I was just looking for something like this but didn’t know it could be made this simple! I need to use a thermocouple to read temperature with a arduino but the resistance change over the thermocouple is too small to be noticed. Thanks and great timing :)
good explanation, but you should mention that the big advantage of the wheatstone bridge is that the voltmeter actually shows the small deviation from the equilibrium and thus you can use a much more sensitive measurement range. In your example of 20 ohm resistors (quite low value by the way) if you would only measure one resistor which changes from e.g. 20 ohm to 20.2 ohm than this would only be a change of 1% seen on the last decimal on a regular multimeter. Even if you just measure the voltage on the right side, you end up with an unuseable value of just 5.02 V, also here the important information is hidden in the last digit of the multimeter. However, if you measure the difference between the two voltages, you get a value of 25 mV which you even might be able to read with an addition decimal in the millivolt range of your multimeter.
There's a mistake on 4:43. The strain gauge resistance must be 20 ohm, just like R3, for a bridge to be balanced. Also on 5:30, the more temperature you apply, the more resistance increases. So, for example, it must increase to 22 ohms. But you're showing that it decreases. Otherwise very good, clear explanation! Thank you, dude!
disagree. Seems like an important reason for why this configuration is used is to account for resistors and systems not being ideal.. Although 20 ohms may make the bridge balanced in ideal conditions, this is real life. 23 ohms might be needed to balance the circuit due to the resistors not being ideal and environmental factors such as temperature
@@clobraico_private9121 that would have been plausible if he had explained that pragmatic scenario. The explanation should stick to the theory. If you dont understand the theory you wont understand its real world effects and variations.
Resistors come in large variation of properties and not all respond the same way to changes in temperature. Look up thermistors; they come with negative (i.e. temp goes up resistance goes down) and positive (vice versa) temperature coefficients. Now: Even resistors that aren't purpose built to respond to temperature coefficient. And whether the temperature coefficient of any given resitor is positive or negative depends on its construction and the materials its made from. Therefore the generalization "the more temperature you apply, the more resistance increases" is incorrect.
Nice explanation, but using quarter wheatstone bridge as u showed in this video doesn't solve the problem with temperature messing up the measurement, because it's very likely that resistors used in this bridge will have different temperature coefficient than the strain gauge. We should use the half bridge instead, so 2 strain gauges , to make sure that the changing temperature won't mess up our mesurements, am I right?
but R1, R2 and R3 are not effected by the same temperature that was given to the Thermistor, so they are not all effected at the same time like you said in the minute before. how can you explain this ?
This explanation is completely wrong. A Wheatstone bridge is useless if you are only measuring on 1 of the legs. You need to be measuring on at least 2 of the legs, with 4 being the best, to gain anything from using it. You don’t even talk about the EM cancelation effects that this is primarily used for. This is by far the worst explanation of a Wheatstone bridge that I have ever seen. You could have at least presented a textbook example like a magnetic pickup.
Thank you for saving my life with this video. Those fucking physics teachers in my country just taught me to check the ratio between the resistances of resistors without any explanations.
The main goal of this video is how to eliminate temperature effects from our sensors. No one of the professors on our faculty could explained like that.
Hey what about using just a simple voltage divider - just put the strain guage in series with another known resistor, and measure the difference in the voltage drop...? Is there any advantage over the wheatsone bridge?
*PLZ HELP*. Given a pressure of 2kpa, nominal resistance of 120 ohm, diameter of strain gauge 0.1mm, a GF of 2. What will be the change in resistance value of the strain gauge?....in short I wanta formula to calculate the change in resistance of strain gauge for a given INPUT PRESSURE
@3.51 sec, you say , R3 can be changed until Vc = Vd; but didnot understand here.. Rx is a R3*const(Ratio of other two resistors). How can you change only R3 to make Vc = Vd. This part is not clear. Once we know R1, R2; Rx is R3* Ratio of (R1 & R2) assuming Vc = Vd. In this case i can choose R3 any value of Ohms and it will meet the criteria. so why do we need to change R3 value
Your videos are so SO good and well explained! I love your style of explanation where you sandwich the theory in between practical usage and that makes it really easy to follow and understand. Thanks for making these videos!
actually the device should be called Christie's bridge after Samuel Christies the actual inventor... wheatstone only popularised it in his days and some one else named it wheatstones bridge because back then the real inventor wasnt realy known and wheatstone was an already famous person...so the wrong person gets the credits (again)
Hi bro very good idea but how we can attach this to microcontroller using list means I would ask otherwise the project is awesome house have a good idea for project why not to make a constant current source for example in LED driver or something else Goodluck
I don't know if the same thing happens in the US, but in Brazil everyone sees this and many other advanced subjects in high school, you just need to search "ponte de whatstone" here and you will see the number of video lessons, it's crazy
Just looking into the wheatstone bridge with a thermistor for one of my projects. Have you used this with the Arduino for temp readings? Currently I'm just using the thermistor in a voltage divider and it's quite accurate but can never have high enough accuracy right? :) if you haven't done said project, any chance?
