Thank you sooo much for explaining how to deduce the unknown variable mathematically...my professor is excellent but conveniently skips over these parts so I either have to go in for tutoring or am stuck. This really helped, as usual. You rock!
I just wasted 30 minutes trying to read and figure out how to do this and here you come again saving me with epic 20 second explanation, Thank you so much!!!
Hi, I just wondering how did you get p2= p1.e^(-dh/R).(1/t2-1/t1)? if ln(p2/p1) = lnp2- lnp1. how is it possible when P1 changed the side has multiplied by e^(-dH/R).(1/t2-17t1)? . Thanks very much Sir.
Here in the equation, we have an enthalpy of vapourisation and we have two state 1 and 2. So which latent heat should we need to consider state 1 enthaply or state 2 enthalpy. Please help me in this doubt.
Isn't the enthalpy of vaporization changes depending on the temperature? How come there is just one value of enthalpy of vaporization between two different temperatures?
So when using the equation to find P2, the exponents to "e" are all divided by R? He found T2-T1, then multiplied by 24000 (Hvap), THEN divided by R. However, the equation was written as Hvap/R * (1/T2-1/T1)... Our tutor found 1/T2-1/T1, multiplied by Hvap, then divided by R, which would be (Hvap*(1/T2-1/T1)) / R as the exponent to e ... if someone can clarify that would be super helpful! Thx!
So question... How to know whether to use the very first (base equation) and when to use the other equation to find another pressure. The questions look the same when I looked it up.
The molar heat of vapourisation of water is 9700cal/mol, what's the vapour pressure of 5 moles of water at 90°C (given that vapour pressure of 1 mole of water at 100°C is 78mmHg and the gas constant is 1.987cal/mol. Someone should please help with this question.
P1 is the pressure at the start with T1. When you change either P1 or T1 it becomes the second parameter of its kind. If you cange the temperature, the temp. you change it to becomes T2 with its own pressure P2
Hi I've watched your videos and I've a question. I've examination in physics about a vacuum boiling water experiment by manipulating the pressure to a low point so the water in the bowl starts boiling at a low temperature. I've tryed to find some table or calculator that can somehow demonstrate that the result I've found is close to what we can see in tables eg. Are there any calculators (tryed to find some but they didn't work) or law that I can refer to? I hope that you can help? Best regards Mowaddat
The 10^-3 is how many places the decimal goes to the left. The 0.003225 is the same number as 3.2*10^-3. It’s just in scientific notation instead of standard form. If, for example, the number were 3225.00 then the scientific notation would be 3.225*10^3.
It'd have been smarter to show the passages from the first formula to the others, and not giving all the formulas like they are different. What's the sense of learning all of them, you just need the first and you need to know how to reverse it. but yeah, just my opinion
Final Exams and Video Playlists: www.video-tutor.net/
Someone that finally tells me how to use the equations instead of the theory behind it
I would like to know whereby that equation is derived
@@nuclearrambo3167 ight lil nigga... ur done😭
This guy is good. calm. good pace. clear. Thanks for lending your talents.
My body gets filled up with peace every time i watch one of your videos.
You have literally helped me in Calculus 3 and Chem II. You're amazing.
I LOVE YOU CHEM BAE
I have a midterm tomorrow, and this is way better than my professor teaching it in over an hour.
Hello Brian, can you please teach me how did he get 28.6 torr? :(((
@@graceremo5724 he did 21 times e raised to 0.31037
You help me with Calculus AND Chemistry? What can't you do? Lol
show his face
History
Organize his videos so they follow any kind of curriculum
Thank you so much. I kept seeing different formulas and never understood why it changes, I was so confused. You are the only one that explained this!
Thank you sooo much for explaining how to deduce the unknown variable mathematically...my professor is excellent but conveniently skips over these parts so I either have to go in for tutoring or am stuck. This really helped, as usual. You rock!
I just wasted 30 minutes trying to read and figure out how to do this and here you come again saving me with epic 20 second explanation, Thank you so much!!!
your videos are truly life saving!!
You've just saved me, i have my exam in two days and i was STRUGGLING with Clausius 😭😭😭 thank you so much
You are the best tutor in chemistry thank you❤
Thank you so much. If only my professor explained things half as well as you do.
Great video.....started this in class today..... Thank you for making this topic easier to understand 📚👩🏽💻🤓
Thank you so much mister. From this channel i can learn for my olympiade contest 😭
THIS MAN IS THE BEST OH MY GOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Hi, I just wondering how did you get p2= p1.e^(-dh/R).(1/t2-1/t1)? if ln(p2/p1) = lnp2- lnp1. how is it possible when P1 changed the side has multiplied by e^(-dH/R).(1/t2-17t1)? . Thanks very much Sir.
Yezzirrrrr ! Took my forever to get my answer correct finally got it after this video.
You rock! If I get a great grade on my test, I'm going to owe it all to you
Thank God that you and this video exist!!!!
Noah Garcia god is make believe.
Thank you, but how do we calculate for T1 if we only had the pressure and the enthalpy of vaporization?
I tried to solve for T2 a bunch myself...and failed. It's been 30 years since I had to do this. Lots of searching for this came up empty. Thank you.
Thank you so much, you really helped me out, greetings from Mexico!
YOU MADE THIS SO EASY THANK YOU!!!!!!!!!!!!!!!!!!!!!!!!!!
i don't know why, but not even my teacher could get me to understand this bs, thanks bro!
Gracias bro joder
Great video. Thank you
Thank you so much, man
Same method of calculating though we are using the R constant as 8.314 giving me a final answer of 22
You are a lifesaver! Thank you
Thanks
How did you get the -2.9737 from dividing this? I am confusion.
