In common-base configuration, the base is common to the input and output circuits. The collector current is approximately equal to the emitter current, with a small base current. Key moments: 00:05 Transistors have three configurations: common base, common emitter, and common collector. Common emitter configuration is widely used due to its advantages in amplifying weak signals in active mode. -Explanation of common base configuration. Base is common to input and output circuits, facilitating signal amplification in active mode. -Operation in active mode. Transistor has two junctions: Junction j1 forward biased (diode EB) and Junction j2 reverse biased (diode BC) for signal amplification. -Comparison with diodes. Transistors are two-port devices with input (ie, V B II) and output (IC, V CE B) characteristics, unlike single-port diodes. 05:10 Understanding the proper nomenclature in transistor circuits is crucial for accurate representation. Kirchoff's current law helps derive key equations for active mode operation and current gain, essential for analyzing transistor behavior. -Importance of following proper nomenclature in transistor circuits for accurate representation of voltage and current. -Deriving key equations using Kirchoff's current law for active mode operation and understanding current gain in transistor circuits. -Explaining the significance of alpha as the common base current gain and its implications on emitter and collector currents.
The best of the best!!! This video is simple yet knowledgeable; and the teacher gives you some valuable information that most other teachers neglected to mention.
Thank you for uploading videos with such clear explanations. It's a kind request to you sir that please upload practicals on electronics like digital gates using IC's.
in vk mehta book, nomenclature of Vbe is opposite , it confused me and i opened this lecture to clear my confusion , my confusion is now totally clear ! Thank you so much Sir ! greetings from Bangladesh
Thank u, twas really conceptual and eliminating out confusions. I liked the way, you drew Vcb and Vbe later in the circuit and gave understanding of its terminals. Most of the lectures i found previously, they seemed to mug up the circuit diagram without and explanations and then explain just the results, that too in a confusing way.
Sir. We r fortunate to have ur lectures seriously... Thanks a lot. Sir y emitter should be highly doped as well as base is lightly.? What's d reason behind it. Plz tell me sir.
Base is lightly doped so that there is less recombination in it and more charge carriers are able to pass to the collector region. The emitter is highly doped to get large number of charge carriers in forward bias.
@@raghuyuva start from scratch. Everything is available on the RUclips. And there is pretty sufficient time to prepare for it. Watch the videos,make schedule and you will be good to go.
This video are really helpful for me . I watching this video from Bangladesh . And I am the student of Gazipur Technical school and college, and my trade is Electrical works and maintenance.
sir,wonderful lecture of ur's helped me in solving many doubts of transistor and pls..... upload working of low passand high pass filters also.......... thankyou for ur lecture
I cbo means the reverse saturation current in common base configuration when the emitter terminal is open ( battery across emitter is disconnected). I ceo means the reverse saturation current in common emitter configuration when the base terminal is open ( battery across base is disconnected). Both I cbo and I ceo are very small so they can be interchanged. Because later we have to ignore thier value anyway.
Your videos really very clear,. Thanks for your this videos., These are very helpful me for Ugc Net Exam.. But ,I have one doubt...mentioned as below.. Please , Explain Why in CB configuration, VCB plot gone to -ve side of axis..,? Thank you
as Vcb is increasing it means reverse bias is increasing so the width of the depletion increases and that implies the base region narrowing and now less voltage is required to keep EB in F.B and due to this curve shifts in -x axis or left side of the graph
Dear sir all your lectures are very good. I am also a lecturer and wishing to make video lectures. Will you please tell me on which platform you created your lectures.
First of all thank you so much sir for sharing knowledge with us. My doubt is why in the O/P characteristics of CE every curve ends at origin and why not in CB(it ends in 2nd quad in case of CB). THANK YOU
For,EB diode,one can neglect RE,since EB diode is in forward bias & any diode in forward-bias-condition has very low resistance.So,from that point of view,we can say,VBE=VEE. But,how can we say VCB=VCC because in that case,RC can't be neglected since the resistance in reverse-bias condition is very high.
thanku sir for sharing. My question is sir, E is input terminal and C is output terminal while the input terminal current is coming out and output current is going inside. Make it clear sir, Thanking you.
at 1:43 instance in video you said we apply weak signal in input and get a amplified signal at output.......in common base current gain does not exceed 1 .....so how this is possible...
Sir in active mode at J2, due to reverse biasing holes will move to p and electrons to n,as they are minority charge carriers,so the direction of current should be from n to p and hence this should be the equation Ic=a×Ie-Icbo. Clear my doubt sir please..
Passing my ECCF exams only because of you, sir! Thanks a lot :)
In common-base configuration, the base is common to the input and output circuits. The collector current is approximately equal to the emitter current, with a small base current.
Key moments:
00:05 Transistors have three configurations: common base, common emitter, and common collector. Common emitter configuration is widely used due to its advantages in amplifying weak signals in active mode.
