Physics - Mechanics: Stress and Strain (12 of 16) Ex. 3: Punch Hole in Steel Plate
HTML-код
- Опубликовано: 7 авг 2024
- Visit ilectureonline.com for more math and science lectures!
In this video I will find the force needed to punch a hole through a steel plate.
sir, what will be the crushing force on the punch by the sheet? will the area taken be πr^2 or simply the circumference of the punch?
I had no option besides subscribing .thanks for the informative videos
If solving for change in x when punching out a hole, would h cover the distance from the hole perimeter to the fixtures, or the hole perimeter to the center of the hole aka radius?
What if you wanted to work out the axial stress of the base of a wall due to its self weight and it’s unit weight of the brickwork being 20kn/m^3
Hi...sir Can you explain about Clearance of punch or Die??? in Punching and Blanking..
thank you! this video helped me understand a hw problem i was having trouble with.
Glad it helped!
sir, that sheared area will be same in blanking operation ? I mean in both punching and blanking operation sheared area is same ? please reply sir
Loved it. I want to thank your wife too for the editing and bringing your work to people who wants to learn all over the world.
Great ... thank you sir
Hello fera Michel
Thanks you sir for your courses
great video again !! Do we also take into account the ductility of the material? Like what would happen if we do the same calculation on composites, composite metals etc. Would this equation would be valid or some other parameters will also come into play?
These methods and equations, do not take into account specific properties of the material. This is just a basic method of solving these types of problems, (just like calculating projectile motion without wind resistance). It teaches us the fundamental properties of materials and gets you close and is typically good enough.
I believe it’s 4.44822* Newton’s a LB , so ~ 58,352 LBs of force .
Yes it is.
Don't know why sir but your videos always solve my problems 💪 thank you sir
That is great. Thank you for letting us know.
So, the material we use to make the hole , must has a large Young's Modulus larger than the shear modulus for the punched material??!!!!!!!!!!!!!
+Thamer Khamais That is correct. That is why industrial diamonds are used for cutting tools.
Thanks, Michel, BTW you doing a great work that creates a big energy to reach the goal.
Hi Sir.
Can you please tell me where is the number 40 com from?
Thanks
Are you referring to: 4.0 x 10^8 ? (the decimal point may be hard to see)
Yes Sir. You said 4.0 that is for shear stress. Would you please tell me where and how I can found this number ?
Thanks you. And Merry Christmas to you Sir.
Hello Michel, could I use this method to design a punching machine? thanks !!
This does indeed calculate the force needed to punch a hole. But then you also need to think about the impulse, which is Force x Time. That means if the punch comes down quickly, the punch applies more force.
@@MichelvanBiezen Thanks a lot !
which physics books do you advice for your students
Thnx for awesome explaining
There are many good physics books available, it becomes a matter of personal preference since they are all good.
@@MichelvanBiezen thanks professor. i am sure about that. I liked your way for teaching so i thought that there are some books you can advice
@@MichelvanBiezen thank you for your kindly answer
@@MichelvanBiezen i spend very significant amount of my day watching your videos.
You are best physics teacher i have ever known
I don't understand where the information for the shear stress came from, or how it relates to the shear modulus.
+TheLordGojira The shear stress of a material can be found in any related reference text or the CRC. Thus the force required to punch a hole in a metal sheet is equal to the shear stress multiplied by the area of the sides of the hole.
Can you help me please, i need shear stress for differents materials
We try to answer questions here whenever we have time.
how did you get sheer stress for steel ?
That is available from text books or the CRC.
okay.. thank you !
why circle area is not pi*r2 sir?
+Hein MT In this case the area is not the area of the circle, but the area of the edge of the circular piece that is cut out. When you stretch it out, it looks like a ribbon, thus its area is length time height.
Thank you.. now I understand. 😂
Thank you
You're welcome
Hi sir
I don't get why at the end you multiply (1 lls/4.48N) to 264,000N great explanation btw!! :)
+fireswamp1
Some people understand pounds better than Newtons as a reference.
oh right ! Thank you :)
Sir why not πr2h is used .
2 x pi x r x t = 2 x pi x r x h as the thickness of the plate can be represented by t or h.
help
What is your question?
@@MichelvanBiezen How do you calculate the force needed for a staple to punch through 30 sheets of office paper?
You would do it exactly the same way as is shown in the video. You will have to look up the shear strength of the paper you are using and 10 sheets of paper is approximately 1 mm thick.
It gives me a bad impression of physics and math teacher when they use calc. for this type of easy calculation.