You are very thorough and your way of explaining things really helps understand these things better. Thank you so much for creating something like this, with so much depth, detail and clarity. I really appreciate the effort. So do thousands others, I'm sure. Keep going!
Thankyou So Much. You can see the quality of your video is that much good that students like us are still watching this even after 8 years approximately from the date of upload👍👍Very Good and Appreciative work👏👏
This is too damn helpful in clearing concepts rather than any boring and lenthy lectures we were going through the college.........points are clear ..this vedios made my head clear ......which was full of many confusions....thanks alot to person who's performing such a wonderful job.....
Sir you are saviour... Try spreading these videos on other platforms also so that more and more people can benefit from it... Thanks once again sir... Keep making such awesome videos... You saved my prelims
You substituted an equation into the emitter current equation of cb configuration and then proceeds to says that the emitter current equation of ce has changed,wonderful!
Even my teacher cant explain so well.. . I wasnt able to understand bjt in 1-2 hour of my lectures. But i am watching it and umderstanding it very easily. Is it really that simple? No, you are too amazing explainer. Apologies for bad grammar,
Thank you so much sir ... It's difficult for an average student to understand this things in a tution batch of 80+ , ( I feel I am not perfect for science but watching this I gain my confidence .. I want to know physics thanks)
OMG. Come to Turkey and see how this lectures going on :) Teachers love only exams. They always want do exams only. I think their names should be changed from teacher to examer :)
If we want to reverse bias the base and collector , why we connected the voltage between emitter and collector but not at base and collector. Please give me a detailed explanation.
Great video! To anyone who can answer, what makes the equation Ic = B(Ib) + (B+1)Icb unique to common emitter configuration? Near the end he compares the reverse saturation currents of common emitter and common base configurations in active mode, but compares them using equations derived from i and ii. Couldn't you have derived the same equation for common base configuration?
Icb is like nano-amperes, so even if B is 400, (B+1)*Icb could go to half of 0.1mA whereas B(Ib) is huge because Ib is in mA(at least). Therefore (B+1)*Icb is neglected w.r.t. B(Ib). Fair enough?
The equations are common for both circuits but difference comes when we see what is input current and input voltage. The output current is compared with respect to the input current. In case of common emitter , the input current is Ib whereas in case of common base , the input current is Ie.Thus two equations tho are co derived but used differently while comprehending the different transistors mode. Correct me if I am wrong!
@7:03, u said if alpha is less than 1, range of beta is 50 to 400, which is nt the case. The value decreases from 50, further down, which u had just calculated.
@1:21 you told that negative terminal is connected to p but actually it is getting connected to n type. So can i consider one n-side getting connected to positive terminal and one to ground as reverse bias condition. Correct me if am wrong
Because the value of alpha is close to one, ideally it is 1 but in real cases it is between .099 to 0.998. Calculate B for these range of alpha and you’ll see the result in concurrence with what is taught in the video. Here, B comes 19 because alpha is hypothetically taken as 0.95
1:13 how Collector and base are revesed baised externally when there is no physical connections between them , also there is a depletion region between base emitter . Could you please sir
How negative terminal of COLLECTOR-EMITTER VOLTAGE is connected to p-type? It is seen that negative terminal is connected to the common emitter junction which is n-type then how can we say that the negative terminal of CE voltage is connected to p-type as you have mentioned in 1:24.. please explain Sir...
at 6:43 how can we say alpha is the amplification factor while Ic = beta Ib + (1+beta) Icbo here clearly the output current, Ic is beta times input current, Ib. Shouldn't beta be the amplification factor? Thanks in advance.
Sir at vedio time 1:20 while doing REVERSED BAISED collector terminal is connected to positive of the battery. BUT where the negative is connected how to understand sir PLEASE TELL SIR I AM HAVING THIS doubts please sir reply 😢
there is a dought in above tutorial...,In reverse bias there is both output terminals are connected to n-type material ,then how should we go for connection of reverse bias ...?
Sir can you please explain how the collector base junction getting reverse biased because we are applying vtg Vcc to collector and emitter. Awaiting for your reply. Thanks.
