@@directhubfeexam Thanks for this. I tried this before looking at your solution. my initial solution did not include the effect of weight at all. I then watched your solution and my initial thinking was the same as Lance was thinking. Thanks for this clarifying. 💯
It will be under the "Particle Curvilinear Motion" topic on page. 115 in FE handbook 10.1. Note that ρ will be the radius of curvature (r) in this case.
M*(v^2/r) is equal to 12.25. If you want to calculate W*cos x, then it will equal to 0.85. Final answer should be closer to A, 12.25 - 0.85 = 11.4
Just checked this. You would need to add the Wcos(x) since it's on the left side of the equal sign. Therefore:
M*(v^2/r) + W*cos x
12.25 + 0.85 = 13.1
@@directhubfeexam Thanks my mistake. I see it now: F = Normal - Weight*cos x
Normal = F + Weight*cos x
@@lancea673 I’m glad you caught that 👍
@@directhubfeexam Thanks for this. I tried this before looking at your solution. my initial solution did not include the effect of weight at all. I then watched your solution and my initial thinking was the same as Lance was thinking. Thanks for this clarifying. 💯
Where can I find the formula of a=v2/r ?
It will be under the "Particle Curvilinear Motion" topic on page. 115 in FE handbook 10.1.
Note that ρ will be the radius of curvature (r) in this case.