For all of you asking how did we get Y outputs: this is actually just an output of any function Y, Y can be whatever function you want. The problem here actually says: find me the function Y, which has such outputs for such inputs. So if function accepts 3 specific inputs, and returns false,then use POS, if true => use SOP
@@israelamanor9127you can apply any rule, you can apply OR operatipn , AND operation or any random operation like A+BC' or A'+BC or A+B'C' etc... depending on your requirements in circuit.
Earlier I thought, that there isn't any good indian channel about computer science , and followed many foreigners.... Now I realise that the gold was within my own country and was searching outside of it 👌.. I didn't expect , really . I am not an engineering student right now , I'm in High school
The number of rows will be 2 (raised to the power of) number-of-variables (ABC)=3. So 8 rows total. The right column (C) will always comprise of 010101... The middle row (B) will be 00110011.... The left column A will be 00001111... If there is a 4th one.. Then it will be eight Zeros and then 8 ones...
Does using the distributive law for the minimal pos or the minimal sop form will yield the other? The minimal sop form of the example is A'C' + B and if we use distributive, it will be (B+A')(B+C') which is the minimal pos form. Is my assumption true or is it just a coincidence in this example?
@@griseldajessica79 A+A'B = (A+A').(A+B) = (A+B) ...[A+A' = 1] ...pls do refer previous lectures make notes and revise..just don't watch it like web series stuff
Late reply... No. The table ie, if 2 variable then no. Of combination is 2^2=4. 2^1 2^0(like place value ) A B 0(start) 0 0 As the first combination is 0 then we Have to add the values of A&B to get the out put as 0. Is only possible when both the values are 0(A) 0(B) A B 0 + 0 = 0 In second combination is 1 it can be Achieved by A is like the 2 digit ( tenth place in normal number system) in binary only 1& 0 is possible therefore A( 2^1) B(2^0- ones place) So the second coloumn sum is 1 so we put A B 0 1 2^1*0=0 + 2^0*1=1 Similarly for 3rd =2 A B 1 0 2^1*1 + 2^0* 0 =2 4th= 3 A B 1 1 2^1*1=2 + 2^0*1=1 =2+1=3 I hope you could understand Value of y (random) :edit
I don't understand why in the very last example in the very end he used made minimal POS form with parentheses instead of just Y=B+A'C'. What is the reason for that?
I AM GETTING TWO DIFFERENT RESULTS FOR FOLLOWING EQUATION QUESTION : Y= A'C' + A'BC + AB WAY-1 Y= A'C' + A'BC + AB Y=A'C' + B (A+A'C) Y=A'C + B(A+C) Y=A'C + BA + BC WAY-2 Y= A'C' + A'BC + AB Y=A'(C'+BC) + AB Y=A'(C'+ B) + AB Y=A'C' + A'B + AB Y=A'C' + B(A'+A) Y=A'C' + B
Thank you i have my exam tommorrow and it helped me
He ducked up!
How was exam 😂?
Me too ❤
I have exam today
Tu yaha bhi 🤣🤣
0:13
0:40 form of minterm
1:44 form of maxterm
2:45 Canonical/standard SOP
5:00 minimal SOP
8:35 Canonical/standard POS
10:20 minimal POS
Who is here, when only one day left for your exams 😀
In other words: any engineer here?
10 minutes left..!👋
@cric8cultz Did you get a good grade? 😂
@@Divin101 Of course bro 😎😂😂
@@Divin101 It's been two years now. I don't even remember that dude 😂🤣
For all of you asking how did we get Y outputs: this is actually just an output of any function Y, Y can be whatever function you want. The problem here actually says: find me the function Y, which has such outputs for such inputs. So if function accepts 3 specific inputs, and returns false,then use POS, if true => use SOP
Same doubt. but no one is ......
What rule is applied to get the output Y
did you find out?@@israelamanor9127
Same doubt how y column written
@@israelamanor9127you can apply any rule, you can apply OR operatipn , AND operation or any random operation like A+BC' or A'+BC or A+B'C' etc... depending on your requirements in circuit.
Sir, there are many excellent tutors on the web, but you are one of the best!
This was well above my expectations. Wow.
iyi dedin kral,wow.