Well done sir,great video! May i ask you a question? I see in a lot of videos that in the switch operation of a transistor we always connect a dc motor for example, between the Vcc and the collector. Where is the mistake in connecting the dc motor between emmiter and ground. PS You explain electronics better than a lot professors in universities
maybe because Base and emmiter are forward biased hence it have a voltage drop of 0.7V, so that amount of voltage might be insufficient for operation of DC motor
Why for the output is the positive terminal connected to n-type and negative terminal to p-type, but in the input positive terminal is connected to p-type and negative to n-type?
why there is a collector-base junction in common emitter transistor? why isnt emitter common in both junctions? what does the word "common" mean in CET?
u giving input between base and emitter, getting output between emitter and collector , biasing of collector and base Vbc is different.. vce (output)= Vbe+ Vcb
you said that leakage current contribution is more in common emmitor configuration than common base configuration but what is the reason behind it theoritically
Sir collector base junction should be in reversed bias but we are giving supply voltage Vcc in collector emmiter .Then how can be say that collector base junction is reverse bias .
in case of CB configuration with npn transistor, although CB junction is reversed biased for majority charge carrier(electrons), it is forward biased for thermally generated minority charge carrier(holes). So, even if the emitter is open, there is minority charge flow from collector to base with emitter open. this current is Icbo(**leakage current**)(collector to base current with emitter open). likewise in CE configuration with npn transistor, despite Ib=0, it is found that there exits a current from collector to emitter, Iceo(**leakage current**)(collector to emitter current with base open). since Iceo = (beta + 1) Icbo and also ones
I am not convinced , see why , cause actually equation we used to get beta which is ( IE=IC+IB) is applied in all configuration if it was an active mode so we used eq for substitution in another eq .and the first eq is applied in all cases , we can use it in any case cause KCL law ( IE=IC+IB) is applied in active mode .so what we did is just some mathematics , how can we conclude that leakage current in CE>>in CB ??
in common base configuration the leakage current is obtained between base and collector junction and in common emitter configuration the leakage current is between emitter and collector when base emitter junction is open circuited . Since, base is small so the no. of minority charge carriers are very less while in emitter the no. of minority charge carriers are higher. So, greater the no. of charge carriers is , greater is the leakage current. Hence, emitter has greater leakage current.
sir, to operate in active mode CB junction should be in reverse bias; but why connected 2nd biasing voltage negative terminal to emitter terminal.. It should be connected to Base terminal...???
Sir but in this diagram how CB junction getting RB from looking it look like RB happening between COllector and emitter. Means Vcc is connected between emitter and collector
Beta can be any value for power transistors only (which can operate up to 10 amps or even more...however if beta is less than 5 , then controlling the transistor would be difficult ) whereas for electronic transistors which deal with smalls current.... Beta have to be between 50 to 400 ....
Let's take IB =1mA and amplifying factor (beta)=49, and R-output = 5kohm, V_output = 49x1mAx5komh = 225V emmiter is used in current amplification, what about this result ?; Or beta amplify both current and voltage?
how can the reverse saturation current in common emitter configuration be different from common base configuration? the reverse saturation current shouldn't depend on external factors like voltage sources, right?
thank you , why we say that CB-J is r-b when we can't connect the negative side of Vcc to the base , how can i under stand this concept? ,,,,,thank you again
One of the best lectures I ever had.
All The Concepts Are Well Explained.... These videos made me fall in lovve with Electronics. Thank You So Much Sir.....
Icbo bta do kya hai
@@DoctorSiblings Leakage Current in Common Base configuration. Check Lecture 65 and 66 for more info
Who is watching this one day before semester exam??😂😁
Same her bro today
We gather here 😂😂😂
I am watching 2 hr before the semester 😅
No need to ask 😂
Me 😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😁😭😭😭😭😭😭😭😭😭😭😭
This entire series is just awesome! Wonderful example of selfless efforts and quality!
hello , you there ?
@priyanshjoshi8605 yes
@@johnmctavish1021 what are u doing now ?
@@priyanshjoshi8605 I'm project Manager now.
@@johnmctavish1021 in India?
Which company ?
You are very thorough and your way of explaining things really helps understand these things better. Thank you so much for creating something like this, with so much depth, detail and clarity. I really appreciate the effort. So do thousands others, I'm sure. Keep going!
My lecturer didn't explain this very well, so I was still confused, but you did a great job explaining this topic! Thank you very much!
