You're an absolute lifesaver. I was assigned a problem relating to heat of vaporization when never having done a problem on it before, and you made it so much easier to understand
R is a constant (a value you're given and plug in) and is equal to 8.314 J/(mol*K) in equations dealing with energy and 0.0821 L*atm/(mol*K) in equations dealing with the ideal gas law.
You have to add a trendline by right clicking on one of the data points. Once this is done, on the right side there should be a side page open up. At the bottom of it there is a place where you can check the box for display equation on chart. Then you will be able to determine the slope from the linear-regression equation.
You're an absolute lifesaver. I was assigned a problem relating to heat of vaporization when never having done a problem on it before, and you made it so much easier to understand
you are my lord and saviour shaun
Absolute legend
thanks man this saved me
Thank you so much
3 years late to the party, but really an amazing video, super clear and understandable, thank you!
May I know the unit for vapour pressure in this sheet? IS it pascal or bar?
Thank you
good explanation, but I have a question. Wouldn't the slope (-3773) have SI units as well?
No. The slope (m) is a constant. In other words the slope is the m, in y=mx+b.
Hi Shaun, I am confused on how you got R = 8.314. Could you explain this part of the equation?
R is a constant (a value you're given and plug in) and is equal to 8.314 J/(mol*K) in equations dealing with energy and 0.0821 L*atm/(mol*K) in equations dealing with the ideal gas law.
THANK U SOOOOO MUCH!!!!!
Hi! Where did you get the slope value? Could you pls explaine it?
Thank you
You have to add a trendline by right clicking on one of the data points. Once this is done, on the right side there should be a side page open up. At the bottom of it there is a place where you can check the box for display equation on chart. Then you will be able to determine the slope from the linear-regression equation.
Thanks!
thanks brother
No problem
What if 1/T is 1/T (K^-1) ?
Oh, nevermind, I figured it out, lol. 🤦🏾♂️
@@julienalexander6113 glad you did as I was trying to figure out what you were referring to. :)
@@shaunshelton6855 🤙🏾