The explaination is correct but to apply the voltage divider metod you must first asume that the voltage between c and d is 0V, and not the other way around
In my school we did it with a two resistor voltage divider. Why do i have to use a Wheatstone bridge compared to a simple two resistor voltage divider?
Hello ! I liked your method of explaining you do a very good job but i have a small question how a voltage divider will existe if we have spplited current i think if we you ohm lows would be more satisfying and thanks you
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I was just looking for something like this but didn’t know it could be made this simple! I need to use a thermocouple to read temperature with a arduino but the resistance change over the thermocouple is too small to be noticed. Thanks and great timing :)
beautiful tutorial, the formulas explained very well and simple to understand!
Really, really interesting!!!
Good tutorial....👌👌👌
good explanation, but you should mention that the big advantage of the wheatstone bridge is that the voltmeter actually shows the small deviation from the equilibrium and thus you can use a much more sensitive measurement range. In your example of 20 ohm resistors (quite low value by the way) if you would only measure one resistor which changes from e.g. 20 ohm to 20.2 ohm than this would only be a change of 1% seen on the last decimal on a regular multimeter. Even if you just measure the voltage on the right side, you end up with an unuseable value of just 5.02 V, also here the important information is hidden in the last digit of the multimeter. However, if you measure the difference between the two voltages, you get a value of 25 mV which you even might be able to read with an addition decimal in the millivolt range of your multimeter.
It all makes sense now, thanks for you explanation, superb. i was struggling to understand the benefits...
There's a mistake on 4:43. The strain gauge resistance must be 20 ohm, just like R3, for a bridge to be balanced.
Also on 5:30, the more temperature you apply, the more resistance increases. So, for example, it must increase to 22 ohms. But you're showing that it decreases. Otherwise very good, clear explanation! Thank you, dude!
Temperature up resistance down
disagree. Seems like an important reason for why this configuration is used is to account for resistors and systems not being ideal.. Although 20 ohms may make the bridge balanced in ideal conditions, this is real life. 23 ohms might be needed to balance the circuit due to the resistors not being ideal and environmental factors such as temperature
@@clobraico_private9121 that would have been plausible if he had explained that pragmatic scenario. The explanation should stick to the theory. If you dont understand the theory you wont understand its real world effects and variations.
Resistors come in large variation of properties and not all respond the same way to changes in temperature. Look up thermistors; they come with negative (i.e. temp goes up resistance goes down) and positive (vice versa) temperature coefficients.
Now: Even resistors that aren't purpose built to respond to temperature coefficient. And whether the temperature coefficient of any given resitor is positive or negative depends on its construction and the materials its made from. Therefore the generalization "the more temperature you apply, the more resistance increases" is incorrect.
Nice explanation, but using quarter wheatstone bridge as u showed in this video doesn't solve the problem with temperature messing up the measurement, because it's very likely that resistors used in this bridge will have different temperature coefficient than the strain gauge. We should use the half bridge instead, so 2 strain gauges , to make sure that the changing temperature won't mess up our mesurements, am
I right?
So R3 should also be a strain gauge? You will have a problem with 2 strain gauges measuring different forces.
but R1, R2 and R3 are not effected by the same temperature that was given to the Thermistor, so they are not all effected at the same time like you said in the minute before. how can you explain this ?
This explanation is completely wrong. A Wheatstone bridge is useless if you are only measuring on 1 of the legs. You need to be measuring on at least 2 of the legs, with 4 being the best, to gain anything from using it. You don’t even talk about the EM cancelation effects that this is primarily used for.
This is by far the worst explanation of a Wheatstone bridge that I have ever seen. You could have at least presented a textbook example like a magnetic pickup.
Great concise clear explanation. Loved the animations.
Thank you for saving my life with this video. Those fucking physics teachers in my country just taught me to check the ratio between the resistances of resistors without any explanations.
I was stuck on this problem for hours. Thank you for the clear explanation!
Next video should be Basic configurations #2 - *FULL BRIDGE RECTIFIER*
It was on my school syllabus... This video is for me like Back to the memory Lane.
The main goal of this video is how to eliminate temperature effects from our sensors. No one of the professors on our faculty could explained like that.
Kind of disappointed that you didn't go into other wheatstone configurations. Like the quad-wheatstone strain gauge :D
Sorry. I can do that in a future part.
Hey what about using just a simple voltage divider - just put the strain guage in series with another known resistor, and measure the difference in the voltage drop...? Is there any advantage over the wheatsone bridge?
Is R2/(R1+R2)*Vin the same as R1/(R1+R2)*Vin? I saw another video of proof showing R1 on top.
please continue to make this kind of videos.