Thankyou So Much. You can see the quality of your video is that much good that students like us are still watching this even after 8 years approximately from the date of upload👍👍Very Good and Appreciative work👏👏
This is too damn helpful in clearing concepts rather than any boring and lenthy lectures we were going through the college.........points are clear ..this vedios made my head clear ......which was full of many confusions....thanks alot to person who's performing such a wonderful job.....
I couldn't able to understand these points ever through worthless college lecturers
amazing teaching...specially without any time waste....and superb content❤❤🔥🔥
@Neso Academy, you all are doing a great job. Your lectures have helped me clear basics of many subjects.
Keep Going. All the Best
Sir you are saviour... Try spreading these videos on other platforms also so that more and more people can benefit from it... Thanks once again sir... Keep making such awesome videos... You saved my prelims
You substituted an equation into the emitter current equation of cb configuration and then proceeds to says that the emitter current equation of ce has changed,wonderful!
Is that the way you talk to your teacher?
You saved my semister
And you wasted ur vocabulary (semister)
Yeah
I read it sister😂
Same @@BhumiDahiya584
Sachin sir...u are the best explanator...aap bht ache se hr topic cover krte ho...koi confusion nhi rhti....tquuu sooo much sir...
Even my teacher cant explain so well.. . I wasnt able to understand bjt in 1-2 hour of my lectures. But i am watching it and umderstanding it very easily. Is it really that simple? No, you are too amazing explainer.
Apologies for bad grammar,
You're doing god's work!
True
Exactly right
Agreed 💯
Man he opened my eyes with this lecture
It is a very nice video.The lecture is very clear.I am so happy.Thank You Sir
This is so darn useful, mate I was getting so confused about common emitter amplification but now I understand the way of the amplification
Sir you are 'God of Engineers'
Thank you so much sir ... It's difficult for an average student to understand this things in a tution batch of 80+ , ( I feel I am not perfect for science but watching this I gain my confidence .. I want to know physics thanks)
OMG. Come to Turkey and see how this lectures going on :) Teachers love only exams. They always want do exams only. I think their names should be changed from teacher to examer :)
Same here in India
Very same here in Bangladesh as well
you are a god to me man 😭😭😭 in my clg i didnt understand electron devices topic but after seeing this i am now clear in this thank you 😍😍😍😍😍
Thanks a lot sir u saved my semester. Your videos are simply awesome .
Hi bro how did engineering go?
Hey,
It went great. Full of memories. How is your going or is it completed ?
@@deepeshAcharya ah that's so nice..I'm in my 2nd year of extc engineering
@@rushabhjain8598 Cool All The best !!!
@@deepeshAcharya thank you so much
Which college were you in?
Can't appreciate your hard work sir
I salute you
good work sir🔥💥💥keep going
Your lectures have made this subject so easy for me
Really sir thanks a lot
Great work🤍
One of best lectures. Thank u so much sir
If we want to reverse bias the base and collector , why we connected the voltage between emitter and collector but not at base and collector.
Please give me a detailed explanation.
Great video! To anyone who can answer, what makes the equation Ic = B(Ib) + (B+1)Icb unique to common emitter configuration? Near the end he compares the reverse saturation currents of common emitter and common base configurations in active mode, but compares them using equations derived from i and ii. Couldn't you have derived the same equation for common base configuration?
Icb is like nano-amperes, so even if B is 400, (B+1)*Icb could go to half of 0.1mA whereas B(Ib) is huge because Ib is in mA(at least). Therefore (B+1)*Icb is neglected w.r.t. B(Ib).
Fair enough?
The equations are common for both circuits but difference comes when we see what is input current and input voltage. The output current is compared with respect to the input current. In case of common emitter , the input current is Ib whereas in case of common base , the input current is Ie.Thus two equations tho are co derived but used differently while comprehending the different transistors mode.
Correct me if I am wrong!
@Sarath Paradox dropped out engineering. This was 2 years ago. Good luck. You might as well drop out, it's not worth it.
Sir at time 3:40 in the video... you have written alpha IE..... is this alpha current amplification factor
Bhai sequence no.. dall do aapki video me.. video bhout shandaar hai . Ekdam top class
In 7:14
How can u get (B+1)Icbo = Iceo?
thanks anyway.
@7:03, u said if alpha is less than 1, range of beta is 50 to 400, which is nt the case. The value decreases from 50, further down, which u had just calculated.
