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You're absolutely correct! I explained the correct solution (2 and 5) starting 1:17:50 in the session. Please watch that part to confirm your approach. :) Best, Shweta
@@egmat How is it not 2 and 4? Version 5 became available june 2010 which is the following year and not the same year as when the decreaseing sale of version 2 started occuring
@@MKEW2002 Sure. We can get the first part (the weight of water vapor per ㎥ of air at its saturation point at 37℃, at sea level) from the graph; and that is ~41 g/㎥. To get the second part (the weight of 1 ㎥ of air containing no water vapor at 37℃, at sea level), we’ve to use the given formula. Using the formula, we get the answer for the second part: ~1,124 g/㎥. Now on solving for “what % of 1124 is 41?”, we get ~3.65%. That’s our answer! I hope this helps. Have a nice day.
@@nishantk7554 Thanks for the explanation. I struggled to get the 1,124 because the question had the kg/m3 unit in the denominator instead and couldn't land at where you got to.
Hey@@MKEW2002! We are going to post a detailed video solution for this HW question in the next few hours. I will just add a comment right here. Stay tuned!
Hey Harshita! Let's read the full statement with your values and see if it makes sense. "Slightly less than 20% of the female respondents indicated that they ate the food at most occasionally." Now, let's check the female chart to see whether that is true. At most occasionally means occasionally or less - this includes rarely, infrequently, and occasionally itself. Now, on the legend, we see the patterns associated with these three categories and just see where the combined huge segment reaches. This combined segment (horizontal blue, light blue solid, and dark blue solid) reaches slightly less than 40%. So, the correct statement would be "Slightly less than 40% of the female respondents indicated that they ate the food at most occasionally." But don't have that "40% of female" in the choices for blank 1. Thus, your chosen values were incorrect. Hope this helps! Best, Shweta
Can you explain the 3.6%? I'm stuck on this one. Do we compare the g/m3 of humidity over total (air+water)? Water vapor = 41g/m3 No water vapor is 10^5/287(37+273)*1000 = 1/889.7 therefore 890g/m3 Total Water Vapor = 931g/m3 Answer: (41/931)x100= 4.4%...None of the answers. Where did I go wrong?
I think there is a mistake in the formula in the question. The kg/m3 should not be in the denominator, but in the numerator, since the units of density are kg/m3 and not m3/kg. Try again with this.
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Thx Shweta, e-GMAT and GMAT Club for this amazing session. I will come back to this video for TA (starting 01:30:14).
You're videos are extremely helpful, thank you so much!! Love the way you explain!
Won't question 5, first sub question be 'indicates statement is correct'?
Kaam for second question the correct answer 2,5 as mentioned about calendar year.please guide me if I'm wrong
You're absolutely correct! I explained the correct solution (2 and 5) starting 1:17:50 in the session. Please watch that part to confirm your approach. :)
Best,
Shweta
@@egmat How is it not 2 and 4? Version 5 became available june 2010 which is the following year and not the same year as when the decreaseing sale of version 2 started occuring
My answers to the last Question :
Blank 1 = 3.6%
Blank 2 = Greater than
Can you explain Blank 1?
@@MKEW2002
Sure.
We can get the first part (the weight of water vapor per ㎥ of air at its saturation point at 37℃, at sea level) from the graph; and that is ~41 g/㎥.
To get the second part (the weight of 1 ㎥ of air containing no water vapor at 37℃, at sea level), we’ve to use the given formula. Using the formula, we get the answer for the second part: ~1,124 g/㎥.
Now on solving for “what % of 1124 is 41?”, we get ~3.65%. That’s our answer!
I hope this helps. Have a nice day.
@@nishantk7554 Thanks for the explanation. I struggled to get the 1,124 because the question had the kg/m3 unit in the denominator instead and couldn't land at where you got to.
This is awesome,@@nishantk7554! Thanks for posting your full solution. :)
Hey@@MKEW2002! We are going to post a detailed video solution for this HW question in the next few hours. I will just add a comment right here. Stay tuned!
Why wont the answer to Q1 be B,C? i.e. 20% female, occasionally
Hey Harshita!
Let's read the full statement with your values and see if it makes sense. "Slightly less than 20% of the female respondents indicated that they ate the food at most occasionally." Now, let's check the female chart to see whether that is true.
At most occasionally means occasionally or less - this includes rarely, infrequently, and occasionally itself. Now, on the legend, we see the patterns associated with these three categories and just see where the combined huge segment reaches. This combined segment (horizontal blue, light blue solid, and dark blue solid) reaches slightly less than 40%.
So, the correct statement would be "Slightly less than 40% of the female respondents indicated that they ate the food at most occasionally." But don't have that "40% of female" in the choices for blank 1. Thus, your chosen values were incorrect.
Hope this helps!
Best,
Shweta
3.6%
Greater than
Can you explain the 3.6%? I'm stuck on this one.
Do we compare the g/m3 of humidity over total (air+water)?
Water vapor = 41g/m3
No water vapor is 10^5/287(37+273)*1000 = 1/889.7 therefore 890g/m3
Total Water Vapor = 931g/m3
Answer: (41/931)x100= 4.4%...None of the answers. Where did I go wrong?
I think there is a mistake in the formula in the question. The kg/m3 should not be in the denominator, but in the numerator, since the units of density are kg/m3 and not m3/kg. Try again with this.
@@vella_shubham Thanks for the tip, that solved it for me.
Thanks a lot for pointing that out,@@vella_shubham! I have fixed it in my presentation as well. :)
Best,
Shweta
Glad this worked,@@MKEW2002! Sorry about the typo. :)