-Explanation of common base configuration. Base is common to input and output circuits, facilitating signal amplification in active mode.
-Operation in active mode. Transistor has two junctions: Junction j1 forward biased (diode EB) and Junction j2 reverse biased (diode BC) for signal amplification.
-Comparison with diodes. Transistors are two-port devices with input (ie, V B II) and output (IC, V CE B) characteristics, unlike single-port diodes.
05:10 Understanding the proper nomenclature in transistor circuits is crucial for accurate representation. Kirchoff's current law helps derive key equations for active mode operation and current gain, essential for analyzing transistor behavior.
-Importance of following proper nomenclature in transistor circuits for accurate representation of voltage and current.
-Deriving key equations using Kirchoff's current law for active mode operation and understanding current gain in transistor circuits.
-Explaining the significance of alpha as the common base current gain and its implications on emitter and collector currents.
The best of the best!!! This video is simple yet knowledgeable; and the teacher gives you some valuable information that most other teachers neglected to mention.
Thank you for uploading videos with such clear explanations. It's a kind request to you sir that please upload practicals on electronics like digital gates using IC's.
thank you soo much sir, best for one-night batting students, just like me.
anyone like that. please like.
Haha
Exactly
Excellent lecture! Thank you sir for the conceptual clarity😄
in vk mehta book, nomenclature of Vbe is opposite , it confused me and i opened this lecture to clear my confusion , my confusion is now totally clear ! Thank you so much Sir ! greetings from Bangladesh
Thank u, twas really conceptual and eliminating out confusions. I liked the way, you drew Vcb and Vbe later in the circuit and gave understanding of its terminals. Most of the lectures i found previously, they seemed to mug up the circuit diagram without and explanations and then explain just the results, that too in a confusing way.
tq sir!very well explained,ill have my exam on basic electronic,staying up to watch ur videos and understand all the concept, T.T
These videos are excellent and very well made. Kudos to the creators!
𝗛𝗵𝗼
The way of explanation is harts of sir...
Keep doing this best explanations
Thanks a lot sir
It is still so much useful after 8 years.... Thank you❤
Thanks!
Best lect on this topic available online..thanks a lot sir
Most underrated youtube channel ❤️
We already know, we already know. Sweetest thing I will hear this week.
very well explained just awesome thanku sir for this simple explanation.
Thanks for making our engineering life easy. May our creator bless you.
This is an seriously helpful vid i have seen ,all the confusions has been cleared out now.thankyou for the videos.
Sir. We r fortunate to have ur lectures seriously... Thanks a lot. Sir y emitter should be highly doped as well as base is lightly.? What's d reason behind it. Plz tell me sir.
Base is lightly doped so that there is less recombination in it and more charge carriers are able to pass to the collector region.
The emitter is highly doped to get large number of charge carriers in forward bias.
tq sir
@@313Ritesh sir I don't know anything about subject then how should I pass backlogs
@@raghuyuva start from scratch. Everything is available on the RUclips. And there is pretty sufficient time to prepare for it. Watch the videos,make schedule and you will be good to go.
Emitter is heavily doped as it's job is to produce much number of electrons
Well explained sir................ ✨✨✨✨
Thank u☺️✌️
I wish my professor was clear cut like you professor. Hats off.
nice sir........i m happy becoz you created playlist for each subject........so continue sir it very helpful
the best academy is neso. thanks sir.
God gifted lecturer to students.❤
thank you sir...best lecture ever.....
good job Neso academy from Ethiopia
you are the best at explaining sir
This video are really helpful for me . I watching this video from Bangladesh . And I am the student of Gazipur Technical school and college, and my trade is Electrical works and maintenance.
Kemon asen
deep thanks and big appreciation to you;sir
how beautifully u explained sir......really awesome
big thank you to you sir
boss in electronics......love you my master
sir,wonderful lecture of ur's helped me in solving many doubts of transistor and pls..... upload working of low passand high pass filters also.......... thankyou for ur lecture
Arre great sir 😘
I become huge fan of your teaching😍😍🤗
Keep helping us tqsm...
I cbo means the reverse saturation current in common base configuration when the emitter terminal is open ( battery across emitter is disconnected).
I ceo means the reverse saturation current in common emitter configuration when the base terminal is open ( battery across base is disconnected).
Both I cbo and I ceo are very small so they can be interchanged. Because later we have to ignore thier value anyway.
realy nice video and beautiful handwriting
Very understandable 👏🏼
Superbb lecture...😘😘😘😘😘keep going...
Very well explained. Thank you!
I do not understand the reverse saturation current, Icbo and Ico. @_@
Nice explanation 👍
Thanku sir respect from Pakistan
Tq soo much.. really understood in one attempt..thanks for the valuable information
How did we get base current as (1-alpha)of emitter current given at the ending of presentation
When the base is grounded current should be zero ?
