isn't there an error at 3:54 , shouldn't Nc = (h2s-h1)/h2a-h1 ? Also i have these common types of questions when they ask to solve for the W(in) for a system usually adiabatic and isentropic but they always seem to exclude the mass, ( W(in) = m(h2-h1) => W(in)= h2-h1 ), this was the question more specifically.......(below) "Air enters a compressor steadily at the ambient conditions of 100 kPa and 22°C and leaves at 800 kPa. Heat is lost from the compressor in the amount of 120 kJ/kg, and the air experiences an entropy decrease of 0.40 kJ/kg·K. Using constant specific heats, determine (i) the exit temperature of the air, (ii) the work input to the compressor, and (iii) the entropy generation during this process. Answer: (i) 85.8 °C, (ii) 184.1 kJ/kg, (iii) 0.0068 kJ/kg.K."
I very much appreciate how much information you pack into these short episodes. I have referenced your videos in several of my design projects and you genuinely help me understand relationships that are not emphasized in traditional textbook form. Thanks for what you do!
I will try to follow the whole thermodynamics playlist and hopefully I will finally pass this subject next year! My issue is I quickly lose oversight and dont practice nearly enough.
Isentropic compression is the ideal process that requires least amount of work input. But why isothermal and polytropic compression has lower work between same pressure limits?
Minor Correction: 4:40 The schematic of a turbine should show the gas expanding, not compressing (right side should be larger than left side).
isn't there an error at 3:54 , shouldn't Nc = (h2s-h1)/h2a-h1 ? Also i have these common types of questions when they ask to solve for the W(in) for a system usually adiabatic and isentropic but they always seem to exclude the mass, ( W(in) = m(h2-h1) => W(in)= h2-h1 ), this was the question more specifically.......(below)
"Air enters a compressor steadily at the ambient conditions of 100 kPa and 22°C
and leaves at 800 kPa. Heat is lost from the compressor in the amount of 120 kJ/kg, and
the air experiences an entropy decrease of 0.40 kJ/kg·K. Using constant specific heats,
determine (i) the exit temperature of the air, (ii) the work input to the compressor, and
(iii) the entropy generation during this process. Answer: (i) 85.8 °C, (ii) 184.1 kJ/kg,
(iii) 0.0068 kJ/kg.K."
I very much appreciate how much information you pack into these short episodes. I have referenced your videos in several of my design projects and you genuinely help me understand relationships that are not emphasized in traditional textbook form. Thanks for what you do!
I will try to follow the whole thermodynamics playlist and hopefully I will finally pass this subject next year! My issue is I quickly lose oversight and dont practice nearly enough.
Your videos are awesome, I was scared when I saw that you were not uploading anymore. I am very happy to see you again :)
This is very helpful, thanks!
Fantastic! Please say what is the App you use for your videos. Samsung Notes?
All i know is he uses iPad, he mentioned it in a comment on some video
@@mayurdahiwale5907 yes, he mentioned that he uses the notes app on the ipad.
You drew the argon turbine as a compressor (5 min mark), great job on all these btw!!
Sorry, saw you made the correction
What is difference between isoentropic efficiency and thermal efficiency..
Isentropic compression is the ideal process that requires least amount of work input. But why isothermal and polytropic compression has lower work between same pressure limits?
Polytropic means both pressure AND volume are changing. Poly = multi
W
How tf am I paying thousands for shitty material when I can get it here for free & explained 1000000x better.