#855

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  • Опубликовано: 21 окт 2024

Комментарии • 53

  • @MsStrej
    @MsStrej 2 года назад +2

    Wow, it’s so obvious yet I wouldn’t thought of it without your video, thanks!

  • @ruhnet
    @ruhnet 3 года назад +2

    Fantastic---what a helpful use of the simple A-B function!

  • @vincei4252
    @vincei4252 3 года назад +26

    With the usual reminder that the ground lead needs to go to ground unless the scope is isolated from the thing being measured. This is for those that have the Eureka! moment and think why can't you just put the leads across the component :-)

    • @TonyBarr99
      @TonyBarr99 3 года назад

      Thank you Vince! You read my mind.

    • @robertmontgomery3892
      @robertmontgomery3892 3 года назад

      @@TonyBarr99 Ditto

    • @BradKwfc
      @BradKwfc Год назад

      Dont BLOW your scope brah!

    • @davidahmad6090
      @davidahmad6090 Год назад

      Here it seems he is using the two voltage probes in a sort of diferencial Mode, so it is my beleif that there is no need to connect the ground probes at all, just the probe tips. Also i thought this method only works when the resistor is on the low side of the circuit, i.e. one side of the resistor Connected to ground?

  • @alocin110
    @alocin110 2 года назад +1

    Excellent demonstration of an intelligent technique. Thank you for sharing. I liked your video.

  • @shawncalderon4950
    @shawncalderon4950 3 месяца назад

    An excellent presentation!

  • @fiorenzo6301
    @fiorenzo6301 2 года назад +2

    How did you get thin traces like this? Because on my oscilloscope, the same rigol mso5000 you have, them are thick and full of noise. Without avaraging i cannot get the same visual result as you but you don't seem to use avaraging. Thanks

    • @IMSAIGuy
      @IMSAIGuy  2 года назад +2

      I don't remember on this video. The scope is very fast so it shows lots of noise on traces. I also use averaging a lot and reduce the BW to 20MHz depending on what I am doing. Good grounding helps of course.

  • @RicardoPenders
    @RicardoPenders 3 года назад

    Cool, thanks for sharing... This is a very useful video.

  • @BrendaEM
    @BrendaEM 2 года назад +1

    Thank you for the video. Recently, I found a gotcha, in that I was trying to use my function generator output to pick off the voltage across a resistor to sense the current for the Y axis to trace a transistor curve, but I couldn't because both instrument BNCs are grounded. My first clue: it picked off the voltage without the ground lead attached. This is why--even an old isolated, low voltage transformer works as the lowest form of curve tracer, yet my function generator would not work that that (re)purpose.
    While I am not optimist that the 1054z would accept the output of a math function as y-axis component of the XY, this video was food for though. Thank you for the video.
    It's iconic that the old scopes had a built-in trace function, but a modern digital scope doesn't. : P
    An isolation transformer would have fixed this problem, but some people do die from 115v AC, and well, the BNC jack is indeed metal and well the switcher has 90vDC in it, which I likely would hold onto for the rest of my short life. Still, I hate the specter blowing up my equipment because grounds are connected.
    There are curve tracer kits, but I am on a very limited budget.

    • @nithinks4047
      @nithinks4047 11 месяцев назад

      What should be the value of resistor to sense the current perfectly....

  • @davidahmad6090
    @davidahmad6090 Год назад

    Great video sir, i am wondering if you connected the ground clips, logic tells me you did not, becuase you are using both volage probes in a sort of differential configuration. Can you use this method on a resisor at any location in the circuit or is it just on a low side resistor, with on side connected to ground ?

    • @IMSAIGuy
      @IMSAIGuy  Год назад +1

      I think it best to connect the grounds. you can use resistors on the high side as well

    • @davidahmad6090
      @davidahmad6090 Год назад

      @@IMSAIGuy Very interesting, thank you sir.

  • @rajaqamar06
    @rajaqamar06 11 месяцев назад

    Question: Patch a RC circuit and connect it to AC input voltage source. DIsplay the voltage waveform of capacitor voltage and waveform of capacitor current simultaneously without using MATH mode of the oscilloscope. Use oscilloscope only to get the desired result.

  • @dohack
    @dohack 5 месяцев назад

    this is with square wave as input from function generator. What if want to measure current drawn by a MCU or BLE chip like STm32wb55rg powered by battery. I don't have Power Profiler. Just an oscilloscope 100 MHz 4 channel and multimeter. I want to measure 200nA to 1A current measurement range. any tip or IC suggestion ?

    • @TalpaDK
      @TalpaDK 3 месяца назад

      One tip... Get the nRF power profiler

  • @waterfuel
    @waterfuel 2 года назад +1

    Is 6 amps AVERAGE DC current on hand held multi-meter, or panel meter,, the same as PEAK 6 DC amps on oscilloscope? I thought it was a 60% difference.

    • @IMSAIGuy
      @IMSAIGuy  2 года назад

      DC is constant voltage/current. there should be no difference between average and peak unless there is a lot of noise on the DC. then the peak would be a very small amount more.

  • @avi-brown
    @avi-brown 2 года назад +1

    Thanks for this! I am interested in measuring the current draw of an entire circuit (battery powered) over a few seconds. Could I treat the entire circuit as the "resistor" (load), connect probes to the + and - of the battery, subtract the 2nd signal, and then convert to amps by dividing the voltage by the circuit's equivalent resistance (assuming it is constant over sleep / active cycles, which I need to check)? Or maybe I should introduce a very small (shunt?) resistor in series with the + or - terminal the battery and measure across that resistor in parallel...?

