These are HANDS DOWN the best teaching tools for aviation on the internet! I took another class and the tutorials are useless compared to these high quality clear and understandable videos!!! THANK YOU!!!!!!!!!!!!!!!!!!
Dear Sir, I just wanted to say that I passed my instrument test the other day and wanted to say that I could not have done it without your help. I scored an 88% it was not exactly easy, but then nothing is when your learning. thanks again, Now off to get commercial..
This one was tough for me when first seeing it. It's still in the 2020 ASA PPL test prep as a possible question on the test. Thank for the explanation, I finally have a better understanding.
I had a dream where I was in a mixed physics/conspiracy class and I got asked a question about objects on a scale in different positions and despite never studying these physics it turns out I was right. All my kerbal space program knowledge paid off.
Remember all A/C are designed to have a nose heavy cg in flight...why...because if the A/C is stalled for any reason, the nose will drop and if you have enough altitude then you can recover from a stall and fly away. If the nose did not automatically drop, you probably would not be able to recover! If your A/C weights for example 2,683 lbs on the ground, then in flight the wings would have to produce enough lift to support 2,683 lbs plus the balance force to keep the nose up force in flight...lets say that is 127 lbs...so in flight the wings would have to produce 2,683+127=2,810 lbs of lift to maintain level flight. Your A/C will always need to produce more lift than the A/C weighs to fly...that is the cost of the safety feature which would allow the A/C to recover from a stall. To minimize this effect...try to load you A/C to the Aft limits of your Wt & Balance envelope?
It was so good vedio tthanks please update more different size bars on both the side for example 4 inch left side and 3 inch in in right side which is supported in the middle
You are welcome Sir. Keep in mind that this is a simple extract from our full software which you can find at: passfaaexams.com/ If you like the way we explained this topic imagine how we explain really difficult subjects like: Weather, VOR Navigation, etc.
The third example is wrong. The plank should be 28.75 lbs at 52.5 inches to the right. The first 45 inches of the plank balance out. Correct me if I'm wrong.
So only the side on the right is now 200lb because the fulcrum was moved? Wouldn't the left side of the plank still have some weight take away from the 200lb on the right?
@5:33 Why did you calculate the plank weight on the left (200 X 15) instead of the weight of the block and it's distance from the datum (250 X 20) to find the current weight on the right?
On the third example, why do you apply 200lb in one position rather than distributing across the length of the plank? Surely there is still a left moment of the fulcrum since some plank weight on the left?
Getting my PPL for helicopters and going to solo here pretty soon, and then take the test. So these questions were REMOVED from the Private Pilot test I'm going to take? It IS good info to know, but if I don't NEED to stress about it, then all the better...
Hello! Quick question :) if i were to put another "y" weight with it's center of mass exactly on the balance point of the fulcrum would it affect the center of mass of the assembly?
Couldn't you do for the second example just find "Z" by doing 150 from the weight of all 3, than multiple it by 100 from the arm to give you 5,000 then subtract from the known of 3750 giving you 1250 than dividing by 50 from the distance of 50? to give you the correct answer as shown below W |A | D x50|50|2500 y50|25|1250 ------------------- 100|37.5|3750 z50|100|5000 -------------------------- 150|100|5000-3750 ---------------------- (D)3750/(W)150=25??
how come the 250 weight can be 3 inches away from de fulcrum and balance the plank? wouldnt this weight need to be twice the distance between the 500 weight and the fulcrum??
+Isaac Gonzalez The weight is not 250, the "moment" is 250. All the weights are 50 lbs. However, the farther you move it from the center the more force is exerted. Or, the weight multiplied by the distance from the center of gravity, in the video called a fulcrum. The increase distance of 50" creates a force of 2500lb on the beam. Hope that helps a bit.
You are welcome sir! don't forget to take a look at our full software for the Private Pilot License at: passfaaexams.com/private-pilot-knowledge-test-prep/
Thank you!
It’s kinda crazy how simple this is once it’s explained properly.
You are welcome sir. You should see how we explain the rest of the material: passfaaexams.com/
These are HANDS DOWN the best teaching tools for aviation on the internet! I took another class and the tutorials are useless compared to these high quality clear and understandable videos!!! THANK YOU!!!!!!!!!!!!!!!!!!
Bruce The Curmudgeon Thank you Bruce. These videos are taken out of our Full courses which you can find at passfaaexams.com
Was looking for an explanation while answering a sporty's test prep set, thank you so much!
Dear Sir, I just wanted to say that I passed my instrument test the other day and wanted to say that I could not have done it without your help. I scored an 88% it was not exactly easy, but then nothing is when your learning. thanks again, Now off to get commercial..
This one was tough for me when first seeing it. It's still in the 2020 ASA PPL test prep as a possible question on the test. Thank for the explanation, I finally have a better understanding.
I had a dream where I was in a mixed physics/conspiracy class and I got asked a question about objects on a scale in different positions and despite never studying these physics it turns out I was right. All my kerbal space program knowledge paid off.