How should you connect a microcontroller with it's ADC input?
masteringelectronicsdesign.com/measure-a-wheatstone-bridge-sensor-signal-with-an-adc/
*PLZ HELP*. Given a pressure of 2kpa, nominal resistance of 120 ohm, diameter of strain gauge 0.1mm, a GF of 2. What will be the change in resistance value of the strain gauge?....in short I wanta formula to calculate the change in resistance of strain gauge for a given INPUT PRESSURE
@3.51 sec, you say , R3 can be changed until Vc = Vd; but didnot understand here.. Rx is a R3*const(Ratio of other two resistors). How can you change only R3 to make Vc = Vd. This part is not clear. Once we know R1, R2; Rx is R3* Ratio of (R1 & R2) assuming Vc = Vd. In this case i can choose R3 any value of Ohms and it will meet the criteria. so why do we need to change R3 value
What software do you use to edit the video? :)
After effects
u slip words first learn to speak words neatly sorry for this
yes
Your videos are so SO good and well explained! I love your style of explanation where you sandwich the theory in between practical usage and that makes it really easy to follow and understand. Thanks for making these videos!
Incredible presentation skills. Well done. 👍👍👍👍
Nice clear and concise explanation and demonstration!
actually the device should be called Christie's bridge after Samuel Christies the actual inventor... wheatstone only popularised it in his days and some one else named it wheatstones bridge because back then the real inventor wasnt realy known and wheatstone was an already famous person...so the wrong person gets the credits (again)
Three words, clear and beautiful. Thanks!
Hi bro very good idea but how we can attach this to microcontroller using list means I would ask otherwise the project is awesome house have a good idea for project why not to make a constant current source for example in LED driver or something else Goodluck
------Great fan of yours
Something that I do not understand. Why is this method better than two resistors in series connection? I mean a voltage divider...
shouldn't RX be (R2R3)/R1 ?
Very helpful tutorial Thank you very much
If the voltage drop increases, why would the voltage at point D increase?
please do nodal analysis or mesh analysis ❤️
Nice explanation thankyou !
Ammaaazing informations, this is genius, thanks a lot
better explanation than my university professor
Why does the voltage increase when the resistance increases?
Hey! I would like to know if you like basketball?
Spanish version please!!!
I don't know if the same thing happens in the US, but in Brazil everyone sees this and many other advanced subjects in high school, you just need to search "ponte de whatstone" here and you will see the number of video lessons, it's crazy
Great video information ❤ Great discussion 💯
Thank you for sharing your knowledge ♥️🇵🇭
do you have schematics for the breadboard?
Just looking into the wheatstone bridge with a thermistor for one of my projects. Have you used this with the Arduino for temp readings? Currently I'm just using the thermistor in a voltage divider and it's quite accurate but can never have high enough accuracy right? :) if you haven't done said project, any chance?
Interesting. Thanks!
Great video have watched almost all on RUclips found this one the easiest and most practical to understand
Great vid ,Thanks a lot 😍🥰
Nice video mate, I liked your power supply ... Did you made it or it something available in the marketing?
The explaination is correct but to apply the voltage divider metod you must first asume that the voltage between c and d is 0V, and not the other way around
Is it possible to use this procedure, when for example Rx is a RTD (Resistance Temperature Detector) or a Potentiometer ?
Can you make a DIY 230V UPS with an integrated charger and battery level indicator for a lead-acid battery?
How to know what size of resistors to use?
Nice bro , keep it up
In my school we did it with a two resistor voltage divider. Why do i have to use a Wheatstone bridge compared to a simple two resistor voltage divider?
Hi, Which software do you use for presenting the schematics and other graphical explanation in 2D?
Very smart explanation!
Hello ! I liked your method of explaining you do a very good job but i have a small question how a voltage divider will existe if we have spplited current i think if we you ohm lows would be more satisfying and thanks you
thank you for explaining 5:22, was wondering that since the start of the video
High precision Wheatstone bridge are capable to measure the resistance between ?
Really great video! Thanks very much!
Excellent explanation ... Vielen danke 🍮🧁🌷
Bro make 8 channel relay control using ethernet shield arduino
Perfect explanation. Thanks!
Nice and Clear!!!
How to select the resistor values?
thank you so much!this is the best video on wheatstone bridge
you are awesome ! ❤❤❤
very well explained
Secret of ur knowledge?
impressive explanation. thank you
Useful video 👍
Thank you. Finally an understandable explanation.
Simple and easy to understand, thank you
This is what I needed thank you very much
Divisor de tensao
what if the sensor changes voltage or amperage vs. resistance ?
Thanks for explanations. Very well explained. Now I remembered what this bridge does. Keep up the good work. Salutare!
good
Thanks man ... You explained it like a pro
Thank you sir 🔥
Nice explanation
Best explanation
THANKS YOUU!!!
Brooo Thanks !
Amazing!!!
that was a clear explanation. thank you
Thank you!
Very nice and great explanation.
Thank you
YOU ARE A LIFE SAVER. THANK YOU
Great vid
crystal clear explanation
perfect
Fantastic explanation 🙏🙏🙏
Great explanation 👌🏽
Thanks, good video!
Great job! Thank you!
Very helpfull.👍👍👍👍👍
thank you for all presentations
awesome explation