every Function with a Bounded Derivative is Uniformly Continuous Proof
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- Опубликовано: 23 июл 2024
- In this video I prove that every function with a bounded derivative is uniformly continuous. I hope this video helps someone out there who is studying mathematical analysis/advanced calculus.
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Thank you:)
Awesome. I've been drowning in my class and was praying you'd upload more real analysis stuff. Your videos are seriously the best out there for this course, thank you!!
aww thank you! So happy it is helping:)
Its so fun to see your thought process! I am taking a class on nonlinear control systems and I never had any background in real analysis or proofs. So seeing how you go through them step by step is a tremendous help!
Hey fantastic video! I would like to see more videos where you try to prove things on the spot and take us through your thought process like in this video. Have a nice day!
Will do lots more coming!!
Thank you for these videos! You are seriously saving my sanity
You are welcome, I'm so happy this is actually helping someone:)
Very Well explained respected Sir. Great explanation...
Uniform continuity is a hurdle I never completely got over.
Yes😄
Thank you for your video. I am wondering do we need to show f is closed on a closed interval to use MVT, since it is not given.
If you assume the domain of f to be the reals, then it follows that f is continuous on the reals, since we know that f is differentiable (this is something you might need to prove). But when f is continuous on the reals, it is for sure continuous on any closed interval, since this closed interval must be contained in the reals. Hope that answers your question.
Well explained
Thank you Sir 🤗
You are welcome!
Just when i thought i was done with uniform continuity, great video!
Thanks man!
Sir, Is this an if and only if conditions for uniform continuity?
This is why I’m a physics major. I don’t understand proofs haha.
Haha well physics is hard I think!!!
i'm still unsure why you can use MVT without first proving that it's continuous?
derivative exist means its continous
Infact, f becomes lipschitz and hence uniformly continuous.
lipschitz isnt imply diffrentiablity , consider |x| its lipschitz (consider reverse triangle inequality) .u mean to say uniformly cont
@@Aman_iitbh oh yaa, i just wrote it mistakenly, thanks for correction.
You look like JEFF BEZZOS !!
Yeah lml
😄