actually E=A/V whereE= eq.wt, A=at. wt., v = valency.. i have solved according to question... there is divalent so i directly put the value instead of telling the main formula ..Sorry for that. (time=13:29).
Dai plz plz yo question gardinu na 1 gram of divalent metal was dissolved in 25ml of 1M H2SO4 The unreached acid further required 15 cc of NaOH (f=0.8) for complete neutralisation .calculate gram equivalent weight of unreached acid and atomic mass of metal
You were so much confused while explaining,You should try speaking more fluently in next video. Anyway,This video was so much help for me| Thanks for the video.
Bro video explanation ko Saath upload gar diye Keep watching and if get any doubt in video comment it we will try our best to clear it.. Thank you #arjunmahato
Please try to read questions more times and convet into your local language so that you can understand the given clues in the questions and also try to relate formula on the basis of given data. Thankyou
actually E=A/V whereE= eq.wt, A=at. wt., v = valency.. i have solved according to question... there is divalent so i directly put the value instead of telling the main formula ..Sorry for that.
actually E=A/V whereE= eq.wt, A=at. wt., v = valency.. i have solved according to question... there is divalent so i directly put the value instead of telling the main formula ..Sorry for that. (time=13:29).
Thanks
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Thanku thanku thanku dear brother thanks alot ekdam clearly buje thanku for helping us
No need to go soo deep but your effort are very helpful thinks dai...👏👏🥰
Dherai ramro xa keep up👍
ramro x vedio sab bhughiyo aru pani halnu la dada
Nearly nearly sabai patterns solved xhaa ...timi sanga kunai questions xhaa bhane cmnt garfai gara laa bro
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Bahut accha bhai ji.....2nd part kahiya ayet
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Second part uploaded
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So helpful vedio dai tq..
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12:27 tira (40/1000)-(50/1000) ta negative ma value aauxa ta i.e. -10^-3 aauxa ta k ho
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welcome bro, keep supporting and sharing videos with friends 😊😊
Dai plz plz yo question gardinu na
1 gram of divalent metal was dissolved in 25ml of 1M H2SO4 The unreached acid further required 15 cc of NaOH (f=0.8) for complete neutralisation .calculate gram equivalent weight of unreached acid and atomic mass of metal
Watch out all the patterns are here : ruclips.net/p/PLAeHHjAOyVQDeskONMhePGytEAKj5gguU
Sir Need more Chemistry12 videos as soon as u can...
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Awesome 👍🏻
You were so much confused while explaining,You should try speaking more fluently in next video.
Anyway,This video was so much help for me|
Thanks for the video.
Thank you for the suggestion, I have tried my best in new video, please check it out 😊
thank you very much balla bhuje jasto bhayo ajhai videos haru haldai garnu hai
Aajhai video haru ni aauxhaa keep watching hai ❤️❤️❤️
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What volume of 5 Percentage Naoh are required to neutralize 2 lit of decinormal H2SO4 . Dai yo.kaserii garni ho
Bro video explanation ko Saath upload gar diye
Keep watching and if get any doubt in video comment it we will try our best to clear it..
Thank you
#arjunmahato
Bro ani yo question xaiina ni ta video ma
#Ask;volumetric analysis numerical Bala video xhan no bro tyo yehi qué hi...2:50min Bala
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Bro part1 ma ho
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Ionic equilibrium banaduna na yaar please
Next video will be on ionic equilibrium
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Question kasari bhujera solve garne ho
Please try to read questions more times and convet into your local language so that you can understand the given clues in the questions and also try to relate formula on the basis of given data.
Thankyou
R ko value mileko xaina bro 0.0821 hunxa answer 74.48 aauxa
Bro,R=0.0821 nai ho , calculation garda decimal pachi ki digit xhutaye ra teti aako ho,you can take whole value 0.0821, Thanks' for suggesting ❤️❤️
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13:29 wrong concept of ew
actually E=A/V whereE= eq.wt, A=at. wt., v = valency.. i have solved according to question... there is divalent so i directly put the value instead of telling the main formula ..Sorry for that.
thank you for the feedback @anoopdhakal
Your teaching skills is too boring
Thanks dai
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