E2 reaction (vid 3 of 4) using chair conformations for anti coplanar reactions

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  • Опубликовано: 19 ноя 2024

Комментарии • 30

  • @indianchika123
    @indianchika123 5 лет назад +13

    you really made me understand everything, i wish i discovered your videos before i failed my first two tests D:

    • @Leah4sci
      @Leah4sci  5 лет назад +3

      Well, it's never too late! Browse through my channel for more videos. :)

  • @bobababe3766
    @bobababe3766 5 лет назад +4

    Thank you so much for the explanations. I literally just spent an hour trying to understand my notes in class and this helped clear up the concept a lot more

    • @Leah4sci
      @Leah4sci  5 лет назад +1

      Awesome, I'm glad it cleared it up for you!

  • @chrisnmai7744
    @chrisnmai7744 7 лет назад +1

    I've struggled so hard to understand chair conformations, and this video has helped me get a grasp on it, as well as E2 reactions. Honestly my studying for my orgo final later today would have been futile without these videos; thank you so much!!

    • @Leah4sci
      @Leah4sci  6 лет назад

      Glad I could help! You are very welcome

  • @anteater2536
    @anteater2536 9 лет назад +5

    thx miss, your videos have saved my life.

    • @Leah4sci
      @Leah4sci  9 месяцев назад

      You're welcome, I'm glad to hear I helped!

  • @shanemckinley4563
    @shanemckinley4563 7 лет назад +2

    I was still able to use your domino effect you mentioned in another video. Because it's trans, still moving in one direction, Domino's can fall even going up steps (in my head) but not in cis because dominos cannot go up, and turn around, and continue to go up, that would be asking too much ! So to speak. Thanks again ! Ready for school now.

    • @Leah4sci
      @Leah4sci  7 лет назад

      Whatever helps you remember! Glad I could help :)

  • @MrZg1982
    @MrZg1982 4 месяца назад

    Hi Leah, thanks for the video. You meant to say "place the pi bond between C1 & C2" because in your video, you said "place the pi bond between C2 & C3."

    • @Leah4sci
      @Leah4sci  4 месяца назад

      I'm having a hard time finding the audio error that you mention. At 8:46, I say that we have the pi bond between carbon 1 and 2. If I mention it otherwise for that example at any point in the video, please disregard. :)

  • @FearMemory
    @FearMemory 10 лет назад

    Your vids are very thorough. Much appreciated.

    • @Leah4sci
      @Leah4sci  9 месяцев назад

      You're so welcome!

  • @Noseqquiero
    @Noseqquiero 7 лет назад

    In all honesty, the first explanation confused me. I understood after you abbreviated it at the end. But all the same, it did help.

    • @Leah4sci
      @Leah4sci  7 лет назад

      Thanks for your feedback. I'm glad you were able to get it in the end!

  • @joeburreaux7953
    @joeburreaux7953 3 года назад +1

    @Leah4Sci What do you do if it's an E1 reaction but it involves cyclohexanes with the wedges and dashes? Do you just not have to worry about anticoplanar? Thanks!

    • @Leah4sci
      @Leah4sci  3 года назад

      E1 has a carbocation intermediate. C+ is sp2 hybridized and thus planar (flat) this means the position of the leaving group is less important

  • @jasper_vs
    @jasper_vs 7 лет назад

    When you are talking about the solvent you say it is polar protic and thus favours E2 above Sn2. But the solvent can 'cage' the nucleophile in an E2 reaction as well. So why is E2 still preferred?

    • @Leah4sci
      @Leah4sci  7 лет назад

      Even when a base (not nucleophile) is caged in E2 it's still reactive. A caged OH- ultimately grabs an H from the 'cager' H2O turning one of those into OH- and through a domino effect you get an OH- getting close enough to the molecule to grab an H. The identify of the base won't change if dissolved in its own conjugate acid solution. ie Methoxide in methanol, ethoxide in ethanol, hydroxide in water...

  • @jaysea9104
    @jaysea9104 2 года назад

    what if youre provided a chair conformation that has the leaving group in the equatorial position?

    • @Leah4sci
      @Leah4sci  2 года назад +1

      Since the final product is an alkene with sp2 hybridized carbons, there will be no longer be any axial or equatorial positions on the leaving group's carbon. (Review around 8:00 in this video.) However, you will need to verify that the beta hydrogen is in an antiperiplanar position before proceeding with the reaction.

  • @SchmidtFamilyEst.1981-we6zm
    @SchmidtFamilyEst.1981-we6zm 2 месяца назад

    Could you simply go off of sterics? A methyl is less sterically hindered than a methyl making it easier for a base to attack a hydrogen?

    • @Leah4sci
      @Leah4sci  Месяц назад

      At which point in the video? (you mentioned methyl vs methyl so I don't understand your question)

  • @sameerkhnl1
    @sameerkhnl1 10 лет назад

    Leah i'm wondering is the direct method not easier? i.e. if we draw the wedge dash projection for hydrogens and considering the unidirectional flow of electrons or does this not work in other examples?

    • @joeburreaux7953
      @joeburreaux7953 3 года назад +1

      It's better but what if the professor gives you only the chair conformation? You need to be able to recognize both forms.

  • @suzanadamaseni7513
    @suzanadamaseni7513 5 месяцев назад

    ❤❤❤

  • @dianthe5756
    @dianthe5756 Год назад

    i love you

    • @Leah4sci
      @Leah4sci  Год назад +1

      Haha, compliment received. Thanks for watching!