NPSHa is difference between suction pressure and vapour pressure of pumping fluid at that temprature provided by process engineer during pump sizing and NPSHr is provided by pump vendor. NPSHa > NPSHr to avoid cavitation due to vaporization of pumping fluid which is caused due to frictional loss between source tank to pump suction as a result suction pressure falls below vapour pressure and cavitation occur.
why NPSHr (from vendor) is have to be smaller than NPSHa (calculated by process engineer), shouldnt it be the higher the difference of suction pressure and vapor pressure, the less the cavitation will occur?
I love the way you start to explain in simple terms then jump to trigonometry. Then you come back to simple terms and jump back to calculus. All over the spectrum with one brush stroke
How about diaphragm actuators..say Shutdown valve air actuated where pressure inverse proportion to area applies...with less area force is more thereby u can actuate such a huge valve 30 inch valve too
@core engineering : Sir are you sure that Area increase then pressure increase? If it is so than kindly answer that area of 8" pipe is higher or 6" pipeline . I am surprised that people are still comments nice explanation and all. What you explain is totally wrong. If area increase then pressure decreases that's all.
Don't get confused , simple thing is here …..according to Bernoulli's equation when we increase area so pressure will increase. For example we all use water pipe to give water in garden so In this situation we push a pipe so water will fastly go as far away, Hence when we push pipe it means we are decreasing area of pipe so pressure will decrease and velocity will increase.
@@Coreengineers Dear sir, Yes now you are correct that if area decrease then pressure increase. Kindly review your video because in video what you are explaining is totally Opposite. That's why I comment. Bernoulli equation is right and I am not confused but kindly check what you explained in your video. You will come to know that in video you explained wrong.
your point is right when considering a pressure of liquid at rest(P=F/A),but in motion always pressure is directly proportional to Area.(As per bernoulis Law)
But if at discharge, velocity is increasing then as per bernoulli eqtn the pressure will decrease at discharge, will it not cause back pressure sir....
No It'll not create back pressure as pump is used to increases the pressure of the fluid and at suction side we increase the dia because of cavitation prevention. For back pressure we use the nrv btw
I think that the NPSH is the sum of the pressure head and the velocity head in the suction of the pump minus the Vapor pressure of liquide .so this sum is still constant if we applie Bernoulli equation so the variation of npsh it’s from aspiration pressure losses that’s why we use bigger diameter to reduce the velocity only
Didn't get it can you elaborate? I understand that A increase by continuity equation velocity increase (Q= AV ) so by Bernoulli equation if total energy is constant and veleocity (kinetic energy) is increasing the pressure must be reduced so total E remain constant, inshort I understand a decrease, pressure decrease & vice versa a increase pressure increase (relatively) but I would like to understand by your pov @@mr.write1433
What would happen if the suction line is smaller than the discharge line? Suction line is 3" and discharge of pump is at 2 1/2" but a reducer is used so it becomes 4".
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Most knowledgeable video thanks for sharing valuable knowledge
New role in thermodynamics 😂
NPSHa is difference between suction pressure and vapour pressure of pumping fluid at that temprature provided by process engineer during pump sizing and NPSHr is provided by pump vendor. NPSHa > NPSHr to avoid cavitation due to vaporization of pumping fluid which is caused due to frictional loss between source tank to pump suction as a result suction pressure falls below vapour pressure and cavitation occur.
why NPSHr (from vendor) is have to be smaller than NPSHa (calculated by process engineer), shouldnt it be the higher the difference of suction pressure and vapor pressure, the less the cavitation will occur?
You said that diameter of discharge decrease it means velosity increase but why always preasure of discharge is greater than suction side?
Informative video....👍
I love the way you start to explain in simple terms then jump to trigonometry.
Then you come back to simple terms and jump back to calculus.
All over the spectrum with one brush stroke
😮
The concept you have mentioned about the pipe in this video was amazing and you have made various videos like this.
Amazing explanation
Can you make a video about which is greater losses in suction line or discharge line for pump
Thanks
sure! I will upload that video soon
Pressure is inversely prepositional to area 😊
It is for solid not for fluid
How about diaphragm actuators..say Shutdown valve air actuated where pressure inverse proportion to area applies...with less area force is more thereby u can actuate such a huge valve 30 inch valve too
Today my concept got cleared thank you!
