Solved Example: Hydrostatic Forces on a Vertical Gate

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  • Опубликовано: 28 авг 2024
  • MEC516/BME516 Fluid Mechanics: A simple solved exam problem of hydrostatic forces on a flat vertical gate. The solution includes locating the line of action i.e, the center of pressure.
    All of the videos in this course, sample exams with solutions, and a copy (pdf) of this solution can be downloaded at www.drdavidnayl...
    Minor Correction: There is a "typo" at 6:46. h_cg=2.8m (not 1.8m) . But the value of y_cp and the problem answers are all ok.
    Course Textbook: F.M. White and H. Xue, Fluid Mechanics, 9th Edition, McGraw-Hill, New York, 2021.
    #fluidmechanics #fluiddynamics #fluidstatics

Комментарии • 36

  • @shenanigansonyoutube2901
    @shenanigansonyoutube2901 6 месяцев назад +10

    In 7 minutes I have learned more about Fluid Mechanics than I have in an entire semester so far with my professor. Thank you.

  • @schwabioso
    @schwabioso Год назад +11

    thx for the video-
    little mistake at 06:48, hcg=2,8m !

    • @FluidMatters
      @FluidMatters  Год назад +8

      Thanks. Yes That's a "typo". The value of y_cp is correct. I will make a note of this correction in the description. That's probably better than deleting this video. Thanks again.

    • @naveedrehman6083
      @naveedrehman6083 5 месяцев назад

      true

    • @FranciscoJLI
      @FranciscoJLI 2 месяца назад

      OMG no way i just three hours until i just saw your comment.

  • @Amanda-le8qe
    @Amanda-le8qe 10 месяцев назад +3

    thanks for the video though was very well explained, i understood it immediately as opposed to my lecturer that rambled for 2 hours straight

  • @Amanda-le8qe
    @Amanda-le8qe 10 месяцев назад +21

    me attemping to learn this at 3 am and my exam is in 5hours 😪😪

  • @dramoyoedward9229
    @dramoyoedward9229 10 месяцев назад +1

    Very clear explanation...thanks🙏

  • @Jaciatel
    @Jaciatel 11 дней назад

    Can you please explain why the yp or the hp is different for vertical surfaces that protrude from the surface or whose tops are levelled with the surface compared to when the surface is below water?

    • @FluidMatters
      @FluidMatters  11 дней назад

      I'm not sure I understand your question. The height of the centroid (h_cg) is the distance measured from the liquid surface. The centre of pressure (y_cp) is the distance below the centroid. A portion of the surface that protrudes above the liquid has no effect, because there is no hydrostatic pressure above the free surface.

  • @vihanga4141
    @vihanga4141 Год назад +2

    Very well explained

    • @FluidMatters
      @FluidMatters  Год назад

      Thanks. Glad to hear it was helpful.

  • @MaximusLX
    @MaximusLX 11 месяцев назад +1

    Thanks for this, very clear explanation

    • @FluidMatters
      @FluidMatters  11 месяцев назад +1

      Glad to hear it was helpful.

  • @aitorag1114
    @aitorag1114 8 месяцев назад

    well explained, thank you.

    • @FluidMatters
      @FluidMatters  8 месяцев назад

      Glad to hear it was helpful

  • @abdullahoz7813
    @abdullahoz7813 9 месяцев назад +1

    At the end, Why did we write 1.8 intead of 2.8 ?

    • @FluidMatters
      @FluidMatters  9 месяцев назад

      See the comment in the video description.

    • @abdullahoz7813
      @abdullahoz7813 9 месяцев назад +1

      Thanks ✋🏻

  • @sindiswahadebe1070
    @sindiswahadebe1070 9 месяцев назад

    For the last question why is the equation not : ycp = Ixx/hA +h

    • @FluidMatters
      @FluidMatters  9 месяцев назад +1

      ycp is measured from the center of gravity, not the free surface. It's the the distance from the h_cg, with the negative sign indicating its below the cg. So, the distance from the free surface to the center of pressure is h_cg + abs(y_cp). I hope that helps.

  • @gameoboy2
    @gameoboy2 8 месяцев назад

    How would I go about finding the reaction forces at points A and B?

    • @FluidMatters
      @FluidMatters  8 месяцев назад

      Basic statics: Once you have the horizontal force at B, then set the sum of the forces in the x-direction equals zero to get F_Ax and set the sum of the forces in the y-direction equals zero to get F_Ay. Actually, F_Ay is zero by observation.

  • @A.Hisham86
    @A.Hisham86 7 месяцев назад +1

    Well, I was expecting you to use the prism way to resolve it too. :)

  • @AJMusicUganda
    @AJMusicUganda 6 месяцев назад

    thanks . please share the link for the first culculation videos.thanks

    • @FluidMatters
      @FluidMatters  5 месяцев назад +1

      All the videos are available at my website www.drdavidnaylor.net I hope that helps.

  • @violetgray4264
    @violetgray4264 8 месяцев назад

    02:05 , free surface has Pa, a little correction i think??

    • @FluidMatters
      @FluidMatters  8 месяцев назад +1

      No correction is needed because Pa also acts on the right side of the gate. So, the effect of atmospheric pressure cancels out.

  • @_AlfiansyahMalikN
    @_AlfiansyahMalikN 10 месяцев назад

    I'm confused, why is the value of Ixx divided by 12?

    • @FluidMatters
      @FluidMatters  10 месяцев назад +1

      The second moment of area of a rectangle about a horizontal axis through its centroid is the width*height^3/12. Google "second moment of area of a rectangle"

  • @HashemAljifri515
    @HashemAljifri515 5 месяцев назад

    What is the distance 1.8 meters??

    • @FluidMatters
      @FluidMatters  5 месяцев назад +1

      In the video description: Minor Correction: There is a "typo" at 6:46. h_cg=2.8m (not 1.8m) . But the value of y_cp and the problem answers are all ok.

    • @ambroseongom5345
      @ambroseongom5345 3 месяца назад

      I was looking for the correction. Thanks for the correction