This your tutorial has really been helpful throughout my Digital Design Course.
Thanks for your great Work!
Any one in 2024
Hello its me 😂
Hello hbiibiiii 😂😂😂😂😂
Tomorrow exam 😂
Hi bro
December by the way
I wasn't able to understand those two forms.Thank u very much sir for this clear explanation.I highly appreciate your attempt.
VERY VERY MUCH HELPFUL...THE METHOD AND WAY OF TEACHING IS TOO GOOD....CRYSAL CLEAR UNDERSTANDING
Earlier I thought, that there isn't any good indian channel about computer science , and followed many foreigners....
Now I realise that the gold was within my own country and was searching outside of it 👌..
I didn't expect , really .
I am not an engineering student right now , I'm in High school
8.9k engineering students viewed this :)
Edit: Still counting 👌🏻
Love you all and best wishes for your career!
its 91k
Reuben Mech now the count updated to 145k
Not all are engeering studts.. m in 12th i hve arts 😭😭 nd i hve this compulsary subjct man😭
217,664
242,789> students>150,000
I love Neso Academy ❤️
Thank you very much neso academy this all video lectures is very important and help full in exam.
Im so grateful for this tutorial,this has been my hardest course so far duw tobits complications,but this has been the best lecture so far
Very beautiful explanation sir..hats offf
SIR I HAVE COMPLETED LECTURE 16 OUT OF 202. TREMENDOUS LECTURE AND THANKYOU FOR YOUR GUIDANCE !!
Thank u!!!!!! I stuck in this question for one hour, now I understand
*Now 535k+ engineering students viewed this :)
🤘🏻*
Sir. With ur lectures I had a great and good command on subject. Sincerely speaking we r fortunate to have u sir
Thank you so much, I was incredibly confused by all these new terms
Thx a lot sir......... Words are insufficient❤❤❤
Simply All explanations are Awesome.
Wow. So much has been cleared up for me. Thanks!
Thank u i have exam tomorrow it helps alot
you are my best teacher ㅠㅠ thank you
Nice well done..... But, At 11:36 a dog 🐕 starts barking.... 😂😂🤣
Thanks i have my exam in the next 6mins 😂
much a nice way of delivering lecture. me much thanxful to u sir...
Thanku so much sir... This is a very good lectures...
Thank so much sir explain very well so I get an idea about both of this how to solve
Watching before my exam 😄
Your lectures are soo better
Awesome Explanation Sir! Thanks
Today is my exam and i am here because of you sir.
Your are the best "NESO"
That's awesome )
By the way, do you have any video tutorial that teaches how to create a trust table just from seeing F function?
The number of rows will be 2 (raised to the power of) number-of-variables (ABC)=3. So 8 rows total.
The right column (C) will always comprise of 010101... The middle row (B) will be 00110011.... The left column A will be 00001111... If there is a 4th one.. Then it will be eight Zeros and then 8 ones...
Congratulations for 1M subscribers ⚘⚘
thank's sir a lot
such a great helpful video only for engineer
Great explanation!!!
How do you find Y? I don't get when the result if 1 or 0.
These are random values
Y must be given in order to complete the problems
Bruh Y is based on Minterm Values
Wow! This is very informative, thanks for sharing it with us. It worth it...dl
Love you neso academy ❤️
That's really great I finally got it.Ty
Very helpful viedo thanku so much
Your videos are motivating
Does using the distributive law for the minimal pos or the minimal sop form will yield the other?
The minimal sop form of the example is A'C' + B and if we use distributive, it will be (B+A')(B+C') which is the minimal pos form. Is my assumption true or is it just a coincidence in this example?
No yeah you're right, yours is the absolute minimal, but in sop form cuz of the additions. His way using the paranthesis is the sop form.
Clear explanation thank you😍
Thank you sirr 😂❤ I've exam in the afternoon 🙌🏻icchipadestha igaa
Literally 2 hours left for Exam
Thankyou mam❤
awesome explanation.........!!!!!!!!!!!!!!!!!!!
Thank you bro! @7:07 we can also replace A as A+AB and proceed.
Yes, absolutely right....