    • @IMSAIGuy
      @IMSAIGuy  2 года назад +2

      no, you would be measuring across the battery in parallel with the circuit. you need to have a resistor in series

    • @avi-brown
      @avi-brown 2 года назад +1

      @@IMSAIGuy Thanks. So a resistor in series with, say, the positive terminal would work? Any recommendations for going about deciding what size resistor to use?

    • @IMSAIGuy
      @IMSAIGuy  2 года назад +1

      @@avi-brown ruclips.net/video/cFcwHVppu3w/видео.html

    • @IMSAIGuy
      @IMSAIGuy  2 года назад +2

      pick a resistor that allows a good measurement and can handle the current. be wary of the burden voltage.

    • @avi-brown
      @avi-brown 2 года назад

      @@IMSAIGuy Thanks so much.

  • @BenFreemanDC
    @BenFreemanDC Год назад +1

    Did yo someone input the value of the resistor into the Oscope? I still don't see how you can get the current measurement from those 2 probes. i understand from the probes you get Va-Vb = Vab but then Ohm's law says you still need the resistor value to get the current.

    • @IMSAIGuy
      @IMSAIGuy  Год назад

      you need to read the resistor color code or look at a schematic for that.

  • @iliakotliar7723
    @iliakotliar7723 3 года назад +1

    If I use differential probe: do I get same results ?

    • @IMSAIGuy
      @IMSAIGuy  3 года назад

      yes. most diff probes are for high voltage, so you will have problems at low levels. low voltage diff probes are quite expensive

    • @EfieldHfield_377
      @EfieldHfield_377 3 года назад

      Poor man diff probe is A - B. Two things i could never bring myself to buy for my lab, A diif probe and a good current probe. The current probe more than anything is what I miss, not greedy if i had something up to 10MHz, but alas i have a cheap bk 300kHz probe, and a sense resistor every now and then. Some day i will buy that probe. Thx for sharing.

  • @mu8502
    @mu8502 2 года назад

    hi can I use 150 MHz probe on 50MHz oscilloscope?

    • @wilburnurbil9848
      @wilburnurbil9848 Год назад

      It depends, but probably. Try it. If it adjusts properly when using your scope probe adjustment square wave then you're go to go.
      If the input capacitance of the scope falls within the adjustment range of the probe then you should be fine. Example, Tektronix 2225 50MHz scope has an input capacitance specified at 25pF, plus or minus a couple pF. A Tektronix P6130 probe has a -3db bandwidth of between 150 - 250MHz depending on probe cable length. The probe specification says it will be happy with scopes between 10 to 30 or 35 pF, again depending on cable length, so should work well.
      The 350MHz probe that comes with the Rigol MSO5000 series scopes is specified to handle scope inputs of between 10 and 25pF. It might not adjust properly to the Tek 2225 where it's right at the limit. The Rigol probe should be fine with a Tektronix 2215A (for example) which has a 20pF input capacitance and a 60MHz bandwidth.

  • @niknam.
    @niknam. 8 месяцев назад

    that's right ONLY if you know the resistors true resistance! but if you not?

    • @IMSAIGuy
      @IMSAIGuy  8 месяцев назад

      Then it's a more difficult day

  • @giostechnologygiovannyv.ri489
    @giostechnologygiovannyv.ri489 Год назад

    what if the circuit is an op amp made up out of many MOSFET's and no resistor to measure? ^^''

    • @IMSAIGuy
      @IMSAIGuy  Год назад

      you will need to unsolder parts of the circuit.
      1. use current meter
      2. use clamp on probe
      3. add a low ohm resistor and do as per video.
      4. there are very expensive probes that I have never used that can detect current in traces.

    • @giostechnologygiovannyv.ri489
      @giostechnologygiovannyv.ri489 Год назад

      @@IMSAIGuy Thanks for the answer!! :D

  • @ammarbasrah1362
    @ammarbasrah1362 Год назад +1

    Show this connected plz

  • @peterjohnson5586
    @peterjohnson5586 Год назад

    Resistors have +/- tolerances.

  • @sammin5764
    @sammin5764 2 месяца назад

    🌷

  • @jj74qformerlyjailbreak3
    @jj74qformerlyjailbreak3 2 года назад +1

    My old scope has Analog add function. No subtract but what can I say, it’s from the late 60s.

    • @IMSAIGuy
      @IMSAIGuy  2 года назад +1

      no problem, you had to just invert one channed

    • @jj74qformerlyjailbreak3
      @jj74qformerlyjailbreak3 2 года назад

      @@IMSAIGuy I was thinking that but my channel 2 is out so I couldn’t test my thinking at the time. Thanks for confirmation
      Great channel.

  • @jdmccorful
    @jdmccorful 3 года назад +3

    If you have the correct scope?

    • @mavamQ
      @mavamQ 3 года назад +1

      I think most scopes will do A + B. To get A - B, you need to invert B. (I think, I haven't used the function for a while)

    • @vincei4252
      @vincei4252 3 года назад +1

      @@mavamQ Yeah, a lot of scopes have an invert and add function. My old tek 2465B has this. There's no "math" since the 'calculations' are done in the analog domain.

    • @jdmccorful
      @jdmccorful 3 года назад

      Thanks for the info.

    • @vincei4252
      @vincei4252 3 года назад

      @@jdmccorful np

    • @frankowalker4662
      @frankowalker4662 3 года назад +2

      My digital scope dose'nt have any maths functions. LOL.