It looks like there is a small mistake in your video. Google says 1 pound is 4.44822 newtons, not 4.48 newtons. Having said this, your videos are the best on RUclips for explaining stress and strain (and I have looked at many). Thanks for making them.
Hello, do you have a video on how to solve the force needed in order to cut a hollow pvc pipe with a circular blade? And find the torque in order to choose the right motor for it?
The torque required depends on the radius of the drill bit, the strength of the material being drilled, the thickness of the material being drilled, the friction caused by the material being drilled, and the speed of the rotating drill, (if the drill slows down too much you build up more back EMF).
i think you should input in the shear stress equation 2 Areas in this example because you are shearing 2 areas and not only one (like you did in 9th video with the circle shear example ) so it should be S=F/2A ,could you explain please ?
eeddoonniiss In the "circle" example the shear stress is also: S = F / A The "2" in the equations comes from the circumference of a circle: C = 2 * pi * R
The deformation dx would be in the same direction as the cut before the knife breaks through. h would be the distance from the cut to where the metal begins to bend (away from the cut) before the knife slices through.
We have a few videos here: Mechanical Engineering: Ch 14: Strength of Materials (11 of 43) Ave. Shear Stress ruclips.net/video/Lk9X9-XWfeQ/видео.html ruclips.net/video/PORCdCy2x7c/видео.html ruclips.net/video/I07bnoneFpU/видео.html ruclips.net/video/elQ7htbRMGg/видео.html
You bring up a good point. How that material is supported when cut does make a big difference. If both sides of the material are supported, it will take more force to cut it, then when only one side is supported and the other side is not. it is assumed here that only one side is supported.
I've been asking myself this question for a while and I took a mechanics class. This was very refreshing and honestly incredibly thorough.
It looks like there is a small mistake in your video. Google says 1 pound is 4.44822 newtons, not 4.48 newtons. Having said this, your videos are the best on RUclips for explaining stress and strain (and I have looked at many). Thanks for making them.
Mohamed,
Shearing is not the same as cutting.
Thus it doesn't matter if the blade is sharp or blunt.
Shouldn't the force required to cut off the piece of metal be also dependent on the type of blade being used and it's sharpness?
Hello, do you have a video on how to solve the force needed in order to cut a hollow pvc pipe with a circular blade? And find the torque in order to choose the right motor for it?
We don't have anything that specific.
Related to it perhaps? Still thank you for the reply.
The torque required depends on the radius of the drill bit, the strength of the material being drilled, the thickness of the material being drilled, the friction caused by the material being drilled, and the speed of the rotating drill, (if the drill slows down too much you build up more back EMF).
Where did you get the value of shear stress steel ?
You can find that in any text book or from the internet. There are MANY different types of steel, so there will be MANY different values.
i think you should input in the shear stress equation 2 Areas in this example because you are shearing 2 areas and not only one (like you did in 9th video with the circle shear example ) so it should be S=F/2A ,could you explain please ?
eeddoonniiss
In the "circle" example the shear stress is also: S = F / A
The "2" in the equations comes from the circumference of a circle: C = 2 * pi * R
sir please reply
did u explain Axial load or torsion ?
in this channel
No, not yet.
Thanks a lot, Sir, how to define the shear strain(dt x/L) in this case?
The deformation dx would be in the same direction as the cut before the knife breaks through. h would be the distance from the cut to where the metal begins to bend (away from the cut) before the knife slices through.
Thank you!
Dear Sir
Where can I see the shear stress of the materials. Please help me. Thank you
We have a few videos here: Mechanical Engineering: Ch 14: Strength of Materials (11 of 43) Ave. Shear Stress ruclips.net/video/Lk9X9-XWfeQ/видео.html ruclips.net/video/PORCdCy2x7c/видео.html ruclips.net/video/I07bnoneFpU/видео.html ruclips.net/video/elQ7htbRMGg/видео.html
Why dont we multiply the area by 2 isnt it two pieces that are cut?
You bring up a good point. How that material is supported when cut does make a big difference. If both sides of the material are supported, it will take more force to cut it, then when only one side is supported and the other side is not. it is assumed here that only one side is supported.
dose the blade matter if its sharp or blunt??