Yes, I think it should be less than 50
@1:21 you told that negative terminal is connected to p but actually it is getting connected to n type. So can i consider one n-side getting connected to positive terminal and one to ground as reverse bias condition. Correct me if am wrong
in 5:16
How can u get alpha/(1-alpha) = beta?
thanks anyway.
Sir u told bita is in range of 50 to 200 . But in the example bita comes 49 and 19 for Alfa= .98 and .95 respectively. Can you please explain ?
Because the value of alpha is close to one, ideally it is 1 but in real cases it is between .099 to 0.998. Calculate B for these range of alpha and you’ll see the result in concurrence with what is taught in the video. Here, B comes 19 because alpha is hypothetically taken as 0.95
Amazing explanation 🙏❤️
Thank you so much to helping me in this chapter 👽😙.
I really appreciate your work!
1:13 how Collector and base are revesed baised externally when there is no physical connections between them , also there is a depletion region between base emitter . Could you please sir
I have cleared my back log of been tnxx sir😀
Finally a good explanation
How negative terminal of COLLECTOR-EMITTER VOLTAGE is connected to p-type? It is seen that negative terminal is connected to the common emitter junction which is n-type then how can we say that the negative terminal of CE voltage is connected to p-type as you have mentioned in 1:24.. please explain Sir...
at 6:43 how can we say alpha is the amplification factor while Ic = beta Ib + (1+beta) Icbo
here clearly the output current, Ic is beta times input current, Ib. Shouldn't beta be the amplification factor?
Thanks in advance.
still this videos are worthy. thnx GOD
Thank you sir ❤️
thnk u sir 4 ur lctrs....i m rlly oblg 2 u...my cncptns r clrd by ur lctrs.....
thnks a lot sir n neso academy
Raksha Prasad do you speak English?
Sir at vedio time 1:20 while doing REVERSED BAISED collector terminal is connected to positive of the battery. BUT where the negative is connected how to understand sir PLEASE TELL SIR I AM HAVING THIS doubts please sir reply 😢
1:24 sir both are n type . so how to decide .
Awesome explanation
If Ic is the output current, why is it going towards the same direction as the Input current (Ie)?
there is a dought in above tutorial...,In reverse bias there is both output terminals are connected to n-type material ,then how should we go for connection of reverse bias ...?
I liked your explanation
very nice explanation'
3:35 what is I cbo in 2nd equation?
Collector base current when emitter is open
Sir can you please explain how the collector base junction getting reverse biased because we are applying vtg Vcc to collector and emitter. Awaiting for your reply. Thanks.
jutla vasantha Yes thats what i feel is difficult to digest . Can someone plz explain this .
jutla vasantha
good
VCC is diffrent and Vcb is different
He has missed one thing that Vcc>Vbb which will make CB junc. rev. biased.
Good explanation SIR
nice lectures...
you are awesome man!!!
Nice explanation
Best lectures
Well done sir,great video!
May i ask you a question? I see in a lot of videos that in the switch operation of a transistor we always connect a dc motor for example, between the Vcc and the collector. Where is the mistake in connecting the dc motor between emmiter and ground.
PS You explain electronics better than a lot professors in universities
maybe because Base and emmiter are forward biased hence it have a voltage drop of 0.7V, so that amount of voltage might be insufficient for operation of DC motor
sir why at 3:02 output current is Ic not Ie
sir, I didn't understand how we got range of beta is 50-400. Please explain. You are doing a really great job and letting us understand things easier.
It depends on transistor. Alpha value will be around 1.
how does the CB junction gets reverse biased if we connect the negative terminal to the n type material?
Why for the output is the positive terminal connected to n-type and negative terminal to p-type, but in the input positive terminal is connected to p-type and negative to n-type?
Please upload videos on transistor common emitter and common collector amplifiers
You way of narrating is like Sal Khan of Khan academy.
Woah...the best explanations
The video is 4 years ago but still he hearts the comments
this was so helpful can u do another video same transistor but as a switch please????
could u please upload videos of the ebers moll model of bjt and bjt amplifier configuration
dear sir I want a question that how a transistor operates at saturation region will u explain ... please I have a doubt on this saturation region
What is the advantage of common emitter configuration over common base configuration......
In collector emitter junction both terminal are n-type....so how you choose positive nd negative terminal for reverse biasing ?
