Given a pressure of 2kpa, nominal resistance of 120 ohm, diameter of strain gauge 0.1mm, a GF of 2. What will be the change in resistance value of the strain gauge?
I hope that i understood it correctly: The bridge uses the ratio between the upper and the lower resistors (R1R2 and R3R4). In the formular is somewhere "R1/R2" and "R3/R4". If you increase both resistors at the same time, the ratio between them won't change much. That's also why the strain gauge 3 and 4 are "swapped" at the full bridge. The resistors that'll change have to be kind of unsymmetrical or "crossed".
@@Dampfhammer96 thank you for your answer. I think I understand the importance of having gauges on both sides. However, in my experience, I can't have gauges on the 2 sides, can I at least make a half bridge by having 2 gauges on the same side or is that not possible? If so, is the formula right: Vin/Vout = (K/4)*(ε1-ε2)?
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Great explanation!
Given a pressure of 2kpa, nominal resistance of 120 ohm, diameter of strain gauge 0.1mm, a GF of 2. What will be the change in resistance value of the strain gauge?
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Great info
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can the 4 gauges of a complete bridge be placed on the same face? None in compression
I hope that i understood it correctly:
The bridge uses the ratio between the upper and the lower resistors (R1R2 and R3R4). In the formular is somewhere "R1/R2" and "R3/R4". If you increase both resistors at the same time, the ratio between them won't change much.
That's also why the strain gauge 3 and 4 are "swapped" at the full bridge. The resistors that'll change have to be kind of unsymmetrical or "crossed".
@@Dampfhammer96 thank you for your answer. I think I understand the importance of having gauges on both sides. However, in my experience, I can't have gauges on the 2 sides, can I at least make a half bridge by having 2 gauges on the same side or is that not possible? If so, is the formula right: Vin/Vout = (K/4)*(ε1-ε2)?
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