Excuse me can you explain please 😭. I still not understand why A+A'B =A+B
@@griseldajessica79 check using truth table
@@griseldajessica79 A+A'B = (A+A').(A+B) = (A+B) ...[A+A' = 1] ...pls do refer previous lectures make notes and revise..just don't watch it like web series stuff
@@deceptivedawwg1111 lol
11:32 how did you simplified by boolean algebra i dont understand (A+B+Cbar)(Abar+B)
Thank you. Well explained
Very informative sir
I DID NOT UNDERSTAND 10:47 . COULD YOU EXPLAIN
Now i watched it♥️🔥
U are awesome man!! Lots of thanks!!
I got it.... thanks NESO academy
2:13 - there should be M(2,4,5)
How? 2 is there
Check properly my friend ur wrong
thank you so much sir.
Thank you so much 💘
This is hilarious it helped me alot
i search how to solve the a + a'b everywhere and i found in here, thx u so much
extremely helpful!!!
it's very helpful sir thanks sir
I join DE lecture in college of 1 hr i didn't get anything...
But in this video Every this is so simple.🤓
i am really your supporter
great video man
Very helpful 👍
learning this at the middle of the night as my professor jump scare an email at the middle of the night that we will have exams tomorrow
Devru guru neenu🙏
How can I make this truth table??I am confused in this....plsss reply and help
the truth table is a given, e.g. by the teacher
Late reply...
No. The table ie, if 2 variable then no. Of combination is 2^2=4.
2^1 2^0(like place value )
A B
0(start) 0 0
As the first combination is 0 then we
Have to add the values of A&B to get the out put as 0. Is only possible when both the values are 0(A) 0(B)
A B
0 + 0 = 0
In second combination is 1 it can be
Achieved by
A is like the 2 digit ( tenth place in normal number system) in binary only 1& 0 is possible therefore
A( 2^1) B(2^0- ones place)
So the second coloumn sum is 1 so we put
A B
0 1
2^1*0=0 + 2^0*1=1
Similarly for 3rd =2
A B
1 0
2^1*1 + 2^0* 0 =2
4th= 3
A B
1 1
2^1*1=2 + 2^0*1=1 =2+1=3
I hope you could understand
Value of y (random) :edit
what are the types of questions for these examples and how to know whether to use the SOP or POS to solve them?
awesome work
This guy is a fucking life saver.
thank you soo much sir,your videos helped me alot :)
love from NEPAL
I don't understand why in the very last example in the very end he used made minimal POS form with parentheses instead of just Y=B+A'C'. What is the reason for that?
thank you very very very very very very very much......... finely now i understand🥱
Minterm sop, check 1,sahi convention,dot ka plus
Maxterm pos,check 0,ulte convention, plus ka dot
Thanks man, helped me alot!
Your explanation is awesome
But it would have been more awesome if you had provided the notes
Btw thank you
I took A' C' common and I got a different answer for the SOP.Is it necessary that we should only try first AB ?
354k engineering students viewed this :)
who was here in February 2019
(^^)
Thank you ❤
sir, will you tell us which one is most simplified expression between sop and pos ?
4 hours left for exam
so tricky to me but a great explanation.
Thanks sir 😊
I AM GETTING TWO DIFFERENT RESULTS FOR FOLLOWING EQUATION
QUESTION : Y= A'C' + A'BC + AB
WAY-1
Y= A'C' + A'BC + AB
Y=A'C' + B (A+A'C)
Y=A'C + B(A+C)
Y=A'C + BA + BC
WAY-2
Y= A'C' + A'BC + AB
Y=A'(C'+BC) + AB
Y=A'(C'+ B) + AB
Y=A'C' + A'B + AB
Y=A'C' + B(A'+A)
Y=A'C' + B
Same here
Thanks but how did you get the 'Y' values
How to implement boolean expression using PLA by :-
F(A,B,C)=Σm(0,3,5,7)
plz explain! 18th aug is my exam nd m stuck on it,,,,
Thanks Neso academy
Ncu wlao attendence lagoo😀😀
Thanku so much 👌
I am watching on the day of my examination 😂😂😂
now it is going to touch 420K mark
thank you :)
is any rule about the values of the function or you take random values?
11:40 i didn't really get it!!
how is it not max term???