If I have a child I will talk them you're legend.
Good explanation
you saved me AGAIN. thank you.
Why is R negative when solving for enthalpy of vap? When I convert the original equation I have a positive R
this really helps a lot
Thank you Chemistry Bae
Thank you so much, all clear
I have a question. If the pressure given in pascal, do we have to change to torr?
One pascal is equal to 0.00750062 torr
@@CSReeves987 so we must use torr as the unit. Just continue calculate in pascal cannot?
Thank you soooo much ,God bless u🤍
Thank you so much 🌹 ❤
Very helpful! Thanks
very good thank you so much
I got 20.3 torr for the question. How did you get 28.6 torr?
So helpful ! Whats the tutor`s name please?
Thank you so much
meu deus você é um divoo obrigada 💕💕💕💕💕💕
Thank you.
You’re the best!!!
thank you so much !!!you are a life saver
Here in the equation, we have an enthalpy of vapourisation and we have two state 1 and 2. So which latent heat should we need to consider state 1 enthaply or state 2 enthalpy.
Please help me in this doubt.
you are a ver help! thanks for the T2 clearance :)
What of the case that we have the formula as InP=-∆H(1/T)/R + C for graphical function
Is it correct or wrong,
Pls Explain
Isn't the enthalpy of vaporization changes depending on the temperature?
How come there is just one value of enthalpy of vaporization between two different temperatures?
So when using the equation to find P2, the exponents to "e" are all divided by R? He found T2-T1, then multiplied by 24000 (Hvap), THEN divided by R. However, the equation was written as Hvap/R * (1/T2-1/T1)... Our tutor found 1/T2-1/T1, multiplied by Hvap, then divided by R, which would be (Hvap*(1/T2-1/T1)) / R as the exponent to e ... if someone can clarify that would be super helpful! Thx!
How do you raise it the negative 1 power to get kelvin? Im working with a Ti-30xa Calulator.
So question... How to know whether to use the very first (base equation) and when to use the other equation to find another pressure. The questions look the same when I looked it up.
Thank you soooooo much!!!
The molar heat of vapourisation of water is 9700cal/mol, what's the vapour pressure of 5 moles of water at 90°C (given that vapour pressure of 1 mole of water at 100°C is 78mmHg and the gas constant is 1.987cal/mol.
Someone should please help with this question.
Nice video dude
Wrong R value for the first problem? We are using torr so shouldn't R = 62.36 L*torr / (K*mol)
Thank you
Thanks!!
Thanks🤩🤩
How did you get from [3.7026x10^3]^-1 to 270K?
On your calculator there should be a button that says (1/x). Click that and you’ll get the same result.
@@Love-wy8pf chem made me realize that idk how to use a calculator
How can I solve for boiling points at different pressures?
Is there a equivalent formula that describes the transition in between liquid to supercritical states?
Can pressures also be taken as atmospheric pressures?
so helpful!!
How do you determine which pressure is either P1 or P2?
P1 is the pressure at the start with T1. When you change either P1 or T1 it becomes the second parameter of its kind. If you cange the temperature, the temp. you change it to becomes T2 with its own pressure P2
R is multiplied by 2.303 or is it?
Is the same equation all the time... Why you called different forms of the equation?
Hi
I've watched your videos and I've a question. I've examination in physics about a vacuum boiling water experiment by manipulating the pressure to a low point so the water in the bowl starts boiling at a low temperature. I've tryed to find some table or calculator that can somehow demonstrate that the result I've found is close to what we can see in tables eg.
Are there any calculators (tryed to find some but they didn't work) or law that I can refer to?
I hope that you can help?
Best regards
Mowaddat
very helpful so I like it
you are clutch
I dont understand how you got 1/310= 3.2*10^-3? I got 0.003225
The 10^-3 is how many places the decimal goes to the left. The 0.003225 is the same number as 3.2*10^-3. It’s just in scientific notation instead of standard form. If, for example, the number were 3225.00 then the scientific notation would be 3.225*10^3.
GRACIAAAAAAAAASSSSSS
como se pone en la calculadora
para que salga 3.70263x10ex-3 y tambbien 270.1k
What is e?
same question huhu
at 6:50 how did you determine the e value?
calculator
e is a constant my dude: 2.718...
It'd have been smarter to show the passages from the first formula to the others, and not giving all the formulas like they are different. What's the sense of learning all of them, you just need the first and you need to know how to reverse it. but yeah, just my opinion
Can some one explain to me how i got 21.66 torr instead of 28.6 at 7:03
I was wondering the same thing tbh
🙌🏾🙌🏾🙌🏾 respect
1 kJ is "about" 1000 J? ABOUT???
nice
I keep getting 15.40 torr.
3:06
Is this still high school level or undergrad?
Hermann KLEIN-HESSLING undergrad
Thanks....
Isn’t it p1/p2
Wait I still don't understand...
Really thought the R was the gas constant. Now I know why I failed my test :(
IT IS gas constant, not the universal gas constant.
@@910suck What do you mean? The R he used in this video was the universal gas constant (8,3 J/K mol).
what is 'R' at there ,ı dont know cause this vid is not in my language
hm okay raydberg constant
@@kaanakyuz7402, it's not the Rydberg constant, it's the universal gas constant.
R is called the ideal gas constant or universal gas constant ; R=8.314 J/mol or it can be R=0.08206 atm*L/mol*K
Gyanesh se kisko nhi smjha fitjee jha2
Wait a minute what is C
urgh am I the only nerd who gets mad when ppl say a kilo joule s ABOUT 1000 joules No it is EXACTLY 1000..
Claucius is my ancestor. It’s pronounced Claw-Shus