Transformers -Amp-Turn Balance, Ideal and practical transformers
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- Опубликовано: 13 сен 2024
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I(1)n1 nullyfying l(2)n2
& I(0) maintaining the initial flux
So how can we say
(I(0)+I(1))n1=I(2)n2 ?
she didnt say like that....
Because i0 is very very small 0.2 x i1 ......so its effect is neglegible in the sum of product ixn..
I1n1 nullifies I2n2 only in ideal transformer, where i0 is 0. But in case of practical transformer I1 has to supply for both nullifying and i0. So I1n1 will be equal to I2n2 + ion1. After nullifying only ion1 will be the net MMF.
We can just say like this, The flux which neutralised The flux established by the Io, will be neutralised by the I1, so that N1*I1= N2*I2, so that I0 will again be able to establish the required flux in the core. In short, I0 will always do the job of establishing the flux in the core, and Additional I1 will do the job of power transfer. i.e. V1*I1= V2*I2. Corollary to this that in load case, power transferred is zero, cause I2=0, and ideally I0 is also zero.
non ideal tx param 21:00
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kisi ko call aaya rhega yr class me