Electrolysis of Copper Sulphate Using Copper Electrodes
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- Опубликовано: 21 ноя 2012
- A SIMPLE explanation of Electrolysis of Copper Sulphate Using Copper Electrodes. Understand how to perform the Electrolysis of Copper Sulphate, and the chemical equation behind it. You can read more about Electrolysis of Copper Sulphate at: www.electrical4u.com/principl...
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Electrolysis is an electrochemical process by which current passes from one electrode to another in an ionized solution that is an electrolyte. In this process, positive ions or cations come to the negative electrode or cathode and negative ions or anions come to the positive electrode or anode.
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Thank you so much sir you explained the whole in just 2 minutes 🙏🏻
The cathode is negative as it attracts the positive cations.
You should not use postive word with cation as cation itself refer to positive ion.
@@theFalcon_1 I know it is redundant but I put positive there so students who are unaware would understand why cations are attracted to the cathode.
Why do the amps in my current start high but then drop to 0 shortly after?
I have the electrolyte solution using copper sulfate, and a positive and negative copper bar. I'm at a loss
this would be correct if it was molten but it is aqueous so you need to deal the the OH and H ions
Thanks
So guys, I have seen a lot of misconception and hate towards this guy in the comment section. If the electrolysis of copper sulphate was done using inert electrodes such as carbon, copper ion would get discharged at the cathode because it is less reactive than hydrogen. As for the anode, oxygen gas would be given off, 4OH- = O2 + 2H2O + 4e-. But in this video, copper electrodes are being used meaning they are going to take part in the electrolysis. I hope this helps. If you have any further question, do let me know. I will be glad to help. Edit: One more thing, if the metal is more reactive then hydrogen, hydrogen ion will be given off at the cathode, and if a halide ion is present (Cl-, Br-, F-, I-) it will be given off at the anode instead of Hydroxide ion (This is true for all aqueous solutions but in case of dilute solution, even if a halide ion is present, OH- ion will be always discharged at the anode)
Wait, why there are still copper at the anode, if all the cations go to the cathode and all the anions go to the anode? And how about the H+ and OH-? Because this is aqueous, not molten. I'm curiously want to know about the electrolysis, but I'm puzzled after I watched your video.
This is an active electrode 🙃
Copper is less reactive than hydrogen
Thank you sir 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
that's actually wrong because if it's a "dilute" Copper (11) Sulphate the electrolyte should include the H2O ions which is broken into H+ and OH-, which means it will have a totally different result because there are two negative ions and two positive ions, and there are some rules to which ions should go to the cathode and which ions should go to the anode.
I agree, the video is wrong!
Actually its not aqueous cuso4 so,h+ and oh- are not present.
Also cuso4 is in its soild form(blue coloured compound)
Ya copper goes first to cathode but oh doesn’t goes to anode cause anoid is ionising
By the look of your comment you prolly didn't understand the topic yet :/
You didn't mention the hydrogen ions and hydroxide ions from water... You need to revise this again. Copper sulfate can't form at one of the electrodes. The direction of electron flow you demonstrated is the opposite.
Thank you so much Sir
Lit mate
Legends watch this in 2023❤❤
you didnt explain why the cathode increases in mass and the anode decreases in mass
this is wrong you forgot about the OH- ions and the H+ ions
@Another Bigfoot with internet access He did mention that it was dissolved in water so yea it's aqueous
Bro this is an active electrode and OH- and SO4- doesn't discharge .__.
Water will not dissociate here into H+ and OH-
Although it wasnt mentioned, at the Aqueous solution, ions present in the electrolyte is hydrogen ion, copper ion, sulphate ion and hydroxide ion. At cathode, the two possible cations that can be discharged is either copper ion or hydrogen ion. Since copper is less reactive then hydrogen, therefore copper iom is being discharged instead of hydrogen ion. At anode, anions that can be discharged is either hydroxide ion or sulphate ion. Since sulphate ion is difficult to discharged, hydroxide ion is being discharged. Hope this helps🙂
@@niccoleanndreajaena7946thanks
Allah razo olsun ya hiçbir yerde yok aw şu deney .hintliler yetişti yine yardıma
yea like that tell me fucking alot
Flow of electron arrow is wrong.
no
PANK
wait i learnt that the anode is negative and the cathode is positive ???
Nicholas Joubert no its da reverse
you probably learnt it as anions being negative and cations being positive but switched them when it came to electrodes, since anions are attracted to anode, the anode is positive and since cations are attracted to the cathode, the cathode is positive, because opposites attract
sorry cathode is negative***
That is true for a galvanic cell.
It's not correct for every cell
This is wrong
Its wrong
You should correct your spellings ^.* :):)
You are wrong my g
he is right g
this could very much be the most useless chemistry tutorial i've ever watched
To be honest this video lacks so much info, I wouldn't recommend it☹️
Not helpful at all
This video has a lot of lack of information and provides a lot of misconceptions.
Very bad