Sir plz Upload Notes for these lectures would be really helpful
Thanks for the exolanation sir 🙏🙏
Really great work bro...helped a lot conceptually
Thank you Sir for the Lectures.Really helpful.
V EB IS CORRECT BECAUSE POTENTIAL OF E IS MORE THAN B REST ALL IS GOOD
Very motivating , helpful and life saver videos...well explained everything...👍🙏👏
Sema sir... Tanq 4 te lecture... 🙏
Thank you sir ❤️
Thank you for these lectures... Very helpfull..
any indians here? SIR?
Yes
Yes I am
Who cares dude
Can anyone please tell me why we are using "Ground " in this cercit?
Yes?
Thank you very much sir!! You helped me a lot🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
semester saver videos... thankyou sir..
Great videos. You are a life saver.
what happens after electron-holes recombine in base region?
I mean do they again split to form I-b
Always u help a lot sir😁😁
Your videos really very clear,.
Thanks for your this videos.,
These are very helpful me for Ugc Net Exam..
But ,I have one doubt...mentioned as below..
Please , Explain Why in CB configuration, VCB plot gone to -ve side of axis..,?
Thank you
as Vcb is increasing it means reverse bias is increasing so the width of the depletion increases and that implies the base region narrowing and now less voltage is required to keep EB in F.B and due to this curve shifts in -x axis or left side of the graph
Super. I thought may be u will go to the inside of electrons that flowing. That much details.
Dear sir all your lectures are very good. I am also a lecturer and wishing to make video lectures. Will you please tell me on which platform you created your lectures.
Sir will u make lectures on "logic families" in this series? because this portion is very confusing
First of all thank you so much sir for sharing knowledge with us.
My doubt is why in the O/P characteristics of CE every curve ends at origin and why not in CB(it ends in 2nd quad in case of CB).
THANK YOU
Thnks a lot sir u made it easy
sir.....when will u upload lectures on OPAMP .....
I need all lecture s related that ....and ...your way of explaining is superb...
thank you sir for the good work
What are the significance(meaning) of the resistances Re and Rc ?
If they r externally provided or internal properties of bjt?
Please tell in detail.
GYAN PRAKASH Internally due to barrier potential.
For,EB diode,one can neglect RE,since EB diode is in forward bias & any diode in forward-bias-condition has very low resistance.So,from that point of view,we can say,VBE=VEE.
But,how can we say VCB=VCC because in that case,RC can't be neglected since the resistance in reverse-bias condition is very high.
it was really helpful tq sir
Thanks sir 🙏☺️
Sir if Vcb also contains barrier potential??
Sir please upload a video of Transistor Current Components.
current components is same alpha ,beta, gamma relation
thanku sir it was very helpful
very important this videos thanx
Sir I think there's one correction - proper nomenclature shld be V EB according to ur battery connection.. Pls check once
Best tutorial
love u sir please make as much video as you can
Very clear explanation sir.
Thanks a lot😊
thanku sir for sharing. My question is sir, E is input terminal and C is output terminal while the input terminal current is coming out and output current is going inside. Make it clear sir, Thanking you.
Which is greater Ic or Ib ?
Ic is greater
Why is J2 reverse biased in active region? And how do we know whether it needs to reverse biased or not?
As it is in active mode j1 act as FB and j2 act as RB
Emmiter will be Reverse bias because It is heavily adobed
sir, doubt in whole video
Literally me
Bhai achaa nhi padhaya kya.
Hindi me pdhaate to jyada samj. Aata 😢
I am more confused now 🤔
Name the videos with no.s such that a series of lectures can b identified by the viewer
we owe your or lives
Thanks Sir
Thanks a lot from my hard❤️❤️
Why eb in forward bias?
Thanks sir u r the best
What is reverse saturation current???? Please tell
please explain how we can obtain voltage gain in common base?and why we call it as current buffer?
at 1:43 instance in video you said we apply weak signal in input and get a amplified signal at output.......in common base current gain does not exceed 1 .....so how this is possible...
Shubham Dhama u will gain voltage amplification..
A lot of thank you ....................................sir
Sir ,please upload power amplifier transistor...and its various types .....
Can I ask which program you use to draw
Agar emitter base junction reverse bias hai to potential barrier greater hoga then how majority charge carriers pass this potential barrier???
Which is the video in which u give concept about current direction in npn and pnp transistor in case of common base configuration
Sir in active mode at J2, due to reverse biasing holes will move to p and electrons to n,as they are minority charge carriers,so the direction of current should be from n to p and hence this should be the equation Ic=a×Ie-Icbo.
Clear my doubt sir please..
Any one from Ethiopia? 🥹
From where the equation at 7:00 come