Now finally clear my doubt ❤
Available and required? Not related to the reel npsh without the dead volum?
i have a doubt, Q=AV, then how throttling valve controls the flow, please clear my queries.
How recycle line impact the pump performance please make one video about it
Bro really excellent video.
thank you ashish!
If area increases pressure decreases
what if suction head is 1", then enlarged to 2" using a reducer, and then back to 1" when connecting to pump, then goes out of the pump at 1"?
Good explain
thanks dear
@core engineering : Sir are you sure that Area increase then pressure increase?
If it is so than kindly answer that area of 8" pipe is higher or 6" pipeline .
I am surprised that people are still comments nice explanation and all. What you explain is totally wrong.
If area increase then pressure decreases that's all.
Don't get confused , simple thing is here …..according to Bernoulli's equation when we increase area so pressure will increase. For example we all use water pipe to give water in garden so In this situation we push a pipe so water will fastly go as far away, Hence when we push pipe it means we are decreasing area of pipe so pressure will decrease and velocity will increase.
@@Coreengineers Dear sir, Yes now you are correct that if area decrease then pressure increase. Kindly review your video because in video what you are explaining is totally Opposite. That's why I comment. Bernoulli equation is right and I am not confused but kindly check what you explained in your video. You will come to know that in video you explained wrong.
your point is right when considering a pressure of liquid at rest(P=F/A),but in motion always pressure is directly proportional to Area.(As per bernoulis Law)
@@manishankarraju5354 in rest pressure is the same everywhere.
@@letslovenature6701 mate u are very wrong.very very wrong.this video is legit .and you are very wrong
Pressure is inversely prapotional to area hota he
Sir request to you please upload about mechanical seal of reactor and pump seal
Could you please explain about end of curve operation of pumps
Will upload the video soon!
When area increases pressure increases????
Pressure is inversely prepositional to area
Nice
But if at discharge, velocity is increasing then as per bernoulli eqtn the pressure will decrease at discharge, will it not cause back pressure sir....
No It'll not create back pressure as pump is used to increases the pressure of the fluid and at suction side we increase the dia because of cavitation prevention. For back pressure we use the nrv btw
If Area will increases, then pressure will be decreases...
Please relate here with bernaulli's principle not P=F/A, A increase Velocity decreases then P increases
Tq❤
thx for the video but how come when A is increasing the P is increasing??
Please watch bernaulli's principle videos
this video is misleading. Increase in area lead to decrease in pressre drop.
Is there any formula between suction dia and discharge dia
Will cover in upcoming videos
We kindly ask you to make all your videos piping related and as far as possible you must post at least one piping related video per day.
If I'm not Wrong, if your Area is increased Pressure is Decreased.
Correct P=F/A and A=F/P
Make turbine related topics information sir
yes! I'm planning about it
How areas increases then pressure increases.
See please refer Bernoulli equation I completely understand your point.
Pressure=Force/Area or Force=Pressure*Area
1) pressure increases -force increases
2)Area increases -pressure decreases
Unfortunately
So,You are wrong sir
I think that the NPSH is the sum of the pressure head and the velocity head in the suction of the pump minus the Vapor pressure of liquide .so this sum is still constant if we applie Bernoulli equation so the variation of npsh it’s from aspiration pressure losses that’s why we use bigger diameter to reduce the velocity only
Very narrowly missed the concept.
By your logic if you directly suck water from a reservoir, pump will not cavitate.😅😅😅
Very
Sorry,bro if area increase then Pressure will be decrease.
No, you're wrong it's vice-versa
No man area increase pressure decrease
Didn't get it can you elaborate? I understand that A increase by continuity equation velocity increase (Q= AV ) so by Bernoulli equation if total energy is constant and veleocity (kinetic energy) is increasing the pressure must be reduced so total E remain constant, inshort I understand a decrease, pressure decrease & vice versa a increase pressure increase (relatively) but I would like to understand by your pov @@mr.write1433
What would happen if the suction line is smaller than the discharge line? Suction line is 3" and discharge of pump is at 2 1/2" but a reducer is used so it becomes 4".
Pls explain
But in some cases suction and discharge are equal in size.
Npsha- npshr =1
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