Remember all A/C are designed to have a nose heavy cg in flight...why...because if the A/C is stalled for any reason, the nose will drop and if you have enough altitude then you can recover from a stall and fly away. If the nose did not automatically drop, you probably would not be able to recover!
If your A/C weights for example 2,683 lbs on the ground, then in flight the wings would have to produce enough lift to support 2,683 lbs plus the balance force to keep the nose up force in flight...lets say that is 127 lbs...so in flight the wings would have to produce 2,683+127=2,810 lbs of lift to maintain level flight. Your A/C will always need to produce more lift than the A/C weighs to fly...that is the cost of the safety feature which would allow the A/C to recover from a stall.
To minimize this effect...try to load you A/C to the Aft limits of your Wt & Balance envelope?
thank you sir!! I’m taking my written in 2 weeks and weight and balance is something I need to be 100% good with before I do...(:
@@robertoforbes3405 read about it more, watch videos, and then do a lot of practice problems on it. Also, have your instructor explain it to you.
@@abbieamavi how was weight and balance reviewed during checkride? Was it just the plane cg calculations?
It was so good vedio tthanks please update more different size bars on both the side for example 4 inch left side and 3 inch in in right side which is supported in the middle
Thanks! I was struggling with the instruction from gold seal and king school
You are welcome Sir. Keep in mind that this is a simple extract from our full software which you can find at: passfaaexams.com/
If you like the way we explained this topic imagine how we explain really difficult subjects like: Weather, VOR Navigation, etc.
Thanks ! I am taking my AGI this Friday . This helps .
In the last problem what does the 50inches above the weight 500lbs represent?
Awesome explanations really in much simpler way. thanku. God bless u
The third example is wrong. The plank should be 28.75 lbs at 52.5 inches to the right. The first 45 inches of the plank balance out. Correct me if I'm wrong.
Thank you!! great explanation
This is exactly what I needed! Simple and clear explanations. Thank you.
You are welcome Mr. Baxter
Thats all we do at Pilot Training Solutions. Find simple answers to pilot questions.
So only the side on the right is now 200lb because the fulcrum was moved? Wouldn't the left side of the plank still have some weight take away from the 200lb on the right?
I was curious about that, as well.
@5:33 Why did you calculate the plank weight on the left (200 X 15) instead of the weight of the block and it's distance from the datum (250 X 20) to find the current weight on the right?
On the third example, why do you apply 200lb in one position rather than distributing across the length of the plank? Surely there is still a left moment of the fulcrum since some plank weight on the left?
Getting my PPL for helicopters and going to solo here pretty soon, and then take the test. So these questions were REMOVED from the Private Pilot test I'm going to take? It IS good info to know, but if I don't NEED to stress about it, then all the better...
Thank you!
Hello! Quick question :) if i were to put another "y" weight with it's center of mass exactly on the balance point of the fulcrum would it affect the center of mass of the assembly?
svlad84 The CG would not change because its arm would be 0 and therefore the total moment would also be 0.
Couldn't you do for the second example just find "Z" by doing 150 from the weight of all 3, than multiple it by 100 from the arm to give you 5,000 then subtract from the known of 3750 giving you 1250 than dividing by 50 from the distance of 50? to give you the correct answer as shown below
W |A | D
x50|50|2500
y50|25|1250
-------------------
100|37.5|3750
z50|100|5000
--------------------------
150|100|5000-3750
----------------------
(D)3750/(W)150=25??
Real useful simple & clear..thanks
Hi - your demo for PC (VFR) link does not seem to work
Regards,
Philippe
+Philippe Martin Apologies Sir.
The web guys were uploading a newer version of the Demo so the page was down. It should be working fine now.
+Gian Luca Noia
Tx - will take a look
ɷ Youuu Wontttt Beliveee Guyss H0w I Lostt Fat Fast In Justtt 3 Weeks Withhh Thiss Weight Loss Diet Visitt : - t.co/qKKnXk09RW
DOUBLE THUMBS UP!!! Thank you so much! :-)
great explanation.
Thanks so much ! You save my ATPL ^^
thank you a lot for this video it was really useful
how come the 250 weight can be 3 inches away from de fulcrum and balance the plank? wouldnt this weight need to be twice the distance between the 500 weight and the fulcrum??
+Isaac Gonzalez The weight is not 250, the "moment" is 250. All the weights are 50 lbs. However, the farther you move it from the center the more force is exerted. Or, the weight multiplied by the distance from the center of gravity, in the video called a fulcrum. The increase distance of 50" creates a force of 2500lb on the beam. Hope that helps a bit.
How to solve for finding the fulcrum
Really appreciated sir.!💜
You are welcome sir! don't forget to take a look at our full software for the Private Pilot License at: passfaaexams.com/private-pilot-knowledge-test-prep/
Crazy how weightless that plank is.
Thanks, from Perù.
thanks, from Perù.
thankyou
Nice video