Is collector emitter junction even possible? For all I know there's base in between and such a junction doesn't exist.
Sir why we are not using minus sign in first EQ means Ie=-ic-ib
Which transitor configuration is mostly used for auido amplifier
Very useful video sir
What is leakage current?
And what is the difference between Icbo and Iceo? Please tell me...
I want to ask which book you referred while creating these lecture series?
Is tgere no resistance gain in common emiiter config. Pls show characteristics of this config as well. Thanks.
why there is a collector-base junction in common emitter transistor?
why isnt emitter common in both junctions?
what does the word "common" mean in CET?
u giving input between base and emitter, getting output between emitter and collector , biasing of collector and base Vbc is different..
vce (output)= Vbe+ Vcb
you said that leakage current contribution is more in common emmitor configuration than common base configuration but what is the reason behind it theoritically
Sir collector base junction should be in reversed bias but we are giving supply voltage Vcc in collector emmiter .Then how can be say that collector base junction is reverse bias .
Great content and teaching but it would be great if changed ur Background white 😊 I think it's better for eyes
Is Beta applicable only for this CE configuration?, because in CB configuration, Alpha is only applicable in the said configuration
can u plz explain transistor as a switch
sir plz provide leacture on ELECTROMAGNETIC THEORY for ENGINNERING student
how we can threotically prove that leakage current in common emitter configuration is more than that in common base configuration
in case of CB configuration with npn transistor, although CB junction is reversed biased for majority charge carrier(electrons), it is forward biased for thermally generated minority charge carrier(holes). So, even if the emitter is open, there is minority charge flow from collector to base with emitter open. this current is Icbo(**leakage current**)(collector to base current with emitter open).
likewise in CE configuration with npn transistor, despite Ib=0, it is found that there exits a current from collector to emitter, Iceo(**leakage current**)(collector to emitter current with base open).
since Iceo = (beta + 1) Icbo and also ones
I am not convinced , see why , cause actually equation we used to get beta which is ( IE=IC+IB) is applied in all configuration if it was an active mode so we used eq for substitution in another eq .and the first eq is applied in all cases , we can use it in any case cause KCL law ( IE=IC+IB) is applied in active mode .so what we did is just some mathematics , how can we conclude that leakage current in CE>>in CB ??
@@RahmaElsaeed-cf6ru Note that in CE configuration, I (CEO) incorporates the I sub E term. That is how you get Beta in the first place.
in common base configuration the leakage current is obtained between base and collector junction and in common emitter configuration the leakage current is between emitter and collector when base emitter junction is open circuited . Since, base is small so the no. of minority charge carriers are very less while in emitter the no. of minority charge carriers are higher. So, greater the no. of charge carriers is , greater is the leakage current. Hence, emitter has greater leakage current.
Please tell me the app you used here
sir, to operate in active mode CB junction should be in reverse bias; but why connected 2nd biasing voltage negative terminal to emitter terminal.. It should be connected to Base terminal...???
Great Work! Keep it up!
Sir but in this diagram how CB junction getting RB from looking it look like RB happening between COllector and emitter. Means Vcc is connected between emitter and collector
sir if alpha is from 0.95 to 0.98 then beta will be between 19 to 49 .then how can be range of beta will be from 50 to 400.waiting for your reply
Beta can be any value for power transistors only (which can operate up to 10 amps or even more...however if beta is less than 5 , then controlling the transistor would be difficult ) whereas for electronic transistors which deal with smalls current.... Beta have to be between 50 to 400 ....
Still waiting for a satisfactory answer by the channel
I think so. He suddenly wrote 50-400 and did not explain why.
why you can not put ie=ib+ic equaction in the common base configuration ic equaction .....?
Let's take IB =1mA and amplifying factor (beta)=49, and R-output = 5kohm,
V_output = 49x1mAx5komh = 225V
emmiter is used in current amplification, what about this result ?; Or beta amplify both current and voltage?
very nice your lecture
how can the reverse saturation current in common emitter configuration be different from common base configuration? the reverse saturation current shouldn't depend on external factors like voltage sources, right?
thank you , why we say that CB-J is r-b when we can't connect the negative side of Vcc to the base , how can i under stand this concept? ,,,,,thank you again
Minority charge carriers have large effect in CE configuration... can we take this as advantages or disadvantage....
How (B+1) I cbo = I ceo ??? Pls explain